Class 11 chemistry MCQs with answers are provided here for chapter 4 Chemical Bonding and Molecular Structure. These MCQs are based on CBSE board curriculum and correspond to the most recent Class 11 chemistry syllabus. By practicing these Class 11 Multiple choice questions, students will be able to quickly review all of the ideas covered in the chapter and prepare for the Class 11 Annual examinations as well as other entrance exams such as NEET and JEE.
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Class 12 Chemical Bonding and Molecular Structure MCQs
1. Which one of them is the weakest?
(a) Ionic bond
(b) Covalent bond
(c) Metallic Bond
(d) van der Waals force
Ans: (d)
Solution: Among them van der Waals force is the weakest force.
2. The bond angle around atom which uses sp2 hybridization is ———–
(a) 1200
(b) 1800
(c) 1070
(d) 1090. 28’
Ans: (a)
Solution: The bond angle around an atom which uses sp2 hybridization is 1200.
3. In the resonating structures of benzene, the number of sigma and pi bonds are
(a) 3π and 12σ
(b) 3σ and 3π
(c) 6σ and 6π
(d) 12σ and 12π
Ans: (a)
Solution: In Benzene (C6H6) ring contain 3 alternative double bond = 3π bonds and (six C-C sigma bond + six C-H sigma bond) = 12 σ bonds
4. Which of the following substances has a dipole moment more than zero?
(a) Water
(b) Methane
(c) Carbon dioxide
(d) Nitrogen
Ans: (a)
Solutions: The dipole moment (μ) of H2O = 1.84 D
5. The ion which is iso-electronic with CO is —————
(a) CN–
(b) O2–
(c) N2+
(d) O2+
Ans: (a)
Solution : Both CO (6 + 8=14) and CN– (6 + 7+1= 14) have the same electrons. so they are iso-electronic with each other.
6. The correct bond order in the following species is —————.
(a) O2+ < O2– < O22+
(b) O2– < O2+ < O22+
(c) O22+ < O2+ < O2–
(d) O22+ < O2– < O2+
Ans: (b)
Solution: The correct one is O2– < O2+ < O22+ , bond order is 1.5 < 2.5 < 3.0 respectively.
7. Which of the following molecules have trigonal planar geometry?
(a) BF3
(b) NH3
(c) PCl3
(d) IF3
Ans: (a)
Solution: BF3 has trigonal planar geometry. The hybridization of BF3 is sp2 hybridization.
8. During change of O2 to O22- ion, the electron adds on which of the following orbitals?
(a) σ* orbital
(b) π orbital
(c) σ orbital
(d) π* orbital
Ans: (d)
Solution: The incoming electrons added to π* orbital in the change of O2 to O22- ion.
9. In which of the following pairs, the two molecules have identical bond orders:
(a) N2 , O22+
(b) N2 , O2–
(c) N2– , O2
(d) O22- , N2
Ans: (a)
Solution: Both N2 and O22+ have bond order equal to 3.0.
10. Ionic bonds will be formed more easily between elements with comparatively:
(a) low ionization enthalpy and high electron affinity
(b) high ionization enthalpy and high electron affinity
(c) low ionization enthalpy and low electron affinity
(d) high ionization enthalpy and low electron affinity
Ans: (a)
Solution: Ionic bonds will be formed more easily between elements with low ionization enthalpy and high electron affinity.
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