Markovnikov's Rule

Markovnikov’s Rule, also known as Markownikoff’s rule, can be used to describe the outcome of some chemical addition reactions. The Russain chemist Vladimir Vasilyevich Markovnikov first formulated this rule in 1865.

What is Markovnikov’s Rule?

When a protic acid (HX) is added to an asymmetric alkene, the acidic hydrogen attaches itself to the carbon having a greater number of hydrogen substituents whereas the halide group attaches itself to the carbon atom which has a greater number of alkyl substituents.

To simplify the rule, it can also be stated as – “Hydrogen is added to the carbon with the most hydrogens and the halide is added to the carbon with least hydrogens”.
An example of a reaction that observes Markovnikov’s rule is the addition of hydrobromic acid (HBr) to propene, which is shown below.

Markovnikov’s rule

Markovnikov’s rule

It can be observed from the reaction illustrated above that the majority of the product formed obeys Markovnikov’s rule, whereas the minority of the product does not.
Let us consider the addition reaction wherein an alkene reacts with water to give rise to an alcohol. This reaction proceeds via the formation of a carbocation. It is observed in this reaction that the hydroxyl group attaches itself to the carbon with more carbon-carbon bonds whereas the hydrogen atom attaches itself to the other carbon in the double bond which has more carbon-hydrogen bonds.

What is the Mechanism Behind Markovnikov’s Rule?

To understand this mechanism, let us consider the same example illustrated earlier, i.e. the addition reaction of hydrobromic acid with propene. The Mechanism of Markovnikov’s rule can be broken down into the following two steps.

Step 1

Markovnikov Rule Mechanism Step 1

The Mechanism behind Markovnikov’s Rule (Step 1)

The alkene is protonated and it gives rise to the more stable carbocation as shown below.

From the illustration shown above, we can see that there are two types of carbocations that can be formed from the protonation of the alkene, one is a primary carbocation and the other is a secondary carbocation. However, the secondary carbocation is far more stable and therefore, its formation is preferred over the formation of a primary carbocation.

Step 2

Markovnikov Rule Mechanism Step 2

The Mechanism behind Markovnikov’s Rule (Step 2)

The halide ion nucleophile now attacks the carbocation. This reaction yields the alkyl halide. Since the formation of the secondary carbocation is preferred, the major product of this reaction would be 2-bromopropane as illustrated below.

It is important to note that the Markovnikov’s rule was developed specifically for its application in the addition reaction of hydrogen halides to alkenes. The opposite of  ‘Markovnikov’ addition reactions can be described as Anti-Markovnikov based on the regioselectivity of the reaction.

Examples of Markovnikov and Anti-Marknovnikov Addition Reactions

The Hydration of Alkenes

When alkenes are treated with certain aqueous acids (usually sulfuric acid), the resulting electrophilic addition reaction yields an alcohol as the product. The regioselectivity of such reactions can be predicted by Markownikoff’s rule. Therefore, these reactions can be classified as Markovnikov reactions. In the hydration of alkenes, the H+ ion acts as an electrophile and attacks the alkene to generate a carbocation intermediate (the intermediate with greater stability is protonated). The subsequent nucleophilic attack on the carbocation by water molecules forms an oxonium ion, which is deprotonated to afford the required alcohol product.

The Hydroboration/Oxidation of Alkenes

When alkenes are treated with borane (BH3) in the presence of hydrogen peroxide or sodium hydroxide, an alcohol is obtained as the final product. In this electrophilic addition reaction, the boron atom acts as an electrophile. This reaction does not obey Markovnikov’s rule and can, therefore, be classified as an anti-Markovnikov reaction

Frequently Asked Questions – FAQs

What is the Reasoning behind Markovnikov’s Rule?

The protonation of the alkene by the protic acid results in the formation of a carbocation. The most stable carbocation is the one in which the positive charge is held by the carbon with the greatest number of alkyl substituents. Therefore, the majority of the product features the addition of the halide to the carbon having fewer hydrogen substituents.

Does the Following Reaction obey Markovnikov’s Rule?

Markovnikov's Rule Exercise 1

Since the bromine atom attaches itself to the carbon having a greater number of hydrogen atoms (or fewer alkyl substituents), the reaction illustrated above does not obey Markovnikov’s rule.

If the Following Reaction obeys Markovnikov’s Rule, What would be the Major Product?

Markovnikov's Rule Exercise 2

The product in which bromine is attached to the secondary carbon would be the major product. The CH3CH=CHBr product would be the minor product as per Markovnikov’s Rule.

What does Markovnikov’s rule predict?

Markovnikov’s rule predicts the regiochemistry of the reaction when a protic acid (usually denoted by HX) is added to an unsymmetrically substituted alkene. It predicts that the halide part of the protic acid preferentially attaches itself to highly substituted carbon atoms whereas the hydrogen component of the protic acid preferentially attaches itself to the least substituted carbon atom (the carbon atom holding the most carbon-hydrogen bonds). 

Which reactions do not obey Markovnikov’s rule?

Free radical addition reactions do not obey Markovnikov’s rule since the regioselectivity of the mechanisms of these reactions are not predicted by Markovnikov’s rule. These reactions are generally referred to as Anti-Markovnikov addition reactions.

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  1. Thanks…

  2. i am satisfied with this explanation,thank you.

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