Derivation of Escape Velocity

Derivation of escape velocity is a very common concept in the kinematics topic of physics and often questions related to it are included in the school exams. The escape velocity derivation is also important to understand the in-depth concepts better and have a thorough understanding of the related concepts.

Derivation of Escape Velocity

With the help of the escape velocity formula, it is possible to calculate the minimum velocity that an object requires to overcome a particular planet’s or object’s gravitational pull. Here, the derivation of escape velocity is given in a very simple and easy to understand way that can help students learn this concept more effectively.

Derivation of Escape Velocity:

Before checking the escape velocity derivation, it is important to know what escape velocity is and what are its related concepts. Check out Escape Velocity of Earth for a detailed understanding of the minimum velocity required to overcome the earth’s gravitational pull.

Escape Velocity Formula:

\(\begin{array}{l}v_{e}=\sqrt{2gR}\end{array} \)


Assume a perfect sphere-shaped planet of radius R and mass M. Now, if a body of mass m is projected from a point A on the surface of the planet. An image is given below for better representation:

Derivation of Escape Velocity

In the diagram, a line from the center of the planet i.e. O is drawn till A (OA) and extended further away from the surface. In that extended line, two more points are taken as P and Q at a distance of x and dx, respectively from the center O.

Now, let the minimum velocity required from the body to escape the planet b

\(\begin{array}{l}v_{e}\end{array} \)

Thus, Kinetic Energy will be

Derivation of Escape Velocity

At point P, the body will be at a distance x from the planet’s center and the force of gravity between the object and the planet will be:

Derivation of Escape Velocity

To take the body from P to Q i.e. against the gravitational attraction, the work done will be->

Derivation of Escape Velocity

Now, the work done against the gravitational attraction to take the body from the planet’s surface to infinity can be easily calculated by integrating the equation for work done within the limits x=R to x=∞.


Derivation of Escape Velocity

By integrating it further, the following is obtained:

Derivation of Escape Velocity

Thus, the work done will be:

Derivation of Escape Velocity

Now, to escape from the surface of the planet, the kinetic energy of the body has to be equal to the work done against the gravity going from the surface to infinity. So,

K.E. = W

Putting the value for K.E. and Work, the following equation is obtained:

Derivation of Escape Velocity

From this equation, the escape velocity can be easily formulated which is:

Derivation of Escape Velocity

Putting the value of g = GM, the value of escape velocity becomes:

Derivation of Escape Velocity

From this equation, it can be said that the escape velocity depends on the radius of the planet and the mass of the planet only and not on the mass of the body.

Escape Velocity of Earth:

From the above equation, the escape velocity for any planet can be easily calculated if the mass and radius of that planet are given. For earth, the values of g and R are:

g = 9.8 m

R = 63,781,00 m

So, the escape velocity will be:

\(\begin{array}{l}v_{e}=\sqrt{2\times 9.8\times 63,781,00}\end{array} \)

Escape Velocity of Earth= 11.2 km/s.

This was the derivation of the escape velocity of earth or any other planet. This escape velocity derivation is very crucial as questions related to this topic are common in the physics exams. To learn more similar concepts, check out the related articles below.

Related Articles

For more important derivations of physics formulas, stay tuned with BYJU’S.

Frequently Asked Questions – FAQs

What is gravity?

Gravity is an attractive force by which planets or bodies draw other bodies towards their centre. The gravity force keeps planets in orbit around their parent stars.

What is escape velocity?

Escape velocity is the velocity at which a body travels to break free from either the planet’s or the Moon’s gravity.

What is the escape velocity of the Earth?

The escape velocity of the Earth is equal to 11.2 km/s (40,270 kmph, or 11,186 m/s).

What is the escape velocity of the Sun?

The escape velocity of the Sun is equal to 618 km/s.

What is the escape velocity of the Moon?

The escape velocity of the Moon is equal to 2.38 km/s.

What is the escape velocity of Jupiter?

The escape velocity of Jupiter is equal to 59.5 km/s.

Test your knowledge on Escape velocity derivation


  1. Thanks so much

  2. Jigme Choden Ghalley

    Thankyou so much byjus experts. You cleared my doubts🌹

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