Aim
To find the weight of a given body using the parallelogram law of vectors.
Materials Required
- Gravesand’s apparatus which is a parallelogram law of forces apparatus
- Plumb line
- Two hangers with slotted weights
- A body whose weight is to be determined
- Thin strong thread
- White drawing paper
- Drawing pins
- Mirror strip
- Sharp pencil
- Half-meter scale
- Set squares
- Protractor
Theory
If an unknown weight body S is suspended from the middle of the hanger, and P and Q are the two balance weights from the other two ends of the hanger, then the unknown weight is calculated using the below equation:
\(\begin{array}{l}S=\sqrt{P^{2}+Q^{2}+2PQcos\theta }\end{array} \) |
Where,
- S is the unknown weight
- P and Q are the balance weights
Diagram
Procedure
- Set up the Gravesand’s apparatus with its board vertical and with the help of a plumb line.
- Oil the pulleys P1 and P2 if they are not friction-less.
- With the help of drawing pins, fix the white sheet on the board.
- Let O be the knot made from three-piece of strong thread.
- Let P and Q be the weights that are tied at both the ends of the hanger and S be the given body tied to the third end.
- Let the third weight S be vertically in the middle of the board and weights P and Q are passed over the pulley.
- Junction O should be maintained at equilibrium by adjusting weights P and Q.
- All the three weights P, Q and S act as three forces, \(\begin{array}{l}\overrightarrow{P}, \,\, \overrightarrow{Q}\,\, \textup{and} \,\, \overrightarrow{S}.\end{array} \)
- All three weights should hang freely without touching the board or table.
- With a sharp pencil, mark the position of junction O.
- Disturb the weights P and Q and leave them free.
- The position of junction O will be closer to the earlier position.
- Let P1 and P2 be the position of P, Q1 and Q2 be the position of Q and S1 and S2 be the position of S which are taken down with the help of the mirror.
- Remove the paper from the board.
- Using half-meter scale draw lines through P1 and P2, Q1 and Q2 and S1 and S2 represent P, Q, and S respectively. All these lines should meet at point O.
- Taking a scale, 1 cm = 50 g, OA = 3 cm and OB = 3 cm to represent P =150g and Q = 150g.
- R is represented by completing the parallelogram OACB and by joining OC with the help of set squares.
- When OC is measured, it comes to 3.9 cm.
- P and Q can be changed for different sets.
- By using spring balance, find the weight of the wooden box.
Observation
Least count of spring balance = …… g
Zero error of spring balance = …….. g
Weight of unknown body by spring balance = …….g
Scale used: Let 1 cm = 50 g
Sl. no | Forces | Sides | Resultant force R (g wt) | Unknown weight S (g wt) | Weight by spring balance (g wt) | Error (g wt) | |||
P (g wt) | Q (g wt) | OA (cm) | OB (cm) | OC (cm) | |||||
1. | 150 | 150 | 3 | 3 | 3.9 | 195 | 195 | 200 | 5 |
2. | |||||||||
3. |
Calculations
OC = 3.9 cm, R = 50 × 3.9 = 195 g
Unknown weight, S = 195g
Mean unknown weight,
Weight by spring balance = 200 g
Difference = 5 g
Result
The unknown weight of given body = 195 g
The error is within limits of experimental error.
Precautions
- The board should be stable and placed verticle.
- There shouldn’t be any friction in the pulleys.
- The board or the table should not be in touch with the hangers.
- The middle of the paper should have junction O.
- When the weights are at rest, the points should be marked.
- A sharp pencil should be used to mark the points.
- To show the direction of forces, arrows should be marked.
- To make a fairly big parallelogram, a proper scale should be taken.
Sources Of Error
- There might be friction in the pulleys.
- Weights might not be accurate.
- Points marked may be correct.
- Weight measured by spring balance may not be accurate.
Read More: Addition of Vectors
Viva Questions
Q1. Define scalar quantity.
Ans: It is defined as the physical quantity which has only magnitude like length, mass, etc.
Q2. Define vector quantity.
Ans: It is defined as the physical quantity which has magnitude and direction like force, velocity, etc.
Q3. Define addition of vector.
Ans: The addition of vector is defined as the operation of adding two or more vectors together into a vector sum.
Q4. What is resolution of vectors?
Ans: Resolution of the vector is defined as the breaking of a single vector into its components.
Q5. Why is addition of vector different from the addition of scalars?
Ans: Addition of vector has direction and magnitude whereas the addition of scalar has only magnitude. Therefore, the addition of vector is different from the addition of scalar.
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