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Markovnikov Rule Questions

Markovnikov’s Rule, sometimes known as Markownikoff’s Rule, can be used to characterise the outcome of several chemical addition reactions in organic chemistry. This rule was proposed by Russian scientist Vladimir Vasilyevich Markovnikov in 1865. The rule can be used to predict the molecular structures of the products of addition reactions.

Definition: In addition reactions to unsymmetrical alkenes, the electron-rich component of the reagent adds to the carbon atom with fewer hydrogen atoms linked to it, whereas the electron-deficient component adds to the carbon atom with more hydrogen atoms tied to it.

Markovnikov Rule Chemistry Questions with Solutions

Q-1: With the help of an appropriate example, write the steps of the Markovnikov rule mechanism.


Step-1 Formation of carbocation

H+, an electrophile produced by hydrogen bromide, attacks the double bond of propene to form a carbocation, as shown below:

Markovnikov mechanism

Because the secondary carbocation (b) is more stable than the primary carbocation (a), it takes precedence as it forms faster.

Step-2 Attack of Nu

The carbocation (b) is attacked by Br ion, resulting in the following product:

Markovnikov mechanism

Q-2: State a rule that is the opposite of the Markovnikov rule.

Answer: When a polar molecule is introduced to an unsymmetrical alkene in the presence of organic peroxide, the negative part of the molecule is attached to the carbon atom that is coupled to more Hydrogen atoms than the other unsaturated carbon atom. This reaction is known as the peroxide or Kharash effect, or the anti-Markovnikov rule addition reaction.

Q-3: The Markovnikov rule is not followed in

  1. Reaction of alkenes with sulphuric acid
  2. Reaction of alkene with water
  3. Hydroboration-oxidation reaction
  4. Oxymercuration-Demercuration Reaction

Answer: c) Hydroboration-oxidation reaction

Explanation: The ultimate product of treating alkenes with borane (BH3) in the presence of hydrogen peroxide or sodium hydroxide is an alcohol. The boron atom acts as an electrophile in this electrophilic addition process.The boron atom is mostly placed on the carbon which is less substituted. Therefore, it can be classified as an anti-Markovnikov reaction.

Q-4: Will the Markovnikov rule apply when adding HBr to a symmetrical alkene?

Answer: No

Explanation: Addition reactions of HBr to symmetrical alkenes (similar groups attached to double bond) take place by electrophilic addition mechanism.

For example: Addition of HBr to ethene takes place as:

CH2=CH2 + HBr → CH3-CH2-Br

Because the system is symmetrical, there is no olefin carbon that can be classified as having fewer or more H-atoms.

Q-5: Write IUPAC name of the product obtained by addition reactions of HBr to pent-1-ene in the absence of peroxide.

Answer: The reaction follows the Markovnikov Rule in the absence of peroxide.

CH3-CH2-CH2-CH=CH2 + HBr

\(\begin{array}{l}\overset{no\ peroxide}{\rightarrow}\end{array} \)

The IUPAC name of the product is 2-Bromopentane.

Q-6: Free radical addition reaction obey

  1. Markovnikov rule
  2. Kharash effect
  3. Hoffmann rule
  4. Saytzeff rule

Answer: b) Kharash effect

Q-7: When a hydrogen halide(HX) is introduced to an unsymmetrical alkene, an intermediate is

  1. Free Radical
  2. Carbocation
  3. Carbanion
  4. Nitrene

Answer: b) Carbocation

Explanation: The production of carbocation occurs when HX is added to an unsymmetrical alkene according to the Markovnikov rule. The product is generated after the nucleophile attacks the created carbocation.

Q-8: When two acid (H-X) equivalents are added to an aliphatic alkyne, what product is produced?(X= Cl, Br, I)

  1. Alkenyl halide
  2. Geminal dihalide
  3. Alkyl Halide
  4. Aryl halide

Answer: b) Geminal dihalide


One equivalent of an acid gives the alkenyl halide (vinyl halide)

Two equivalent of an acid gives geminal dihalide.

The reaction illustration is shown below:

Markovnikov addition of acid to alkynes

Q-9: What is the hybridisation of the following carbocation?


  1. sp2
  2. sp3
  3. sp
  4. p

Answer: a) sp2

Explanation: Because the positive-charged carbon forms three sigma bonds, this is an example of sp2 hybridisation.

Q-10: Sort the following chemicals in decreasing order of HBr reactivity: isobutene, ethene, and propene

Answer: Isobutene>propene>ethene


The stability of the carbocation produced determines the reactivity of alkenes towards HBr.

Tertiary carbocation is more stable than secondary and primary carbocation.

Isobutene results in the formation of 3o carbocation, propene in 2o carbocation and ethene in 1o carbocation.

As a result, isobutene is the most reactive towards HBr, whereas ethene is the least reactive.

Q-11: Reaction which will give fastest carbocation

Reactions involving carbocation formation

Answer: b)


In a) carbocation is formed by removal of chlorine and is resonance stabilised.

In b) the carbocation formed is mesomerically stabilised (lone pair donation of oxygen).

In c), proton released from HCl attacks the double bond and forms carbocation which is again resonance stabilised.

In d) carbocation formed after removal of chlorine forms an antiaromatic system, hence least stable.

The reaction that gives the most stable carbocation will proceed fast. Any carbocation which is stabilised by +M effect( back bonding) is the most stable.

Thus, reaction b) will give the fastest carbocation.

Q-12: What will be the primary product if the following reaction follows the Markovnikov rule?

Markovnikov Reaction

Answer: a)

Explanation: According to Markovnikov, the acid’s negative component (Br) adds to the more substituted olefinic carbon. As a result, product (a) is a major product.

Q-13: Does the reaction follow Markovnikov rule?

Anti Markovnikov Equation

Answer: No

Explanation: The halide component is added to the carbon in the product, which is less substituted. It is an anti markovnikov product.

Q-14: How do you explain the product like the one shown in the below reaction?

Markovnikov Rule

Answer: HCl will simply join its hydrogen to the olefin carbon with the greatest hydrogens and chlorine to the carbon with less hydrogen, according to markovnikov rule. But here, chlorine is added to the carbon other than olefinic.This is because of the rearrangement of the carbocation formed.

The methyl shift takes place which results in a more stable tertiary carbocation.

Q-15: What is the order of reactivity of hydrogen halides with alkenes?

Answer: Due to a decrease in bond (HX) dissociation energy, the stability of hydrogen halides diminishes along the group. The reactivity order is


Practise Questions on Markovnikov Rule

Q1: How does Markovnikov’s rule show that electrophilic addition reactions to alkenes are regioselective?

Q-2: Markovnikov reaction is a

  1. Electrophilic substitution reaction
  2. Nucleophilic substitution reaction
  3. Electrophilic addition reaction
  4. SN1 reaction

Q-3: In the hydration of alkene, the rate determining step is

  1. Protonation of alkene
  2. Nucleophilic attack by water molecule
  3. Deprotonation to alcohol
  4. All of the above

Q-4: List the factors that influence carbocation stability.

Q-5: Addition of HCl to propyne leads to

  1. Vinyl carbocation
  2. Allyl carbocation
  3. Both of the above
  4. Sec-vinyl carbocation

Click the PDF to check the answers for Practice Questions.
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