What is conservation of angular momentum?
It is the rotational analogue of linear momentum, it is denoted by l, and angular momentum of a particle in rotational motion is defined as:
\(l\) = \(r~Ã—~p\)

This is a cross product of r i.e. the radius of the circle formed by the body in rotational motion, and p i.e. the linear momentum of the body, the magnitude of a cross product of two vectors is always the product of their magnitude multiplied with the sine of the angle between them, therefore in the case of angular momentum the magnitude is given by,
\(l\) = \(r~p~sinÎ¸\)

Torque and Angular MomentumÂ Relationship
Relationship between torque and angular momentum can found as follows,
\(\overrightarrow{l}\) = \(\overrightarrow{r}~Ã—~\overrightarrow{p}\)
Differentiating LHS and RHS,
\(\frac{d\overrightarrow{l}}{dt}\) = \(\frac{d}{dt}(\overrightarrow{r}~Ã—~\overrightarrow{p})\)
By the property of differentiation on cross products the above expression can be written as follows,
\(\frac{d\overrightarrow{l}}{dt}\) = \(\frac{dr}{dt}~\times~\overrightarrow{p}~+~r~\times~\frac{d\overrightarrow{p}}{dt}\)
\(\frac{d\overrightarrow{r}}{dt}\) is change in displacement with time, therefore it is linear velocity \(\overrightarrow{v}\)
\(\frac{d\overrightarrow{l}}{dt}\) = \(\overrightarrow{v}~\times~\overrightarrow{p}+~r~\times~\frac{d\overrightarrow{p}}{dt}\)
\(\overrightarrow{p}\) is linear momentum i.e. mass times velocity,
\(\frac{d\overrightarrow{l}}{dt}\) = \(\overrightarrow{v}~\times~m\overrightarrow{v}~+~r~\times~\frac{d\overrightarrow{p}}{dt}\)
Now notice the first term, there is \(\overrightarrow{v}~\times~\overrightarrow{v}\) magnitude of cross product is given by
\(\overrightarrow{v}~\times~\overrightarrow{v}sinÎ¸\) where the angle is 0 hence the whole term becomes 0.
From newtonâ€™s 2nd law we know that \(\frac{d\overrightarrow{p}}{dt}\) is force,
\(\frac{d\overrightarrow{l}}{dt}\) = \(\overrightarrow{r}~\times~\overrightarrow{F}\)
We know that \(r~\times~f\) is torque, hence
\(\frac{d\overrightarrow{l}}{dt}\) = \(\overrightarrow{Ï„}\),torque
So rate of change of angular momentum is torque.
Conservation ofÂ Angular Momentum – Calculation
Angular momentum of a system is conserved as long as there is no net external torque acting on the system, the earth has been rotating on its axis form the time the solar system was formed due to the law of conservation of angular momentum,
There are two ways to calculate the angular momentum of any object, if it is a point object in a rotation, then our angular momentum is equal to the radius times the linear momentum of the object,
\(\overrightarrow{l}\) = \(\overrightarrow{r}~\times~\overrightarrow{p}\)
If we have an extended object, like our earth for example, the angular momentum is given by moment of inertia i.e. how much mass is in motions in the object and how far it is from the centre, times the angular velocity,
\(\overrightarrow{l}\) = \(\overrightarrow{I}~\times~\overrightarrow{\omega}\)
But in both case as long as there is no net force acting on it, the angular momentum before is equal to angular momentum after some given time, imagine rotating a ball tied to a long string, the angular momentum would be given by,
\(\overrightarrow{l}\) = \(\overrightarrow{r}~\times~\overrightarrow{p}\) = \(\overrightarrow{r}~\times~m\overrightarrow{v}\)
Now when we somehow decrease the radius of the ball by shortening the string while it is in rotation, the r will reduce, now according to the law of conservation of angular momentum L should remain the same, there is no way for mass to change, therefore \(\overrightarrow{v}\) should increase, to keep the angular momentum constant, this is the proof for conservation of angular momentum.
Conservation of Angular Momentum Applications
Law of conservation of angular momentum has many applications, including:
 Electric generators,
 Aircraft engines, etc.
To learn more about the conservation of angular momentum and other related topics with the help of interactive video lessons, visit BYJU’S.
Q1) What is the conservation of angular momentum?
Answer:
For a system with no external torque, the angular momentum is constant.
Q2) The angular momentum of a particle in rotational motion is defined by the equation
 l = r Ã— p
 l = r^{2 }Ã— p
 l = r/p
 l = r^{2}/p^{2}
Answer: a. l = r Ã— p
The angular momentum of a particle in rotational motion is defined by the equation l = r Ã— p.
Q3) List a few applications of conservation of angular momentum
Answer:
A few application of angular momentum are:
 Aircraft engine
 Electric generators
Q4) Orbital angular momentum is associated with the motion of the body along the _____.
 Circular path
 Central point
 Pivot axis
 Straight path
Answer: a. circular path
Orbital angular momentum is associated with the motion of the body along the circular path
Q5) If a particle moves in a way it is said to change its angular position relative to its reference axis, it is said to have angular momentum.
 True
 False
Answer: a. True
If a particle moves in a way that its angular position changes relative to its reference axis, is said to have angular momentum.
Q6) The angular momentum of a moving body is represented by the symbol
 L
 A
 M
 Z
Answer: a. L
The angular momentum of a moving body is represented by the symbol L.
Q7) The SI unit of angular momentum is _____.
 Js^{â€“1}
 J
 Js
 W
Answer: c. Js
The SI unit of angular momentum is Js.