SSC CGL Online Mock Test Free – The SSC CGL mock tests provided by BYJU’S will help candidates practice and outshine in the examination. It is imperative for candidates to give a finishing touch to their preparation with the SSC CGL Online test series since the competition for the Combined Graduate Level exam is really tough.
The Staff Selection Commission conducts the SSC CGL exam. The exam is conducted for various Group B and Group C posts for various departments of the Central Government.
For more details on the SSC Preparation for other exams, refer to the linked article.
Since the SSC CGL Tier I 2020 exam which was scheduled to conduct from May 29th to June 7th, 2021 is postponed due to a surge in COVID-19 cases, applicants of the examination have got extra time at hand to give an edge to their exam preparation and what other can be more fruitful than practicing in the exam-like environment provided in Free SSC CGL Mock Test Online!
Candidates can get more details related to SSC CGL exam in the linked article.
The SSC CGL exam is taken up by lakhs of candidates each year and the free SSC CGL mock tests will help candidates prepare for the actual exam. Each mock test consists of 25 questions from the three main sections of the SSC exams: reasoning ability, quantitative aptitude and English language.
SSC CGL Mock Test 1:-Download PDF Here
SSC CGL Mock Test 2:-Download PDF Here
SSC CGL Mock Test 3:-Download PDF Here
For comprehensive SSC CGL preparation refer to the links for assistance- |
These SSC Exams are a great opportunity for candidates wanting to work in various departments, offices, organizations under the Government of India.
SSC CGL Exam Dates
The SSC CGL exam notification for the year 2020-21 is released on December 29th, 2020. The recruitment for the SSC CGL exam for the year 2019 was released on 22nd October 2019. The important dates for the SSC CGL exam are as follows:
The table below gives a complete idea about the SSC CGL 2020 Exam:
Name of the Recruitment Exam | SSC CGL Exam 2020-21 |
Recruiting board | Staff Selection Commission |
SSC CGL Notification | Released on 29th December 2020 |
SSC CGL Vacancies | to be announced |
Online Application Submission | December 29th, 2020 to January 31st 2021 |
SSC CGL Admit Card | To be notified |
Tier I exam | May 29th to June 7th 2021 (Postponed) |
Tier-II exam | To be notified |
Tier III exam | To be notified |
Tier IV exam | To be notified |
Candidates willing to appear for the next recruitment of SSC CGL exam can check the SSC CGL exam analysis for a better understanding of the scope and difficulty level of the exam.
Below Mentioned table gives the important dates for SSC CGL 2019 exam.
SSC CGL Exam | |
SSC CGL Tier I | March 3, 2020, to March 9, 2020 |
SSC CGL Tier-II | November 2nd to November 5th 2020 |
SSC CGL Tier III | November 22nd 2020 |
SSC CGL Exam Related links:
SSC Exam Date | SSC Admit Card | SSC Recruitment |
SSC Exam Pattern | SSC Results | SSC Preparation |
SSC Online | SSC Eligibility | Static GK |
SSC CGL Exam Pattern
The SSC CGL exam pattern is set by the Staff Selection Commission for the different posts. The exam pattern for SSC CGL exam is given below in brief:
SSC CGL Exam Pattern | |
SSC CGL Tier I | General Intelligence & Reasoning
General Awareness Quantitative Aptitude English Language |
SSC CGL Tier-II | Quantitative Aptitude
English Language Statistics General Studies (Finance & Economics) |
SSC CGL Tier III | English/ Hindi Descriptive Paper |
Candidates must regularly give SSC CGL mock tests to analyse their preparation level. It gives candidates a chance to practice and revise the syllabus based on the actual exam pattern.
Read, How to prepare for SSC CGL Exam in 30 Days?
SSC CGL Free Mock Tests
The free SSC CGL mock test pattern will be the same as the one given below. Candidates can refer to the free SSC CGL mock test given below.
SSC CGL Mock Test 1
Q. (1) In a row of girls, position of Shreya from the left side of the row is 11th and Aishwarya from the right side of the row is 17th. If Reema is sitting just in the middle of Shreya and Aishwarya and her position from Shreya is 5th, then how many girls are sitting in the row?
- 35
- 37
- 26
- 29
- 31
Answer: 2
Solution: Position of Reema from left = Position of Shreya from left + Position of Reema from Shreya = 11 + 5 = 16th
Position of Reema from right = Position of Aishwarya from right + Position of Shreya from Aishwarya = 17 + 5 = 22nd
Total number of girls = (Sum of the positions of Reema from both sides) – 1
= (16 + 22) – 1
= 37
Directions Q. (2-3): Read the following information carefully and answer the questions that follow:
- ‘A * B’ means ‘A is the mother of B’
- ‘A x B’ means ‘A is the father of B’
- ‘A + B’ means ‘A is the sister of B’
- ‘A – B’ means ‘A is the brother of B’
- ‘A > B’ means ‘A is the son of B’
- ‘A < B’ means ‘A is the daughter of B’
Q. (2) In the expression ‘P x Q + Y > Z’, how is Z related to P?
- Daughter-in-law
- Daughter
- Wife
- Sister
- Brother
Answer: 3
Solution: P x Q → P is the father of Q
Q + Y → Q is the sister of Y
Y > Z → Y is the son of Z
Hence, Z is the wife of P.
Q. (3) In the expression ‘ X + Y > M – N’, how is X related to N?
- Son
- Daughter
- Nephew
- Niece
- Mother
Answer: 4
Solution: X + Y → X is the sister of Y
Y > M → Y is the son of M
M – N → M is the brother of N
Therefore, X is the niece of N.
Directions Q. (4-5): In these questions, the relationship between different elements is shown in the statements. The statements are followed by two conclusions. Mark your answer as:
- If only conclusion I is true
- If only conclusion II is true
- If either conclusion I or II is true
- If neither conclusion I nor II is true
- If both the conclusions I and II are true.
Q. (4) Statement: A > B ≥ C; D < B < E
Conclusions:
- A > D
- C < E
Answer: 5
Solution: From the given statement, A > B ≥ C; D < B < E , we can conclude:
- A > B, D < B. Therefore, A > D.
- B ≥ C, B < E. Therefore, C < E.
Q. (5) Statement: P < Q = O ≥ N > M
Conclusions:
- Q > M
- P < N
Answer: 5
Solution: From the given statement, P < Q = O ≥ N > M, we can conclude:
- Q = O, O > M, therefore, Q > M
- P < N
Directions Q. (6-7): Read the following statement carefully and answer the question given below.
- Point Q is 6 metres towards the North of point P.
- Point T is 10 metres towards the East of point Q.
- Point R is 7 metres towards the East of point P.
- Point S is 11 metres towards the West of point R.
Q. (6) How far should one walk from point P in order to reach point S?
- 8 metres
- 4 metres
- 7 metres
- 11 metres
- 9 metres
Answer: 2
Solution:
Q. (7) If a person walks 6 metres South from the point T and then walks after taking a right turn, which of the following points would he reach first?
- P
- Q
- R
- S
- None of the above
Answer: 3
Solution:
Directions Q. (8): In each of the following questions, a question is followed by two statements. You have to select a statement that answers the question. Mark your answer as:
- If the data in statement I alone is sufficient to answer the question while the data in statement II alone is not sufficient to answer the question.
- If the data in statement II alone are sufficient to answer the question while the data in statement I alone is not sufficient to answer the question.
- If the data either in statement I alone or in statement II alone is sufficient to answer the question.
- If the data in both statements I and II together are not sufficient to answer the question.
- If the data in both statements I and II together are necessary to answer the question.
Q. (8) Six girls A, B, C, D, E and F are sitting around a circular table with an equal distance between them. If all the girls are facing the centre, then who is sitting opposite to F?
Statements:
- F is sitting between A and D while E is sitting adjacent to B and D.
- A is adjacent to both F and C while B is sitting adjacent to C.
Answer: c (If the data either in statement I alone or in statement II alone is sufficient to answer the question)
Solution: As per the question, we get the following two arrangements:
Therefore, either from statement I or statement II alone, we can conclude that B is sitting opposite to F. Thus, the data either in statement I alone or in statement II alone are sufficient to answer the question.
Directions Q. (9-11): What will come in place of (?) in the given series?
Q. (9) 22, 23, 27, 36, 52, 77, (?)
- 92
- 96
- 113
- 117
- 120
Answer: 3
Solution: The pattern of the given series is as follows:
- 22 + 1^{2} = 23
- 23 + 2^{2} = 27
- 27 + 3^{2} = 36
- 36 + 4^{2} = 52
- 52 + 5^{2} = 77
- 77 + 6^{2} = 113
Q. (10) 5, 30, 185, 1300, (?), 93650
- 10200
- 10405
- 5450
- 7800
- 7650
Answer: 2
Solution: The pattern of the given series is:
- (5 x 5) + 5 = 30
- (30 x 6) + 5 = 185
- (185 x 7) + 5 = 1300
- (1300 x 8) + 5 = 10405
- (10405 x 9) + 5 = 93650
Q. (11) 330, 547, 673, 738, 766, (?)
- 775
- 873
- 947
- 830
- 780
Answer: 1
Solution: The pattern of the given series is:
- 330 + 6^{3} + 1 = 547
- 547 + 5^{3} + 1 = 673
- 673 + 4^{3} + 1 = 738
- 738 + 3^{3} + 1 = 766
- 766 + 2^{3} + 1 = 775
Directions Q. (12-15): The table given below shows the ratio between literate and illiterate persons and the population of seven villages of a district. Study the table and select the most appropriate answers.
Villages | Ratio (literate: illiterate) | Population |
A | 9: 2 | 2354 |
B | 4: 1 | 2540 |
C | 7: 2 | 2709 |
D | 13: 4 | 5100 |
E | 5 : 3 | 3248 |
F | 5: 2 | 4921 |
G | 13: 6 | 3990 |
Q. (12) If 42% of the illiterates of village D are males, then what is the number of illiterate women in this village?
- 600
- 696
- 750
- 830
- 800
Answer: 2
Solution: Number of illiterates in village D = (4 / 17) x 5100 = 1200
Number of illiterate females in village D = (100 – 42) % of 1200
= 58% of 1200 = (58 / 100) x 1200 = 696
Q. (13) If the ratio between males and females in the village G is 11: 8 and 60% females in village G are illiterates, then how many males of this village are illiterate?
- 200
- 252
- 320
- 380
- 170
Answer: 2
Solution: Number of literates in village G = (8 / 19) x 3990 = 1680
Number of illiterate women = 60% of 1680 = (60 / 100) x 1680 = 1008
Number of illiterates in village G = (6 / 19) x 3990 = 1260
Therefore, number of illiterate males in village G = 1260 – 1008 = 252
Q. (14) What is the difference between the number of literates in Village C and the number of illiterates in Village A?
- 1500
- 1679
- 1342
- 230
- 1670
Answer: 2
Solution:
Number of literates in Village C = 7/9 x 2709 = 2107
Number of illiterates in Village A = 2/11 x 2354 = 428
Difference between the number of literates in Village C and the number of illiterates in Village A = 2107 – 428 = 1679
Q. (15) By what percentage is the number of literates in village F is more than the number of literates in village A?
- 80%
- 60%
- 82.50%
- 88%
- 75%
Answer: 3
Solution: Number of literates in village F = (5 / 7) x 4921 = 3515
Now, the number of literates in village A = (9 / 11) x 2354 = 1926
Therefore, required percentage = [(Number of literates in village F – Number of literates in village A) / Number of literates in village A] x 100
= [(3515 – 1926) / 1926] x 100
= 82.50
Directions Q. (16 -17): In each question, two equations numbered I and II are given. You have to solve both the equations and mark answer as
- If p < q
- If p > q
- If p ≥ q
- If p ≤ q
- If p = q
Q. (16) I. p = (729)^{⅔}
II. q^{2} = 7225, q > 0
Answer: 1
Solution: Equation I ⇒ p = (9^{3})^{⅔ }
⇐ p = (9)^{3 x ⅔ }= (9)^{2 }= 81
Equation II ⇒ q^{2} = (± 85)^{2}
⇐ q = ± 85
But since q > 0, therefore, q = 85
Hence, p < q
Q. (17) I. p^{2 }– 22p + 121 = 0
II. q^{2} = (1331)^{⅔ }
Answer: 5
Solution: Equation I ⇒ p^{2} – 11p – 11p + 121 = 0
⇐ p(p – 11) – 11(p – 11) = 0
⇐ (p – 11) (p – 11) = 0
⇐ p = 11
Equation II ⇒ q^{2} = (11^{3})^{⅔ }
⇐ q^{2} = (11)^{2}
⇐ q = 11
Therefore, p = q
Directions Q. (18-20): Find the antonyms of each of the words given in bold in the following questions.
Q. (18) Churn
- Agitate
- Seethe
- Heave
- Embed
- Baffle
Answer: 4
Q. (19) Propel
- Mobilize
- Sling
- Flip
- Shy
- Repress
Answer: 5
Q. (20) Abade
- Wane
- Dim
- Slack off
- Strengthen
- Dwindle
Answer: 4
Directions Q. (21-23): Read each sentence to find out whether there is any grammatical error in it. The error, if any, will be in one part of the sentence marked as (1), (2), (3), (4) and (5). If the sentence is correct, mark option (5) as your answer.
Q. (21) Ridha picked them up one by one (1) / and admired craftsmanship (2) / and then saw that there (3) / were a note in the box as well. (4) / No error (5)
- (1)
- (2)
- (3)
- (4)
- (5)
Answer: 4
Q. (22) The Chief Minister of Assam sits (1) / third to the right of the (2) / Chief Minister of Delhi and (3) / neither of them sits at extreme ends. (4) / No error (5)
- (1)
- (2)
- (3)
- (4)
- (5)
Answer: 4
Q. (23) The poor landless (1) / and marginal farmers (2) / have no other choice (3) / than migrating. (4) / No error (5)
- (1)
- (2)
- (3)
- (4)
- (5)
Answer: 5
Directions Q. (24-25): Replace the bold word with an appropriate and synonymous word in each of the following questions.
Q. (24) On 21st September every year, World Peace Day is observed. This day was declared by the United Nations General Assembly to strengthen the ideals of peace.
- Invigorate
- Curtail
- Vigilante
- Improve
- Liberate
Answer: 1
Q. (25) Snowy fortunately became the heir to a huge palace and acquired the power to rule the kingdom.
- Devisee
- Hermit
- Ere
- Misanthrope
- Anchorite
Answer: 1
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Frequently Asked Question -SSC CGL Online Mock Tests Free
Q.1. Does BYJU’S provide solutions to SSC CGL Free Mock Tests?
Q.2. How to prepare for SSC CGL exam in 3 months?
Q.3. Can a candidate retake the SSC CGL practice papers to improve his score?
Q.4. Why should I choose BYJU’S SSC CGL mock test online free series?
Q 5. How can a candidate choose the right SSC CGL Sample Papers?
Ans. The digital resource can help candidates find out various SSC CGL free online mock tests or sample papers, but they must clarify which mock papers will be good enough to help them improve their quality of performance in the SSC CGL 2020 exam. Here the parameters to choose right SSC CGL sample papers or online test series:
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