ML Aggarwal Solutions for Class 6 Maths Chapter 2 – Whole Numbers are provided here to help students prepare for their exams and score well. This chapter deals with problems based on Whole Numbers. The concepts are explained in detail, and solutions are prepared by our expert faculty team in the best possible ways for students to understand them. Students are advised to refer to ML Aggarwal Solutions as reference materials to boost their confidence level to achieve high marks in their exams.
Chapter 2 – Whole Numbers provides solutions to questions related to each and every topic present in this chapter. Students can refer to and easily download the PDF of ML Aggarwal Class 6 Solutions for free from the link given below.
ML Aggarwal Solutions for Class 6 Maths Chapter 2 – Whole Numbers
Access answers to ML Aggarwal Solutions for Class 6 Maths Chapter 2 – Whole Numbers
1. Write the smallest whole number. Can you write the largest whole number?
Solution:
The smallest whole number is 0.
No, we cannot write the largest whole number.
2. Write the successor of each of the following numbers:
(i) 3999
(ii) 378915
(iii) 5001299
Solution:
(i) 3999
The successor of 3999 is
3999 + 1 = 4000
(ii) 378915
The successor of 378915 is
378915 + 1 = 378916
(iii) 5001299
The successor of 5001299 is
5001299 + 1 = 5001300
3. Write the predecessor of each of the following numbers:
(i) 500
(ii) 38794
(iii) 54789011
Solution:
(i) 500
Predecessor of 500 is
500 – 1 = 499
(ii) 38794
Predecessor of 38794 is
38794 – 1 = 38793
(iii) 54789011
Predecessor of 54789011 is
54789011 – 1 = 54789010
4. Write the whole number (in each of the following) whose successor is:
(i) 50795
(ii) 720300
(iii) 8300000
Solution:
(i) 50795
The required whole number = Predecessor of the given number
50795 – 1 = 50794
(ii) 720300
The required whole number = Predecessor of the given number
720300 – 1 = 720299
(iii) 8300000
The required whole number = Predecessor of the given number
8300000 – 1 = 8299999
5. Write the whole number (in each of the following) whose predecessor is:
(i) 5347
(ii) 72399
(iii) 3012999
Solution:
(i) 5347
The required whole number = Successor of the given number
5347 + 1 = 5348
(ii) 72399
The required whole number = Successor of the given number
72399 + 1 = 72400
(iii) 3012999
The required whole number = Successor of the given number
3012999 + 1 = 3013000
6. Write next three consecutive whole numbers of the following numbers:
(i) 79
(ii) 598
(iii) 35669
Solution:
(i) 79
The next three consecutive whole numbers are 80, 81, 82.
(ii) 598
The next three consecutive whole numbers are 599, 600, 601.
(iii) 35669
The next three consecutive whole numbers are 35670, 35671, 35672.
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