While paying tax on sale of goods and services, you can avail the tax you have already paid on the purchase of the above goods/service and pay only the balance amount as tax. This is called Input Tax Credit (ITC). Students will encounter problems based on this concept in this exercise. The solutions for all these problems are available in Selina Solutions for Class 10 Maths. Students willing to clear doubts on solving any problem of this exercise can download the Concise Selina Solutions for Class 10 Maths Chapter 1 GST [Goods and Services Tax] Exercise 1(B) PDF which is given below.
Selina Solutions Concise Maths Class 10 Chapter 1 GST [Goods and Services Tax] Exercise 1(B) Download PDF
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Access Selina Solutions Concise Maths Class 10 Chapter 1 GST [Goods and Services Tax] Exercise 1(B)
Exercise 1(B) Page No: 17
1. Fill in the blanks:
When the goods/services are sold for Rs. 15,000 under intra-state transaction from station A to station B and the rate of GST is 12%.
As per GST System
(a) S.P. at station A = …………………………………………………………………………………
(b) CGST = 6% of 15,000 = …………………………………………………………………………..
SGST = 6% of 15,000 = …………………………………………………………………………..
(c) C.P. at station B = …………………………………………………………………………………
(d) If profit =Â Rs. 5000
S.P. at station B = …………………………………………………………………………………
Now the same goods/services are moved under inter-state transaction from station B to station C and the rate of tax is 12%.
(e) GST = ………………………………………………………………………………………………
(f) C.P. at station C = …………………………………………………………………………………
Solution:
When the goods/services are sold for Rs. 15,000 under intra-state transaction from station A to station B and the rate of GST is 12%.
As per GST System
(a) S.P. at station A =Â Rs. 15,000
(b) CGST = 6% of 15,000 =Â Rs. 900
SGST = 6% of 15,000 =Â Rs. 900
(c) C.P. at station B =Â Rs. 15,000
(d) If profit =Â Rs. 5000
S.P. at station B = 15,000 + 5000 =Â Rs. 20,000
Now the same goods/services are moved under inter-state transaction from station B to station C and the rate of tax is 12%.
(e) GST = 12% of 20,000 =Â Rs. 2400
(f) C.P. at station C =Â Rs. 20,000
2. Goods/services are sold from Agra (U.P.) to Kanpur (U.P.) for Rs. 20,000 and then from Kanpur to Jaipur (Rajasthan). If the rate of GST is 18% and the profit made at Kanpur is Rs. 5000, find:
(i) the net GST payable by the dealer at Kanpur.
(ii) the cost of goods/services at Jaipur.
Solution:
From the question, when the product is sold from Agra to Kanpur (intra-state transaction)
For the dealer in Agra:
S. P. in Agra =Â Rs. 20,000
CGST = 9% of Rs. 20,000 = 9/ 100 x 20,000 = 1800
SGST = 9% of Rs. 20,000 = 9/100 x 20,000 = 1800
Now, when the product is sold from Kanpur to Jaipur (inter-state transaction)
For the dealer in Kanpur
Input-tax credit = 1800 + 1800 =Â Rs. 3600
C. P. =Â Rs. 20,000 and Profit =Â Rs. 5000
So, the S.P. = 20,000 + 5000 =Â Rs. 25,000
IGST = 18% of 25,000 =Â Rs. 4500
Therefore,
(i) Net GST paid by the dealer at Kanpur
= Output GST – Input GST
= 4500 – 3600
=Â Rs. 900
(ii) The cost of goods/services at Jaipur
= S. P. in Agra + IGST
= 25,000 + 18% of 25000
= 25,000 + 4500
=Â Rs. 29,500
3. Goods/services are sold from Kota (Rajasthan) to Mumbai for Rs. 20,000 and then from Mumbai to Pune. If the rate of GST is 12% and the profit made at Mumbai is Rs. 5000; find the net GST paid at Pune, if the dealer at Pune is the end-user.
Solution:
From the question, we have
For the dealer in Mumbai (inter-state transaction)
CP =Â Rs. 20,000
IGST = 12% of Rs. 20,000 = 12/100 x 20,000 = Rs. 2400
Given, Profit =Â Rs. 5000
SP =Â Rs. 25,000
Now, for the dealer in Pune (intra-state transaction)
CP =Â Rs. 25,000
CGST = 6% of 25,000 =Â Rs. 1500
SGST = 6% of 25,000 =Â Rs. 1500
Thus, the GST paid by the end user at Pune is (1500 + 1500)Rs =Â Rs. 3000
4. A is a dealer in Banaras (U.P.). he supplies goods/services worth Rs. 8000 to a dealer B in Agra (U.P.). Dealer B, in turn, supplies the same goods/services to dealer C in Patna (Bihar) at a profit of Rs. 1200. Find the input and output taxes for the dealer C under GST system; if the rate of GST is 18% and C does not sell his goods/services further.
Solution:
From the question,
For the dealer A (intra-state transaction)
SP =Â Rs. 8,000
For the dealer B (intra-state transaction)
CP =Â Rs. 8,000
CGST = 9% of 8,000 =Â Rs. 720
SGST = 9% of 8,000 =Â Rs. 720
Given profit =Â Rs. 1,200
SP =Â Rs. 9,200
For the dealer C (inter-state transaction)
CP =Â Rs. 9,200
IGST = 18 % of Rs. 9,200 = 18/100 x 9200 = Rs 1656
Input Tax =Â Rs. 1,656
As the dealer in Patna does not sell the product.
Thus, the output GST (tax on sale) =Â Rs. 0
5. A is a dealer in Meerut (U.P.). He supplies goods/services, worth Rs. 15,000 to a dealer B in Ratlam (M.P.). Dealer B, in turn, supplies the same goods/services to dealer C in Jabalpur (M.P.) at a profit of Rs. 3000. If rate of tax (under GST system) is 18%, find :
(i)Â The cost of goods/services to the dealer C in Jabalpur.
(ii)Â Net tax payable by dealer B.
Solution:
From the question,
For A (case of inter-state transaction)
S.P. in Meerut =Â Rs. 15,000
For B (case of inter-state transaction)
C.P. =Â Rs. 15,000
IGST = 18% of 15,000 = 18/100 x 15,000 = Rs. 2700
Now, the input tax for B =Â Rs. 2,700
And the S.P. in Ratlam = 15,000 + 3000 = Rs. 18,000
For C (case of intra-state transaction)
C.P. =Â Rs. 18,000
CGST = 9% of 18,000 = 9/100 x 18,000 = Rs. 1620
SGST = 9/100 x 18,000 = Rs. 1620
(i) Cost for the dealer C in Jabalpur
= S.P. for the dealer in Ratlam + GST
= 18,000 + 1620 + 1620
=Â Rs. 21,240
(ii) Output tax for B = Rs. 1620 + Rs. 1620 = Rs. 3240
Net GST payable by the dealer B
= Output tax – Input tax
= 1620 + 1620 – 2700
=Â Rs. 540
6. A dealer X in Hapur (U.P.) supplies goods/services, worth Rs. 50,000 to some other dealer Y in the same city. Now the dealer Y supplies the same goods/services to dealer Z in Calcutta at a profit of Rs. 20,000. Find:
(i)Â Output and input taxes for the dealer Y
(ii)Â Net GST payable by dealer Y.
[The rate of GST at each stage is 28%]
Solution:
From the question, we have
For the dealer X (intra-state transaction)
The SP =Â Rs. 50,000
For the dealer Y (intra-state transaction)
CP =Â Rs. 50,000
CGST = 14% of 50,000 =Â Rs. 7,000
SGST = 14% of 50,000 =Â Rs. 7,000
So, the input tax for dealer Y =Â Rs. 14,000
Profit =Â Rs. 20,000
SP =Â Rs. 70,000
For the dealer Z (inter-state transaction)
CP =Â Rs. 70,000
IGST = 28 % of Rs. 70,000 = 28/100 x 70,000 = Rs. 19,600
Thus, the input tax =Â Rs. 19,600 which becomes the output tax for dealer Y.
Now,
The net GST payable for Y will be
= Output tax for Y – Input tax for Y
= 19,600 – 14,000
=Â Rs. 5600
7. Consultancy services, worth Rs. 50,000, are transferred from Delhi to Calcutta at the rate of GST 18% and then from Calcutta to Nainital (with profit = Rs. 20,000) at the same rate of GST. Find the output tax at
(i)Â Delhi
(ii)Â Calcutta
(iii)Â NainitalÂ
Solution:
(i) Output tax in Delhi (inter-state):
IGST = 9% of 50,000 =Â Rs. 4500
Thus, the output tax in Delhi =Â Rs. 4500
(ii) Output tax in Calcutta:
C.P. in Calcutta =Â Rs. 50,000 and Profit =Â Rs. 20,000
S.P. in Calcutta = 50,000 + 20,000 =Â Rs. 70,000
IGST = 18% of 70,000 =Â Rs. 12,600
Thus, the output tax in Calcutta =Â Rs. 12,600
(iii) Since, the dealer in Nainital does not sell the product.
Thus, the output GST (tax on sale) =Â Rs. 0
8. For a dealer A, the list price of an article is Rs. 9000, which he sells to dealer B at some lower price. Further, dealer B sells the same article to a customer at its list price. If the rate of GST is 18% and dealer B paid a tax, under GST, equal to Rs. 324 to the government, find the amount (inclusive of GST) paid by dealer B.
Solution:
Let dealer A sell to dealer B at Rs. x lower price.
Then from the question,
Net Tax paid by dealer B is
⇒ Output tax – Input Tax = Rs. 324
⇒ 18% of 9000 – 18% of (9000 – x) = 324
⇒ 1620 – 1620 + 18% of x = 324
⇒ 18% of x = 324
⇒ x = 1800
Therefore, the selling price of B = 9000 – 1800 =Â Rs. 7200
And,
The amount (inclusive of GST) paid by dealer B
= 7200 + 18% of 7200
= 7200 + 1296
=Â Rs. 8496
9. The marked price of an article is Rs. 6000. A wholesaler sells it to a dealer at 20% discount. The dealer further sells the article to a customer at a discount of 10% on the marked price. If the rate of GST at each stage is 18%, find the amount of tax (under GST) paid by the dealer to the government.
Solution:
We have,
Initial marked price by manufacturer A is Rs. 6000
Then, B bought the T.V. at a discount of 20%.
Now, Cost price of B = 80% of 6000 =Â Rs. 4800
And, GST paid by B for purchase = 18% of 4800 =Â Rs. 864
Again, B sells T.V. at discount of 10% of market Price
So, the Selling price for B = 6000 – 10% of 6000 =Â Rs. 5400
And, GST charged by B on selling of T.V. = 18% of 5400
=Â Rs. 972
Thus, GST paid by B to the government
= GST charged on selling price – GST paid against purchase price
= 972 – 864
=Â Rs. 108
10. A is a manufacturer of T.V. sets in Delhi. He manufacturers a particular brand of T.V. set and marks it at Rs. 75,000. He then sells this T.V. set to a wholesaler B in Punjab at a discount of 30%. The wholesaler B raises the marked price of the T.V. set bought by 30% and then sells it to dealer C in Delhi. If the rate of GST = 5% find tax (under GST) paid by wholesaler B to the government.
Solution:
We know that,
Initial marked price by manufacturer A is Rs. 75,000
Then, B bought the T.V. at a discount of 30%.
So, the Cost price of B = 70% of 75,000 =Â Rs. 52,500
And, GST paid by B for purchase = 5% of 52,500 =Â Rs. 2625
Now, B sells T.V. by increasing marked price by 30%.
Then, the Selling price for B = 75,000 + 30% of 75,000 =Â Rs. 97,500
And, GST charged by B on selling of T.V. = 5% of 97,500
=Â Rs. 4875
Thus, the GST paid by B to the government
= GST charged on selling price – GST paid against purchase price
= 4875 – 2625
=Â Rs. 2250
11. For a trader, marked price of a refrigerator = Rs. 15,680 inclusive of GST at the rate of 12% on the marked price. Gagan, a customer for this refrigerator, asks the trader to reduce the marked price of the refrigerator to such extend that its reduced price plus GST on it is equal to marked price of the refrigerator. Find the required reduction.
Solution:
Let us assume the marked price of the refrigerator be Rs. x.
Which is inclusive of GST (12%)
So,
x + 12% of x = 15,680
1.12x = 15,680
x =Â Rs. 14,000
Initial marked price =Â Rs. 14,000
Now,
Let Rs. y be the price reduction asked by Gagan.
So, the new price = 14,000 – y
And, GST on new price = 12% of (14,000 – y)
From the question,
14,000 – y + 0.12(14,000 – y) = 14,000
-1.12y + 1680 = 0
y = 1500
Therefore, the required reduction in price is Rs. 1500.
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