ML Aggarwal Solutions for Class 7 Maths Chapter 7 Percentage and Its Applications are available here. To cover the entire syllabus in Maths, the ML Aggarwal solutions is an essential study material as it offers a wide range of questions that test students’ understanding of concepts. Students can gain a thorough knowledge of the concepts by referring to ML Aggarwal Solutions for Class 7 Maths.
Chapter 7 – Percentage and Its Applications are available for download in PDF for free. A percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the per cent sign, “%”. Suppose a student obtains 90 marks out of 100 in Maths; we can say that he has obtained 90 per cent marks in Maths. Topics covered in this ML Aggarwal Solutions for Class 7 Maths Chapter 7 include converting a fraction into a percentage, converting a percentage into a fraction, percentage as a ratio, and converting a given ratio into a percentage.
ML Aggarwal Solutions for Class 7 Maths Chapter 7 Percentage and Its Applications
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1. Convert the following percents into fractions in simplest form:
(i) 25%
Solution:-
25% can be written in the form of fraction as = 25/100
= ¼
(ii) 150%
Solution:-
150% can be written in the form of fraction as = 150/100
= 15/10
= 3/2
(iii) 7½%
Solution:-
First, convert the mixed fraction into an improper fraction,
7½% = (15/2)%
Then, (15/2)% can be written in the form of fraction as = (15/2)/100
= (15/(2 x 100))
= 15/200
= 3/40
(iv)
%
Solution:-
First, convert the mixed fraction into an improper fraction,
% = (100/3)%
Then, (100/3)% can be written in the form of fraction as = (100/3)/100
= (100/(3 x 100))
= 1/3
(2) Convert the following fractions into percents:
(i) 1/8
Solution:-
1/8 can be converted into per cent as,
= (1/8)/100
= (1/8) x 100
= 12.5%
(ii) 5/4
Solution:-
5/4 can be converted into per cent as,
= (5/4)/100
= (5/4) x 100
= 5 x 25
= 125%
(iii) 9/16
Solution:-
9/16 can be converted into per cent as,
= (9/16)/100
= (9/16) x 100
= 56¼ %
(iv) 3/7
Solution:-
3/7 can be converted into per cent as,
= (3/7)/100
= (3/7) x 100
=
%
(v) 11/15
Solution:-
11/15 can be converted into per cent as,
= (11/15)/100
= (11/15) x 100
=
%
(vi)
%
Solution:-
Convert the mixed fraction into an improper fraction, and we get,
11/8
11/8 can be converted into per cent as,
= (11/8)/100
= (11/8) x 100
= 137.5%
3.
(i) 6 students out of 40 students in a class are absent. What percentage of the students are absent?
Solution:-
From the question, it is given that,
The total number of students in the class is 40
Number of students who are absent = 6
Then, the percentage of the students who are absent = (6/40) x 100
= 0.15 x 100
= 15%
(ii) Antony secured 384 marks out of 500 marks. Find the percentage of marks secured by Antony.
Solution:-
From the question, it is given that,
Antony secured 384 marks
Maximum marks = 500 mark
Then, the percentage of marks secured by Antony = (384/500) x 100
= 0.768 x 100
= 76.8%
(iii) A shop has 500 shirts, out of which 15 are defective. What percentage of shirts are defective?
Solution:-
Total number of shits that shop has = 500
Number of defective shirts = 15
Then, the percentage of shirts that are defective = (15/500) x 100
= 0.03 x 100
= 3%
(iv) Vani has a collection of bangles. She has 20 gold bangles and 10 silver bangles. What is the percentage of each type of bangle?
Solution:-
From the question, it is given that,
Vani has a collection of bangles
Number of gold bangles = 20
Number of silver bangles = 10
Total number of bangles she has = 20 + 10 = 30 bangles
Then, percentage of gold bangles = (20/30) x 100
= 66.67%
Percentage of silver bangles = (10/30) x 100
= 33.34%
(v) There are 120 voters, and 90 of them voted. What per cent did not vote?
Solution:-
From the question, it is given that,
Total number of voters = 120
Number of voters voted = 90
Number of voters did not vote = 120 – 90 = 30
Then, per cent did not vote = (30/120) x 100
= 25%
4. Estimate the part of the figure which is shaded and hence find the percentage of the part which is shaded.
(i)
Solution:-
From the figure,
The shaded part = ¾
Then, the percentage of the part which is shaded = (¾) x 100
= 75%
(ii)
Solution:-
From the figure,
The shaded part = 2/6
= 1/3
Then, the percentage of the part which is shaded = (1/3) x 100
= 33.34%
(iii)
Solution:-
From the figure,
The shaded part = 5/8
Then, the percentage of the part which is shaded = (5/8) x 100
= 62.5%
5. Convert the following percentages into ratios in simplest form:
(i) 14%
Solution:-
14% can be written as,
= 14/100
= 7/50
It can be written in ratio form as = 7: 50
(ii) 7/4%
Solution:-
7/4% can be written as,
= (7/4)/100
= 7/(4 x 100)
= 7/400
It can be written in ratio form as = 7: 100
(iii) 100/3%
Solution:-
100/3% can be written as,
= (100/3)/100
= 100/(3 x 100)
= 1/3
It can be written in ratio form as = 1: 3
(iv) 37.5%
Solution:-
37.5% can be written as,
= 37.5/100
= 375/1000
= 3/8
It can be written in ratio form as = 3: 8
6. Express the following ratios as percentages:
(i) 5: 4
Solution:-
The above ratios can be written as = 5/4
Percentage = (5/4) x 100
= 5 x 25
= 125%
(ii) 1: 1
Solution:-
The above ratios can be written as = 1/1
Percentage = (1/1) x 100
= 100%
(iii) 2: 3
Solution:-
The above ratios can be written as = 2/3
Percentage = (2/3) x 100
= 66.67%
(iv) 9: 16
Solution:-
The above ratios can be written as = 9/16
Percentage = (9/16) x 100
= 0.5625 x 100
= 56.25%
7. An alloy consists of 7 parts of zinc and 33 parts of copper. Find the percentage of copper in the alloy.
Solution:-
From the question, it is given that,
An alloy consists of 7 parts of zinc
33 parts of copper
Then, the total parts contain in the alloy = 33 + 7 = 40
So, the percentage of copper in the alloy = (33/40) x 100
= 82.5%
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