# Selina Solutions Concise Mathematics Class 6 Chapter 5: Natural And Whole Numbers Exercise 5(D)

Selina Solutions Concise Mathematics Class 6 Chapter 5 Natural Numbers And Whole Numbers Exercise 5(D) provide problems on division of Whole Numbers for better conceptual knowledge among students. The solutions are created by experts at BYJUâ€™S, in accordance with the students’ understanding skills. Practicing these Solutions enables students to solve the textbook questions in a short duration without any errors. These solutions provide step by step methods in a simple and lucid manner to enhance their problem-solving abilities. Students can access Selina Solutions Concise Mathematics Class 6 Chapter 5 Natural Numbers And Whole Numbers Exercise 5(D) PDF, for free download from the links provided below.

## Selina Solutions Concise Mathematics Class 6 Chapter 5: Natural Numbers And Whole Numbers Exercise 5(D) Download PDF

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Exercise 5(A) Solutions

Exercise 5(B) Solutions

Exercise 5(C) Solutions

Exercise 5(E) Solutions

Exercise 5(F) Solutions

### Access Selina Solutions Concise Mathematics Class 6 Chapter 5: Natural Numbers And Whole Numbers Exercise 5(D)

#### Exercise 5(D) page no: 40

1. Show that:

(i) division of whole numbers is not closed.

(ii) any whole number divided by 1, always gives the number itself.

(iii) every non-zero whole number divided by itself gives 1 (one).

(iv) zero divided by any non-zero number is zero only.

(v) a whole number divided by 0 is not defined.

For each part, given above, give two suitable examples.

Solution:

(i) Example:

5 and 8 are whole numbers, but 5 Ã· 8 is not a whole number

Therefore, closure property does not exist for division of whole numbers

(ii) Example:

2 Ã· 1 = 2, 18 Ã· 1 = 18, 129 Ã· 1 = 129

Hence, the given statement, any whole number divided by 1, always gives the number itself is true.

(iii) Example:

2 Ã· 2 = 1, 128 Ã· 128 = 1, 256 Ã· 256 = 1

Therefore, the given statement, every non-zero whole number divided by itself gives one is true

(iv) Example:

0 Ã· 138 = 0, 0 Ã· 2028 = 0, 0 Ã· 15140 = 0

Therefore, the given statement, zero divided by any non-zero number is zero only, is true

(v) Example:

7 Ã· 0 is not defined

16 Ã· 0 is not defined

Hence, the given statement, a whole number divided by zero is not defined, is true

2. If x is a whole number such that x Ã· x = x, state the value of x.

Solution:

We know that, any number divided by 1, always gives the number itself

The value of x can be any number 1, 2, 3, 4, 5,6â€¦â€¦and so on.

3. Fill in the blanks:

(i) 987 Ã· 1 = â€¦â€¦â€¦..

(ii) 0 Ã· 987 = â€¦â€¦..

(iii) 336 â€“ (888 Ã· 888) = â€¦â€¦â€¦â€¦

(iv) (23 Ã· 23) â€“ (437 Ã· 437) = â€¦â€¦â€¦..

Solution:

(i) 987 Ã· 1 = 987

(ii) 0 Ã· 987 = 0

(iii) 336 â€“ (888 Ã· 888) = 335

(iv) (23 Ã· 23) â€“ (437 Ã· 437) = 0

4. Which of the following statements are true?

(i) 12 Ã· (6 Ã— 2) = (12 Ã· 6) Ã— (12 Ã· 2)

(ii) a Ã· (b â€“ c) = a / b â€“ a / c

(iii) (a â€“ b) Ã· c = a / c â€“ b / c

(iv) (15 â€“ 13) Ã· 8 = (15 Ã· 8) â€“ (13 Ã· 8)

(v) 8 Ã· (15 â€“ 13) = 8 / 15 â€“ 8 / 13

Solution:

(i) 12 Ã· (6 Ã— 2) = (12 Ã· 6) Ã— (12 Ã· 2)

12 Ã· 12 = 2 Ã— 6

1 â‰  12

Hence, the statement is false

(ii) a Ã· (b â€“ c) = a / b â€“ a / c

a / (b â€“ c) â‰  (ac â€“ ab) / bc

Hence, the statement is false

(iii) (a â€“ b) Ã· c â€“ a / c â€“ b / c

(a â€“ b) / c = (a â€“ b) / c

Hence, the statement is true

(iv) (15 â€“ 13) Ã· 8 = (15 Ã· 8) â€“ (13 Ã· 8)

(15 â€“ 13) / 8 = 15 â€“ 13 / 8

2 / 8 = 2 / 8

Hence, the statement is true.

(v) 8 Ã· (15 â€“ 13) = 8 / 15 â€“ 8 / 13

8 / 2 = (104 â€“ 120) / 15 (13)

4 â‰  (-16) / {15 (13)}

Hence, the statement is false

(iii) and (iv) statements are true