Selina Solutions Concise Maths Class 7 Chapter 4 Decimal Fractions (Decimals) Exercise 4B help students understand the steps to be followed in addition and subtraction of decimals. Our set of expert faculty at BYJU’S strive hard to provide students with ready-made answers for reference purposes. Students can understand the other methods, which can be followed in answering the problems. To boost the academic performance of students, Selina Solutions Concise Maths Class 7 Chapter 4 Decimal Fractions (Decimals) Exercise 4B, PDF links are available here for free download.
Selina Solutions Concise Maths Class 7 Chapter 4: Decimal Fractions (Decimals) Exercise 4B Download PDF
Access other exercises of Selina Solutions Concise Maths Class 7 Chapter 4: Decimal Fractions (Decimals)
Access Selina Solutions Concise Maths Class 7 Chapter 4: Decimal Fractions (Decimals) Exercise 4B
1. Add:
(i) 0.5 and 0.37
(ii) 3.8 and 8.7
(iii) 0.02, 0.008 and 0.309
(iv) 0. 4136, 0. 3195 and 0.52
(v) 9.25, 3.4 and 6.666
(vi) 3.007, 0.587 and 18.341
(vii) 0.2, 0.02 and 2.0002
(viii) 6. 08, 60.8, 0.608 and 0.0608
(ix) 29.03, 0.0003, 0.3 and 7.2
(x) 3.4, 2.025, 9.36 and 3.6221
Solution:
(i) 0.5 and 0.37
So we get
0.5 + 0.37 = 0.87
(ii) 3.8 and 8.7
So we get
3.8 + 8.7 = 12.5
(iii) 0.02, 0.008 and 0.309
So we get
0.02 + 0.008 + 0.309 = 0.337
(iv) 0.4136, 0.3195 and 0.52
So we get
0.4136 + 0.3195 + 0.52 = 1.2531
(v) 9.25, 3.4 and 6.666
So we get
9.25 + 3.4 + 6.666 = 19.316
(vi) 3.007, 0.587 and 18.341
So we get
3.007 + 0.587 + 18.341 = 21.935
(vii) 0.2, 0.02 and 2.0002
So we get
0.2 + 0.02 + 2.0002 = 2.2202
(viii) 6.08, 60.8, 0.608 and 0.0608
So we get
6.08 + 60.8 + 0.608 + 0.0608 = 67.5488
(ix) 29.03, 0.0003, 0.3 and 7.2
So we get
29.03 + 0.0003 + 0.3 + 7.2 = 36.5303
(x) 3.4, 2.025, 9.36 and 3.6221
So we get
3.4 + 2.025 + 9.36 + 3.6221 = 18.4071
2. Subtract the first number from the second:
(i) 5.4, 9.8
(ii) 0.16, 4.3
(iii) 0.82, 8.6
(v) 2.237, 9.425
(vi) 41 .03, 59.46
(vii) 3.92. 26.86
(viii) 4.73, 8.5
(ix) 12.63, 36.2
(x) 0.845, 3.71
Solution:
(i) 5.4, 9.8
It can be written as
9.8 – 5.4 = 4.4
(ii) 0.16, 4.3
It can be written as
4.3 – 0.16 = 4.14
(iii) 0.82, 8.6
It can be written as
8.6 – 0.82 = 7.78
(v) 2.237, 9.425
It can be written as
9.425 – 2.237 = 7.188
(vi) 41 .03, 59.46
It can be written as
59.46 – 41.03 = 18.43
(vii) 3.92, 26.86
It can be written as
26.86 – 3.92 = 22.94
(viii) 4.73, 8.5
It can be written as
8.5 – 4.73 = 3.77
(ix) 12.63, 36.2
It can be written as
36.2 – 12.63 = 23.57
(x) 0.845, 3.71
It can be written as
3.71 – 0.845 = 2.865
3. Simplify:
(i) 28.796 -13.42 – 2.555
(ii) 93.354 – 62.82 – 13.045
(iii) 36 – 18.59 – 3.2
(iv) 86 + 16.95 – 3.0042
(v) 32.8 – 13 – 10.725 +3.517
(vi) 4000 – 30.51 – 753.101 – 69.43
(vii) 0.1835 + 163.2005 – 25.9 – 100
(viii) 38.00 – 30 + 200.200 – 0.230
(ix) 555.555 + 55.555 – 5.55 – 0.555
Solution:
(i) 28.796 -13.42 – 2.555
It can be written as
= 28.796 – (13.42 + 2.555)
On further calculation
= 28.796 – 15.975
= 12.821
(ii) 93.354 – 62.82 – 13.045
It can be written as
= 93.354 – (62.82 + 13.045)
On further calculation
= 93.354 – 75.865
= 17.489
(iii) 36 – 18.59 – 3.2
It can be written as
= 36 – (18.59 + 3.2)
On further calculation
= 36 – 21.79
= 14.21
(iv) 86 + 16.95 – 3.0042
It can be written as
= 102.95 – 3.0042
On further calculation
= 99.9458
(v) 32.8 – 13 – 10.725 +3.517
It can be written as
= (32.8 + 3.517) – (13 + 10.725)
On further calculation
= 36.317 – 23.725
= 12.592
(vi) 4000 – 30.51 – 753.101 – 69.43
It can be written as
= 4000 – (30.51 + 753.101 + 69.43)
On further calculation
= 4000 – 853.041
= 3146.959
(vii) 0.1835 + 163.2005 – 25.9 – 100
It can be written as
= (0.1835 + 163.2005) – (25.9 + 100)
On further calculation
= 163.2840 – 125.9
= 37.484
(viii) 38.00 – 30 + 200.200 – 0.230
It can be written as
= (38.00 + 200.200) – (30 + 0.230)
On further calculation
= 238.200 – 30.230
= 207.970
= 207.97
(ix) 555.555 + 55.555 – 5.55 – 0.555
It can be written as
= (555.555 + 55.555) – (5.55 + 0.555)
On further calculation
= 611.110 – 6.105
= 605.005
4. Find the difference between 6.85 and 0.685.
Solution:
The difference between 6.85 and 0.685 = 6.85 – 0.685
= 6.165
5. Take out the sum of 19.38 and 56.025, then subtract it from 200.111.
Solution:
We know that the sum of 19.38 and 56.025 can be written as
19.38 + 56.025 = 75.405
We can write it as
Difference between 200.111 and 75.405
200.111 – 75.405 = 124.706
6. Add 13.95 and 1.003, and from the result, subtract the sum of 2.794 and 6.2.
Solution:
We know that addition of 13.95 and 1.003 can be written as
13.95 + 1.003 = 14.953
Similarly the sum of 2.794 and 6.2 can be written as
2.794 + 6.2 = 8.994
Here the difference between 14.953 and 8.994
14.953 – 8.994 = 5.959
7. What should be added to 39.587 to give 80.375?
Solution:
It is given that
Sum of two numbers = 80.375
One number = 39.587
So the other number = 80.375 – 39.587 = 40.788
8. What should be subtracted from 100 to give 19.29?
Solution:
It is given that
Sum of two numbers = 100
One number = 19.29
So the other number = 100 – 19.29 = 80.71
9. What is the excess of 584.29 over 213.95?
Solution:
It is given that
Sum of two numbers = 584.29
One number = 213.95
So the other number = 584.29 – 213.95 = 370.34
10. Evaluate:
(i) (5.4 – 0.8) + (2.97 -1.462)
(ii) (6.25 + 0.36) – (17.2 – 8.97)
(iii) 9.004 + (3 -2.462)
(iv) 879.4 – (87.94 – 8 .794)
Solution:
(i) (5.4 – 0.8) + (2.97 -1.462)
It can be written as
= 4.6 + 1.508
On further calculation
= 6.108
(ii) (6.25 + 0.36) – (17.2 – 8.97)
It can be written as
= 6.61 – 8.23
On further calculation
= – 1.62
(iii) 9.004 + (3 – 2.462)
It can be written as
= 9.004 + 0.538
On further calculation
= 9.542
(iv) 879.4 – (87.94 – 8 .794)
It can be written as
= 879.4 – 79.146
On further calculation
= 800.254
11. What is the excess of 75 over 48.29?
Solution:
We know that the excess of 75 over 48.29 can be written as
Hence, the excess of 75 over 48.29 is 26.71.
12. If A = 237.98 and B = 83.47.
Find:
(i) A – B
(ii) B – A.
Solution:
(i) A – B
It is given that A = 237.98 and B = 83.47
Substituting the values
A – B = 237.98 – 83.47
A – B = 154.51
(ii) B – A
It is given that A = 237.98 and B = 83.47
Substituting the values
B – A = 83.47 – 237.98
B – A = – 154.51
13. The cost of one kg of sugar increases from ₹28.47 to ₹32.65. Find the increase in cost.
Solution:
Cost of sugar = ₹28.47
Cost of sugar is raised = ₹32.65
Increase in the cost of sugar = ₹32.65 – ₹28.47 = ₹4.18
Comments