 # HC Verma Solutions Vol 2 Chapter 8 Gauss’s Law

HC Verma Solutions Vol 2 Chapter 8 Gauss’s Law will help students find the right answers to all the exercises and important questions given in the chapter. By going through the solutions students will understand how to solve problems related to Gauss’s Law which was first formulated by Joseph-Louis Lagrange in the year 1773 and later was improvised by Carl Friedrich Gauss in the year 1813. The formula is expressed as ϕ = Q / ϵ0 where Q = total charge within the given surface and ϵ0 = the electric constant. Gauss’s law is also called as Gauss’s flux theorem. Coulomb’s law can also be derived from this theorem.

## Key Chapter Topics Related To Gauss’s Law

Some of the important topics included are;

• Solid Angle
• Application of Gauss’s Law
• Spherical Charge Distributions
• The Flux of Electric Field Through a Surface

Class 12 students who are preparing for their exams and even JEE aspirants can use the HC Verma Solutions to understand the concepts more clearly as we as enhance their problem-solving skills. With the solutions, students can significantly boost their preparation and perform well in the exams. HC Verma book for physics is often regarded as the perfect book for students who are willing to prepare for Engineering and medical entrance exams. The solutions which are also available in a PDF format will give students a clear advantage over others when they have to tackle difficult numerical problems in less time.  Students can access the solutions below.

## Important Question In Chapter 8

1. A point charge c is placed in a metal block having a cavity. If the charge C is kept or brought outside the metal, will charge c experience any electric force?

2. A nonconducting material is used to make a circular ring of radius r and is placed with its axis parallel to a uniform electric field. The ring is then rotated about a diameter through 180°. What will happen to the flux of the electric field? Will it increase or decrease?

3. If the flux of the electric field through a spherical surface of radius 10 cm surrounding the total charge is 25 V-m then what will the flux over a concentric sphere of radius 20 cm be

(a) 200 V-m (b) 100 V-m (c) 500 V-m (d) 25 V-m

4. What happens when an electric dipole is kept at the centre of a sphere.

(a) The electric field is not zero anywhere on the sphere.

(b) The electric field is zero on a circle on the sphere.

(c) The flux of the electric field through the sphere is zero.

(d) The electric field is zero at every point of the sphere.

5. There is no net charge in a metallic particle which is placed beside a finite metal plate having a positive charge. State where the electric force will be present on the particle?

(a) parallel to the plate (b) away from the plate (c) close to the plate (d) zero electric force.

## HC Verma Solutions Vol 2 Gauss’s Law Chapter 8           