Test

**1. It is found that if a neutron suffers an elastic collinear collision with deuterium at rest, fractional oss of its energy is p**

_{d}; while for its similar collision with carbon nucleus at rest, fractional loss of energy is p_{C}. The values of p_{d}and p_{c}are respectively:a. (0, 0)

b. (0, 1)

c. (.89,.28)

d. (.28,.89)

L.M.C

mV_{1} + 2m V_{2} = mV_{0}

V_{1} + 2V_{2} = V_{0} …(1)

V_{2} – V_{1} = V_{0}…(2)

On solving

V_{2} = 2V_{0}/3 and V_{1}= V_{0}/3

Final KE of neutron= (1/2)mV_{1}^{2}= (1/2)m(V_{0}/3)^{2}

=

Loss of K.E =

Fractional loss P_{d} = (8/9) = 0.89

Similarly collision between N and C

mV_{1} + 12 m.V_{2} = mV_{0}

V_{1} + 12V_{2} = V_{0} …(1)

V_{1}-V_{2} = V_{0} …(2)

On Solving

V_{2} = 2V_{0}/13

And V_{1} = 11V_{0}/13

Final K.E =

Loss of KE =

Fractional loss P_{c} = (48/169) = 0.28

**Answer: (c)**

**2. The mass of a hydrogen molecule is 3.32 x 10**

^{-27}kg. If 10^{23}hydrogen molecules strike, per second, a fixed wall of area 2 cm^{2}at an angle of 45^{0}to the normal, and rebound elastically with a speed of 10^{3}m/s, then the pressure on the wall is nearly:a. 2.35 x 10

^{2}N/m

^{2}

b. 4.70 x 10

^{2}N/m

^{2}

c. 2.35 x 10

^{3}N/m

^{2}

d. 4.70 x 10

^{3}N/m

^{2}

Change in momentum of one molecule

Force

Where n -> no. of molecules incident per unit time

Pressure P = Force/Area

**Answer: (a)**

**3. A solid sphere of radius r made of a soft material of bulk modulus K is surrounded by a liquid in a cylindrical container. A mass less piston of area a floats on the surface of the liquid, covering entire cross section of cylindrical container. When a mass m is placed on the surface of the piston to compress the liquid, the fractional decrement in the radius of the sphere,(dr/r) is:**

a. mg/3Ka

b. mg/Ka

c. Ka/mg

d. Ka/3mg

Bulk modulus

From eq.(1) and (2)

**Answer: (a)**

**4. Two batteries with e.m.f. 12 V and 13 V are connected in parallel across a load resistor of 10 Ω. The internal resistances of the two batteries are 1 Ω and 2 Ω respectively. The voltage across the load lies between.**

a. 11.4 V and 11.5 V

b. 11.7 V and 11.8 V

c. 11.6 V and 11.7 V

d. 11.5 V and 11.6 V

**5. A particle is moving in a circular path of radius a under the action of an attractive potential U = -k/2r**

^{2}. Its total energy isa. zero

b.

c.

d.

F= -k/r^{3}

Centripetal force

Total Energy E = K + U = 0

**Answer: (a)**

**6. Two masses m**

_{1}= 5 kg and m_{2}= 10 kg, connected by an inextensible string over a frictionless pulley, are moving as shown in the figure. The coefficient of friction of horizontal surface is 0.15. The minimum weight m that should be put on top of m2 to stop the motion is:a. 43.3 Kg

b. 10.3 Kg

c. 18.3 Kg

d. 27.3 Kg

At equilibrium f_{r} = T = m_{1}g

f_{rmax} =(m_{2} + m)g

(10+m)g =5g

10 +m = 5/0.15

10+m = 100/3

m = (70/3)kg = 23.3 kg.

The minimum weight in the options is 27.3 kg.

**Answer: (d)**

**7. If the series limit frequency of the Lyman series is v**

_{L}, then the series limit frequency of the Pfund series is:a. v

_{L}/16

b. v

_{L}/25

c. 25v

_{L}

d. 16v

_{L}

Series limit is

Lyman : ∞

→ 1

P fund :∞

→ 5

v_{Lyman} = RC

v_{Pfund} = RC/25

**8. Unpolarized light of intensity I passes through an ideal polarizer A. Another identical polarizer B is placed behind A. the intensity of light beyond B is found to be I/2. Now another identical polarizer C is placed between A and B. The intensity beyond B is now found to be I/8. The angle between polarizer A and C is:**

a. 45

^{0}

b. 60

^{0}

c. 0

^{0}

d. 30

^{0}

Unpolarized light passes the A

I _{after A} = I/2

I _{after B} = I/2 (given)

The angle between A and B is 90^{0}

Let A and C have angle θ

I _{after c} = (I/2)cos^{2} θ

I _{after B} = (I/2)cos^{2} θ cos^{2}(90 – θ )= I/8, therefore, [cos θ sin θ]^{2}= ¼

Sin 2 θ = 1

Therefore, θ = 45^{0}

**Answer: (a)**

**9. An electron from various excited states of hydrogen atom emit radiation to come to the ground state. Let λ**

_{n}, λ_{g}be the de Broglie wavelength of the electron in the n^{th}state and the ground state respectively. Let A_{n}be the wavelength of the emitted photon in the transition from the n^{th}state to the ground state. For large n, (A, B are constants)a. Λ

^{2}

_{n}≈ A+B λ

^{2}

_{n}

b. Λ

^{2}

_{n}≈ λ

c. Λ

_{n}≈A + (B/ λ

^{2}n)

d. Λ

_{n}≈A + Bλ

_{n}

mvr = (nh/2 π)

λ_{de Broglie }= (h/p) = (2 πr/n)

λ_{n }=(2 πr_{n}/n)

_{}

**Answer: (c)**

**10. The reading of the ammeter for a silicon diode in the given circuit is:**

a. 11.5 mA

b. 13.5 mA

c. 0

d. 15 mA

Knowledge based

Si diode has forward bias resistance

200 at 2 V

400 at 1 V

⇒ here R_{fb} < 200 … at 3V

I = (V-ΔV)/R = (3-0.7)/200 = 2.3/200 = 11.5 mA

**Answer: (a)**

**11. An electron, a proton and an alpha particle having the same kinetic energy are moving in circular orbits of radii r**

_{e}, r_{p}, r_{α}respectively in a uniform magnetic field B. The relation between r_{e}, r_{p}, r_{α}is:a. r

_{e}< r

_{p}< r

_{α}

b. r

_{e}< r

_{α}< r

_{p}

c. r

_{e}> r

_{p}= r

_{α}

d. r

_{e}< r

_{p}= r

_{α}

r = mv/qB = p/qB

K = (1/2)mv^{2}——-same

= (p^{2}/2m)

Therefore, p ∞ √m

B same

r∝(p/q) or √m/q

q_{p} =q_{e}

m_{p} = 183 m_{e}

q_{α} = 2 q_{p}

m _{α}= 4 m_{p}

Mass of electron is least and charge qe = e

So, r _{e} < r _{p} = r

**Answer: (d)**

**12. A parallel plate capacitor of capacitance 90 pF is connected to a battery of emf 20V. If a dielectric material of dielectric constant k = 5/3 is inserted between the plates, the magnitude of the induced charge will be:**

a. 2.4 nC

b. 0.9 nC

c. 1.2 nC

d. 0.3 nC

Battery remains connected as dielectric is introduced

So E, V unchanged

q_{0} = C_{0}V

q = kC_{0}V

Induced charge q = q q_{0}

= C_{0}V(k-1)

= 90 x 10^{-12} x 20((5/3)-1) = 1.2 nC

**Answer: (c)**

**13. For an RLC circuit driven with voltage of amplitude V\(\begin{array}{l}\omega _{0}=\frac{1}{\sqrt{LC}}\end{array} \) the current exhibits resonance. The quality factor, Q is given by:**

_{m}and frequencya.

b.

c.

d.

Quantity factor

**Answer: (c)**

**14. A telephonic communication service is working at carrier frequency of 10 GHz. Only 10% of it is utilized for transmission. How**

a. 2 x 10

^{5}

b. 2 x 10

^{5}

c. 2 x 10

^{3}

d. 2 x 10

^{4}

No of channels =(carrier frequencyx0.1)/channel bandwidth

= (0.1 x 10 x 10^{9})/(5 x 10^{3})= 2 x 10^{5}

**Answer: (a)**

**15. A granite rod of 60 cm length is clamed at its middle point and is set into longitudinal vibrations. The density of granite is 2.7 x 10**

^{3}kg/m^{3}and its Young’s modulus is 9.27 x 10^{10}Pa. What will be the fundamental frequency of the longitudinal vibrations?a. 10 kHz

b. 7.5 kHz

c. 5kHz

d. 2.5 kHz

On substituting the value, we get the required answer.

**Answer: (c)**

**16. Seven identical circular planar disks, each of mass M and radius R are welded symmetrically as shown. The moment of inertia of the arrangement about the axis normal to the plane and passing through the point P is:**

a.

b.

c.

d.

M.I. about origin

**Answer: (b)**

**17. Three concentric metal shells A, B and C of respective radii a, b and c (a < b < c) have surface charge densities + σ, -σ and +σ respectively. The potential of shell B is:**

a.

b.

c.

d.

**Answer: (d)**

**18. In a potentiometer experiment, it is found that no current passes through the galvanometer when the terminals of the galvanometer when the terminals of the cell are connected across 52 cm of the potentiometer wire. If the cell is shunted by a resistance of 5 Ω, a balance is found when the cell is connected across 40 cm of the wire. Find the internal resistance of the cell.**

a. 2 Ω

b. 2.5 Ω

c. 1 Ω

d. 1.5 Ω

When switch s is opened

E = λL_{1}———-(I)

Where λ is potential gradient

when switch is closed E – ir = λL_{2} … (II)

Replace i = E/(R+r)

**Answer: (d)**

**19. An EM wave from air enters a medium. The electric fields are\(\begin{array}{l}\vec{E_{1}}=E_{01}\hat{x}cos\left [ 2\pi v\left ( \frac{z}{c}-t \right ) \right ]\end{array} \) in air and in medium, where the wave number k and frequency v refer to their values in air. The medium is nonmagnetic. If ε**

_{r1}refer ε_{r2}to relative permittivities of air and medium respectively, which of the following options is correct?a.

b.

c.

d.

**Answer: (a)**

**20. The angular width of the central maximum in a single slit diffraction pattern is 60**

^{0}. The width ofthe slit is 1μm. The slit is illuminated by monochromatic plane waves. If another slit of same width is made near it, Young’s fringes can be observed on a screen placed at a distance 50 cm from the slits. If the observed fringe width is 1 cm, what is slit separation distance? (i.e., distance between the cenrtres of each slit.)a. 75 μm

b. 100 μm

c. 25 μm

d. 50 μm

2α = 60^{0}

a=1 μm** **

D = 50 cm

(Cond. for minima/Path diff Δx = a sin θ = n λ)

a=1 μm and θ =30^{0} and n=1

λ = 0.5 μm

If same setup is used for YDSE

Fringe width β = λD/d = 1cm

d=0.5 x 10^{-6} x 0.5/0.01 = 25 μm

d = 25 μm

**Answer: (c)**

**21. A silver atom in a solid oscillates in simple harmonic motion in some direction with a frequency of 10**

^{12}/sec. What is the force constant of the bonds connecting one atom with the other? (Mole wt. of silver = 108 and Avagadro number = 6.02 x 10^{23}gm mole^{-1}a. 2.2 N/m

b. 5.5 N/m

c. 6.4 N/m

d. 7.1 N/m

Frequency

K =m(2 πf))^{2}

Mass of 1 atom

m=18 x 10^{-26} Kg

k = 18 x 10^{-26}(2π x 10^{12})^{2} = 4 π^{2} x 18 x 10^{-2}

k = 7.1 N/m (π^{2} =10)

**Answer: (d)**

**22. From a uniform circular disc of radius R and mass 9 M, a small disc of radius R/3 is removed as shown in the figure. The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through centre of disc is:**

a. 10 MR

^{2}

b. (37/9) MR

^{2}

c. 4 MR

^{2}

d. (40/9)MR

^{2}

Answer: (c)

**23. In a collinear collision, a particle with an initial speed v**

_{0}strikes a stationary particle of the same mass. If the final total kinetic energy is 50% greater than the original kinetic energy, the magnitude of the relative velocity between the two particles, after collision, is:a. V

_{0}/2

b. V

_{0}/√2

c. V

_{0}/4

d. √2 V

_{0}

L.M.C

mv_{1}+mv_{2}= mv_{0}

V_{1}+V_{2}=V_{0}———-(I)

Initial KE = (1/2)mV_{0}^{2}

Final KE = (1/2)mV_{1}^{2 }+ (1/2)mV_{2}^{2}

final kE = (3/2)initial kE

(I)^{2} – (II)

2V_{1}V_{2} = -(1/2) V_{0}^{2}———-(III)

(V_{1}-V_{2})^{2} = (V_{1}+V_{2})^{2} – 4V_{1}V_{2}

(V_{1}-V_{2})^{2} = V_{0}^{2}+V_{0}^{2} =2V_{0}^{2}

**Answer: (d)**

**24. The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is B**

_{1}. When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is B_{2}. The ratio B_{1}/B_{2}is:a. √2

b. 1/√2

c. 2

d. √3

Dipole moment μ = niA

μ = ix πR^{2}

If dipole moment is doubled keeping current const. R_{2} = R_{1}√2

Magnetic Field at center of loop

B= μ_{0}i/2R

**Answer: (a)**

**25. The density of the material in the shape of a cube is determined by measuring three sides of the cube and its mass. If the relative errors in measuring the mass and length are respectively 1.5% and 1%, the maximum error in determining the density is:**

a. 4.5 %

b. 6 %

c. 2.5 %

d. 3.5 %

= 1.5 + 3 x 1 = 4.5

**Answer: (a)**

**26. On interchanging the resistances, the balance point of a meter bridge shifts to the left by 10 cm. The resistance of their series combination is 1 k Ω. How much was the resistance on the left slot before interchanging the resistances?**

a. 550 Ω

b. 910 Ω

c. 990 Ω

d. 505 Ω

Let balancing length be L

If R_{1} and R_{2} are interchanged balancing length is (L – 10)

From equ (1) and (2)

Hence, L^{2}-10L = 110 x 100 +L^{2} – 210L

Therefore, 200L = 110 x 100

L = 55 cm

R_{1} + R_{2} = 1000 Ω

On Solving

R_{1} = 550 Ω

R_{2} = 450 Ω

**Answer: (a)**

**27. In an a.c. circuit, the instantaneous e.m.f. and current are given by e = 100 sin 30 t and i = 20 sin(30 t – (π/4)). In one cycle of a.c., the average power consumed by the circuit and the wattles current are, respectively:**

a. ((50/√2),0)

b. 50,0

c. 50,10

d. ((1000//√2),10)

**Answer: (d)**

**28. All the graphs below are intended to represent the same motion. One of them does it incorrectly. Pick it up.**

If Vs t is a straight line with -ve slope acc = – ve const.

Displacement V_{s} time is a parabola opening downward

Only incorrect option is (4)

Correct distance Vs time graph is

**Answer: (4)**

**29. Two moles of an ideal monoatomic gas occupies a volume V at 27**

^{0}C. The gas expands adiabatically to a volume 2 V. Calculate (a) the final temperature of the gas and (b) change in its internal energy.(1) (a) 189 K (b) -2.7 kJ

(2) (a) 195 K (b) 2.7 kJ

(3) (a) 189 K (b) 2.7 kJ

(4) (a) 195 K (b) -2.7 kJ

ΔU = -2.76 kJ

**Answer: (1)**

**30. A particle is moving with a uniform speed in a circular orbit of radius R in a central force inversely proportional to the nth power of R. If the period of rotation of the particle is T, then:**

a. T ∝ R

^{(n+1)/2}

b. T ∝ R

^{n/2}

c. T ∝ R

^{n/2}for any n

d. T ∝ R

^{(n/2)+1}

T ∝ R^{(n+1)/2}

**Answer: (a)**

## Video Lessons – January 10 Shift 1 Physics

## JEE Main 2018 Physics Paper With Solutions Shift 1 January 10

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