Chemical kinetics is an important topic in Physical Chemistry and basically deals with helping students understand the different aspects of a chemical reaction. More specifically, the term â€˜kineticsâ€™ deals with the rate of change of some quantity. For example, the rate of change of displacement is given as velocity. Likewise, acceleration is the rate of change of velocity.

Usually, based on this rate, chemical reactions can be classified as fast (eg: Na + H_{2}O), Moderate (Mg + H_{2}O) and slow (esterification) reactions. In this article, we will learn more about chemical kinetics and see ways to quantify the rate of a reaction and look into various factors which affect the rate of reaction.

### Table of Content

- What is Chemical Kinetics?
- Rate of Formations and Disappearances
- Average and Instantaneous Rate
- Factors Affecting The Reaction Rate
- Solved Questions

## What is Chemical Kinetics?

Chemical kinetics also called reaction kinetics helps us understand the rates of reactions and how it is influenced by certain conditions. It further helps to gather and analyze the information about the mechanism of the reaction and define the characteristics of a chemical reaction.

## Rate of Formations and Disappearances

In any chemical reaction, as the reaction proceeds, the amount of reactants decreases, whereas the amount of products increases. One has to understand that the rate of the overall reaction depends on the rate at which reactants are consumed or the rate at which the products are formed.

If a graph is plotted between the concentration of reactants and products and time, rate of formation of products and rate of disappearance of reactants can be easily calculated from the slope of curves for products and reactants. The overall rate of the reaction may or may not be equal to the rate of formations and disappearances.

(a) Product concentration is zero at time t = 0

(b) at time t = 0, both reactants and products are present.

From the graph, it is understood that the slope of the reactants curve is negative and that for product curve is positive, indicating the concentration of reactants and products, decreases and increases respectively. We will take a simple reaction as an example to illustrate how the rate of overall reactions, rate of disappearances of reactants and rate of formation of products are related.

Let us take the reaction of formation of water.

2H_{2} + O_{2} â†’ 2H_{2}O

From the balanced equation, it is under that, for one mole O_{2} consumed, 2 moles of H_{2} will be consumed and 2 moles of H_{2}O will be formed. Say, the reaction proceeds for 10 mins, taking 1 mole of H_{2} and O_{2} each in the reaction mixture.

2H_{2} + O_{2} â†’ 2H_{2}O

t = 0 1 1 0

t = 10 mins 1 â€“ 0.5 1 â€“ 0.25 0.5

Say after 10 minutes, 0.5 moles of H_{2} is consumed and according to stoichiometry, 0.25 moles of O_{2} is consumed and 0.5 moles of H_{2}O is formed. Now let us calculate the rates for H_{2}, O_{2} and H_{2}O for this first 10 minutes.

Rate of disappearance of \({{H}_{2}}=\frac{0.5-1}{10}\) \(\Rightarrow 0.05mol/\min\)

Rate of disappearance of \({{O}_{2}}=\frac{0.75-1}{10}=0.025mol/\min\)

Rate of formation of \({{H}_{2}}O=\frac{0.5-0}{10}=0.05\,mol/\min\)

From the above calculations, we can see that rate at which H_{2} is consumed is twice the rate at which O_{2} is consumed. So, the stoichiometry of the reaction relates, rates of formation and disappearances of difference reactants and products as follows. Let,

aA + bB â†’ cC + dD

be a reaction.

\(r=\frac{-1}{a}\frac{\Delta \left[ A \right]}{\Delta t}=\frac{-1}{b}\frac{\Delta \left[ B \right]}{\Delta t}=\frac{1}{c}\frac{\Delta \left[ C \right]}{\Delta t}=\frac{1}{d}\frac{\Delta \left[ D \right]}{\Delta t}\)Where r â†’ rate of the overall reaction,

Î”[A], Î”[B], Î”[C], Î”[D] represents a change in concentration and st â†’ change in time.

\(\frac{\Delta \left[ A \right]}{\Delta t}\)â†’ rate of disappearance of A \(\frac{\Delta \left[ B \right]}{\Delta t}\)â†’ rate of disappearance of B \(\frac{\Delta \left[ C \right]}{\Delta t}\)â†’ rate of formation of C \(\frac{\Delta \left[ D \right]}{\Delta t}\)= rate of formation of DTherefore, \(\text{rate of overall reaction}\,\text{=}\frac{\text{rate of formation/disappearance of any one component}}{\text{stoichiometric coefficient of that component}}\)

## Average and Instantaneous Rate

The rate of reaction can be classified into average and instantaneous rate depending on the amount of time period. If the time period taken is finite, then itâ€™s called average rate and is represented as,

\(r\,\,\text{avg=}\frac{\Delta [C]}{\Delta t}\)Î”l â†’ change in concentration

Î”t â†’ change in time

r avg â†’ average rate

Average rate doesnâ€™t give exact information in most cases about the completion of the reaction.

For example, let us consider the hydrolysis of esters to form acid and alcohol.

\(RCOOR’\overset{H_{2}O}{\rightarrow}RCOOH+R’OH\)Say at time t = 0, there was 1M solution of ester which becomes 0.5M in 30 mins. So it is logical for us to assume, that the reaction will be 100% completed in 1 hour. But in reality, the reaction takes more than 3 hours to reach completion. So, for getting a broader insight into the time taken for completion and other purposes, â€œInstantaneous rate is used, which is represented as,

\({{r}_{inst}}=\underset{\Delta t\to 0}{\mathop{\lim }}\,\frac{\Delta [C]}{\Delta t}=\frac{d[C]}{dt}\)From above its understood that, the time period taken is almost zero say from t = 0 to t = 0.0000 …1 second. This eventually comes out to be the differential of change in concentration wrt time.

For all practical purposes, the instantaneous rate is used which can be calculated from concentration is time graph by finding tangent at a point.

Unit of rate is Moll^{-1} s^{-1} because it is concentration/time and concentration is expressed in terms of Molarity/mol l^{-1}) it can also be Nm^{-2}/s if the active mass is used in terms of partial pressures. Depending on other units of time it can also be mol l^{-1} min^{-1} or mol l^{-1} hour^{-1} etc.

## Factors Affecting The Reaction Rate

The rate of a reaction can be altered if any of the following parameters are changed.

### Concentration of Reactants

According to collision theory, which is discussed later, reactant molecules collide with each other to form products. If the concentration of reactants is increased, the number of colliding particles will increase thereby, increasing the rate of reaction.

### Temperature

If the temperature is increased, the number of collisions between reactant molecules per second (frequency of collision). Increases, thereby increasing the rate of the reaction. But depending on whether the reaction is an endothermic or exothermic increase in temperature increases the rate of forward or backward reactions respectively.

### Catalyst

Catalysts alter the rate of the reaction by changing the reaction mechanism. There are two types of catalysts namely, promoters and poisons which increase and decrease the rate of reactions respectively.

**Read More:** Catalyst

For all the above factors, quantification is done in the following sections. We will try to establish a mathematical relationship between the above parameters and rate.

Problem 1: In the reaction N_{2} + 3H_{2} â†’ 2NH_{3}, it is found that the rate of disappearance of N_{2} is 0.03 mol l^{-1} s^{-1}. Calculate, the rate of disappearance of H_{2}, rate of formation of NH_{3} and rate of the overall reaction.

Solution:

N_{2} + 3H_{2} â†’ 2NH_{3}

The rates can be connected as,

\(r=\frac{-d\left[ {{N}_{2}} \right]}{dt}=\frac{-1}{3}\frac{d\left[ {{H}_{2}} \right]}{dt}=\frac{1}{2}\frac{d\left[ N{{H}_{3}} \right]}{dt}\)Given:

\(\frac{d\left[ {{N}_{2}} \right]}{dt}=0.03mol\,{{l}^{-1}}{{s}^{-1}}\)Therefore, overall rate (r) = 0.03 mol l^{-1} s^{-1}

Rate of disappearance of H_{2} \(\left( \frac{d\left[ {{H}_{2}} \right]}{dt}=\frac{3d\left[ {{N}_{2}} \right]}{dt} \right)=0.09\,mol\,{{l}^{-1}}{{s}^{-1}}\)

Rate of formation of \(N{{H}_{3}}\frac{d\left[ N{{H}_{3}} \right]}{dt}=\frac{2d\left[ {{N}_{2}} \right]}{dt}\) \(N{{H}_{3}}\frac{d\left[ N{{H}_{3}} \right]}{dt}=\frac{2d\left[ {{N}_{2}} \right]}{dt}=0.06\,mol\,{{l}^{-1}}{{s}^{-1}}\)

### Solved Questions

**1. What is the rate of reaction?**

Solution:

Rate of the reactions is defined as the rate at which the concentration is changing or the ratio of change in concentration and change in time

\(r=\frac{\Delta \left[ C \right]}{\Delta t}\)r â†’ rate, Î”[C] â†’ change in concentration

Î”t â†’ change in time.

**2. What is the relation between the rate of the overall reaction, rate of formation of products and rate of disappearance of reactants?**

Solution:

Let aA + bB â†’ cC + dD be a reaction, then

\(r=\frac{-1}{a}\frac{d\left[ A \right]}{dt}=\frac{-1}{b}\frac{d\left[ B \right]}{dt}=\frac{+1}{c}\frac{d\left[ C \right]}{dt}=\frac{+1}{d}\frac{d\left[ D \right]}{dt}\)Where r â†’ rate of the overall reaction

\(\frac{-d\left[ A \right]}{dt}\to\)rate of disappearance of A \(\frac{-d\left[ B \right]}{dt}\to\)rate of disappearance of B \(\frac{-d\left[ D \right]}{dt}\to\)rate of formation of D \(\frac{+d\left[ C \right]}{dt}\to\)rate of formation of C**3. What are average and instantaneous rates?**

Solution:

The average rate is calculated by taking a finite time period whereas the instantaneous rate is calculated for a time period that is almost tending to zero. Graphically, the slope of the graph between concentration vs time gives the average rate and tangent of a point gives instantaneous rate.

\({{r}_{avg}}=\frac{\Delta \left[ C \right]}{\Delta t}\,\,\,{{r}_{inst}}=\frac{d\left[ C \right]}{dt}\,\,or\,\,\underset{\Delta t\to 0}{\mathop{\lim }}\,\frac{\Delta \left[ C \right]}{\Delta t}\)