JEE Main 2024 Question Paper Solution Discussion Live JEE Main 2024 Question Paper Solution Discussion Live

Solubility and Solubility Product

What Is Solubility?

Solubility is the amount of the substance (ionic or others) soluble to make a saturated solution at a specified temperature and in a fixed volume of solvent. Solubility changes with the nature of the substance, solvent, temperature and presence of common ions.

Sparingly soluble substances have very low solubility (AgCl, BaSO4) in water. In spite of the low solubility, being ionic substances, they can be considered to form a saturated solution, and the ions are in equilibrium with the undissolved solid.

Read More: Solubility

\(\begin{array}{l}AgCl\rightleftharpoons Ag^+Cl^-\end{array} \)

(Undissolved ) (Dissolved)

Equilibrium constant of dissociation

\(\begin{array}{l}=Kc=\frac{{{\left[ Ag \right]}^{+}}{{\left[ Cl \right]}^{-}}}{\left[ AgCl \right]}\end{array} \)

Silver chloride being solid, the concentration is taken to be constant, such that a new equilibrium constant can be considered.

\(\begin{array}{l}\text{Solubility Product}=Ksp=Kc\left[ AgCl \right]=\left[ A{{g}^{+}} \right]\left[ C{{l}^{-}} \right]\end{array} \)
= Product of the concentration of the ions.

For a sparingly insoluble salt of the general formula, AxBy

\(\begin{array}{l}AxBy(s)\rightleftharpoons xA^y(aq)+yB^x-(aq)\end{array} \)
\(\begin{array}{l}Ksp=[xA^{y+}][yB^{x-}]^{y}\end{array} \)

The value is constant for the substance and varies only with temperature.

Significance of Solubility Product

  • The presence of a common ion may affect the equilibrium and hence, the concentration (solubility) but not the solubility product.
  • Precipitation of the solutes occurs when the ionic product exceeds the Ksp.

Solubility Videos

Solubility – JEE Chemistry

Solubility and Henry’s Law

Relationship between Solubility and Solubility Product

\(\begin{array}{l}AxBy\rightleftharpoons xA^{Y+}+yB^{x-}\end{array} \)

At equilibrium C Cx Cy

Ksp = [xAY+ ]x[yBx-]y = [Cx]x [Cy]y = [C]x [x]x [C]y [y]y

Ksp = [C]x [C]y [x]x [y]y = [C]x+y [x]x [y]y

Ksp = [S]x+y [x]x [y]y S is the solubility= C= mole/l

\(\begin{array}{l}\text{Solubility}= [S]^{x+y}=\frac{Ksp}{x^{x}y^{y}}\end{array} \)

Example: For silver chromate,

\(\begin{array}{l}Ag_2CrO_4\rightleftharpoons2Ag^{+}+CrO_{4}^{2-}\end{array} \)

Ksp = (2S)2 S = 4S3

Also Read 

Test your Knowledge on Solubility and solubility product

Comments

Leave a Comment

Your Mobile number and Email id will not be published.

*

*