NCERT Solutions for Class 7 Maths Exercise 3.3 Chapter 3 Data Handling in simple PDF are provided here. Use of bar graphs with a different purpose, choosing of scale and drawing double bar graphs are the topics covered in this exercise of NCERT Solutions for Class 7 Maths Chapter 3. The bar graph is defined as the representation of numbers using bars of uniform width and the lengths of the bars, depending upon the frequency and the scale that we have chosen. NCERT Solutions for Class 7 Chapter 3 can help students clear doubts quickly and help in learning the topics effectively.
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling – Exercise 3.3
Access Answers to NCERT Solutions for Class 7 Maths Chapter 3 – Data Handling Exercise 3.3
1. Use the bar graph (Fig 3.3) to answer the following questions.
(a) Which is the most popular pet? (b) How many students have a dog as a pet?
Solution:-
The bar graph represents the pets owned by the students.
(a) From the bar graph, the most popular pet is a cat. It is owned by 10 students out of 12 students.
(b) From the bar graph, 8 students have a dog as a pet out of 12 students.
2. Read the bar graph (Fig 3.4), which shows the number of books sold by a bookstore during five consecutive years, and answer the following questions.
(i) About how many books were sold in 1989? 1990? 1992?
(ii) In which year were about 475 books sold? About 225 books sold?
(iii) In which years were fewer than 250 books sold?
(iv) Can you explain how you would estimate the number of books sold in 1989?
Solution:-
(i) By observing the bar graph,
175 books were sold in the year 1989.
475 books were sold in the year 1990.
225 books were sold in the year 1992.
(ii) By observing the bar graph,
475 books were sold in the year 1990.
225 books were sold in the year 1992.
(iii) By observing the bar graph,
In the years 1989 and 1992, the number of books sold was less than 250.
(iv) By observing the bar graph, we can conclude that,
The number of books sold in the year 1989 is about 1 and ¾th part of 1 cm.
WKT, Scale is taken as 1 cm = 100 books
= 100 + (¾ × 100)
= 100 + (3 × 25)
= 100 + 75
= 175
3. Number of children in six different classes is given below. Represent the data on a bar graph.
| Class | Fifth | Sixth | Seventh | Eighth | Ninth | Tenth |
| Number of Children | 135 | 120 | 95 | 100 | 90 | 80 |
(a) How would you choose a scale?
(b) Answer the following questions:
(i) Which class has the maximum number of children? And the minimum?
(ii) Find the ratio of students of class sixth to the students of class eight.
Solution:-
(a) We will take the scale as 1 unit = 10 children because we can represent a bigger and clear difference among the number of students in class 7th and class 9th.
(b) (i) Class 5th has the maximum number of children, i.e., 135, and class 7th has the minimum number of children, i.e., 95.
(ii) The total number of students in class 6th is 120, and the total number of students in class 8th is 100.
Then,
Ratio between the number of students in class 6th and 8th,
= (120/100)
= 6/5
= 6: 5
4. The performance of a student in the 1st Term and 2nd Term is given. Draw a double bar graph choosing the appropriate scale, and answer the following.
| Subject | English | Hindi | Maths | Science | S. Science |
| 1st Term (M.M. 100) | 67 | 72 | 88 | 81 | 73 |
| 2nd Term (M.M. 100) | 70 | 65 | 95 | 85 | 75 |
(i) In which subject has the child improved his performance the most?
(ii) In which subject is the improvement the least?
(iii) Has the performance gone down in any subject?
Solution:-
(i) By observing the double bar graph, there was a maximum mark increase in the Maths subject. So, the child has improved his performance in Maths.
(ii) By observing the double bar graph, the improvement was the least in S. Science.
(iii) By observing the double bar graph, the performance In Hindi has gone down.
5. Consider this data collected from a survey of a colony.
| Favourite Sport | Cricket | Basket Ball | Swimming | Hockey | Athletics |
| Watching | 1240 | 470 | 510 | 430 | 250 |
| Participating | 620 | 320 | 320 | 250 | 105 |
(i) Draw a double bar graph choosing an appropriate scale.
What do you infer from the bar graph?
(ii) Which sport is most popular?
(iii) Which is more preferred, watching or participating in sports?
Solution:-
(i) The fig above is the double bar graph, which represents the people who prefer either watching or participating in different sports. By observing the double bar graph, we came to conclude that most people like watching and participating in cricket, while the least number of people like watching and participating in athletics.
(ii) By observing the double bar graph, we came to conclude that the people who like watching and participating in cricket are the tallest among all the bars. So, cricket is the most popular sport.
(iii) By observing the double bar graph, we came to conclude that watching sports has more preference, rather than participating in sports.
6. Take the data giving the minimum and the maximum temperature of various cities given at the beginning of this Chapter (Table 3.1). Plot a double bar graph using the data and answer the following:
(i) Which city has the largest difference in the minimum and maximum temperature on the given date?
(ii) Which is the hottest city and which is the coldest city?
(iii) Name two cities where the maximum temperature of one was less than the minimum temperature of the other.
(iv) Name the city which has the least difference between its minimum and the maximum temperature.
Solution:-
(i) By observing the double bar graph, we came to conclude that Jammu has the largest difference in the minimum and maximum temperature on 20.6.2006.
(ii) By observing the double bar graph, we came to conclude that Jammu is the hottest city and Bangalore is the coldest city.
(iii) By observing the double bar graph, Bangalore and Jaipur, Bangalore and Ahmedabad, for Bangalore, the maximum temperature was 28oC, while the minimum temperature of both Ahmadabad and Jaipur was 29oC.
(iv) By observing the double bar graph, Mumbai has the least difference between its minimum and maximum temperature.
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