NCERT Solutions for Class 7 Maths Exercise 12.3 Chapter 12 Algebraic Expressions

NCERT Solutions For Class 7 Maths Ex 12.3 PDF Free Download

NCERT Solutions for Class 7 Maths Exercise 12.3 Chapter 12 Algebraic Expressions in simple PDF are available here. In this exercise of NCERT Solutions for Class 7 Chapter 12 contains topics related to finding the value of an expression. PDFs are very useful to help students understand the question pattern and type of different problems. It is essential to understand the various kinds of problems and figure out the best solutions for them. Students can find NCERT Solutions for Class 7 Maths where students can understand the fastest way to solve.

Download the PDF of NCERT Solutions For Class 7 Maths Chapter 12 Perimeter and Area – Exercise 12.3

 

ncert sol class 7 math ch 12 ex 3
ncert sol class 7 math ch 12 ex 3
ncert sol class 7 math ch 12 ex 3
ncert sol class 7 math ch 12 ex 3
ncert sol class 7 math ch 12 ex 3
ncert sol class 7 math ch 12 ex 3
ncert sol class 7 math ch 12 ex 3
ncert sol class 7 math ch 12 ex 3
ncert sol class 7 math ch 12 ex 3

 

Access other exercises of NCERT Solutions For Class 7 Chapter 12 – Algebraic Expressions

Exercise 12.1 Solutions

Exercise 12.2 Solutions

Exercise 12.4 Solutions

Access answers to Maths NCERT Solutions for Class 7 Chapter 12 – Algebraic Expressions Exercise 12.3

1. If m = 2, find the value of:

(i) m – 2

Solution:-

From the question it is given that m = 2

Then, substitute the value of m in the question

= 2 -2

= 0

(ii) 3m – 5

Solution:-

From the question it is given that m = 2

Then, substitute the value of m in the question

= (3 × 2) – 5

= 6 – 5

= 1

(iii) 9 – 5m

Solution:-

From the question it is given that m = 2

Then, substitute the value of m in the question

= 9 – (5 × 2)

= 9 – 10

= – 1

(iv) 3m2 – 2m – 7

Solution:-

From the question it is given that m = 2

Then, substitute the value of m in the question

= (3 × 22) – (2 × 2) – 7

= (3 × 4) – (4) – 7

= 12 – 4 -7

= 12 – 11

= 1

(v) (5m/2) – 4

Solution:-

From the question it is given that m = 2

Then, substitute the value of m in the question

= ((5 × 2)/2) – 4

= (10/2) – 4

= 5 – 4

= 1

2. If p = – 2, find the value of:

(i) 4p + 7

Solution:-

From the question it is given that p = -2

Then, substitute the value of p in the question

= (4 × (-2)) + 7

= -8 + 7

= -1

(ii) – 3p2 + 4p + 7

Solution:-

From the question it is given that p = -2

Then, substitute the value of p in the question

= (-3 × (-2)2) + (4 × (-2)) + 7

= (-3 × 4) + (-8) + 7

= -12 – 8 + 7

= -20 + 7

= -13

(iii) – 2p3 – 3p2 + 4p + 7

Solution:-

From the question it is given that p = -2

Then, substitute the value of p in the question

= (-2 × (-2)3) – (3 × (-2)2) + (4 × (-2)) + 7

= (-2 × -8) – (3 × 4) + (-8) + 7

= 16 – 12 – 8 + 7

= 23 – 20

= 3

3. Find the value of the following expressions, when x = –1:

(i) 2x – 7

Solution:-

From the question it is given that x = -1

Then, substitute the value of x in the question

= (2 × -1) – 7

= – 2 – 7

= – 9

(ii) – x + 2

Solution:-

From the question it is given that x = -1

Then, substitute the value of x in the question

= – (-1) + 2

= 1 + 2

= 3

(iii) x2 + 2x + 1

Solution:-

From the question it is given that x = -1

Then, substitute the value of x in the question

= (-1)2 + (2 × -1) + 1

= 1 – 2 + 1

= 2 – 2

= 0

(iv) 2x2 – x – 2

Solution:-

From the question it is given that x = -1

Then, substitute the value of x in the question

= (2 × (-1)2) – (-1) – 2

= (2 × 1) + 1 – 2

= 2 + 1 – 2

= 3 – 2

= 1

4. If a = 2, b = – 2, find the value of:

(i) a2 + b2

Solution:-

From the question it is given that a = 2, b = -2

Then, substitute the value of a and b in the question

= (2)2 + (-2)2

= 4 + 4

= 8

(ii) a2 + ab + b2

Solution:-

From the question it is given that a = 2, b = -2

Then, substitute the value of a and b in the question

= 22 + (2 × -2) + (-2)2

= 4 + (-4) + (4)

= 4 – 4 + 4

= 4

(iii) a2 – b2

Solution:-

From the question it is given that a = 2, b = -2

Then, substitute the value of a and b in the question

= 22 – (-2)2

= 4 – (4)

= 4 – 4

= 0

5. When a = 0, b = – 1, find the value of the given expressions:

(i) 2a + 2b

Solution:-

From the question it is given that a = 0, b = -1

Then, substitute the value of a and b in the question

= (2 × 0) + (2 × -1)

= 0 – 2

= -2

(ii) 2a2 + b2 + 1

Solution:-

From the question it is given that a = 0, b = -1

Then, substitute the value of a and b in the question

= (2 × 02) + (-1)2 + 1

= 0 + 1 + 1

= 2

(iii) 2a2b + 2ab2 + ab

Solution:-

From the question it is given that a = 0, b = -1

Then, substitute the value of a and b in the question

= (2 × 02 × -1) + (2 × 0 × (-1)2) + (0 × -1)

= 0 + 0 +0

= 0

(iv) a2 + ab + 2

Solution:-

From the question it is given that a = 0, b = -1

Then, substitute the value of a and b in the question

= (02) + (0 × (-1)) + 2

= 0 + 0 + 2

= 2

6. Simplify the expressions and find the value if x is equal to 2

(i) x + 7 + 4 (x – 5)

Solution:-

From the question it is given that x = 2

We have,

= x + 7 + 4x – 20

= 5x + 7 – 20

Then, substitute the value of x in the equation

= (5 × 2) + 7 – 20

= 10 + 7 – 20

= 17 – 20

= – 3

(ii) 3 (x + 2) + 5x – 7

Solution:-

From the question it is given that x = 2

We have,

= 3x + 6 + 5x – 7

= 8x – 1

Then, substitute the value of x in the equation

= (8 × 2) – 1

= 16 – 1

= 15

(iii) 6x + 5 (x – 2)

Solution:-

From the question it is given that x = 2

We have,

= 6x + 5x – 10

= 11x – 10

Then, substitute the value of x in the equation

= (11 × 2) – 10

= 22 – 10

= 12

(iv) 4(2x – 1) + 3x + 11

Solution:-

From the question it is given that x = 2

We have,

= 8x – 4 + 3x + 11

= 11x + 7

Then, substitute the value of x in the equation

= (11 × 2) + 7

= 22 + 7

= 29

7. Simplify these expressions and find their values if x = 3, a = – 1, b = – 2.

(i) 3x – 5 – x + 9

Solution:-

From the question it is given that x = 3

We have,

= 3x – x – 5 + 9

= 2x + 4

Then, substitute the value of x in the equation

= (2 × 3) + 4

= 6 + 4

= 10

(ii) 2 – 8x + 4x + 4

Solution:-

From the question it is given that x = 3

We have,

= 2 + 4 – 8x + 4x

= 6 – 4x

Then, substitute the value of x in the equation

= 6 – (4 × 3)

= 6 – 12

= – 6

(iii) 3a + 5 – 8a + 1

Solution:-

From the question it is given that a = -1

We have,

= 3a – 8a + 5 + 1

= – 5a + 6

Then, substitute the value of a in the equation

= – (5 × (-1)) + 6

= – (-5) + 6

= 5 + 6

= 11

(iv) 10 – 3b – 4 – 5b

Solution:-

From the question it is given that b = -2

We have,

= 10 – 4 – 3b – 5b

= 6 – 8b

Then, substitute the value of b in the equation

= 6 – (8 × (-2))

= 6 – (-16)

= 6 + 16

= 22

(v) 2a – 2b – 4 – 5 + a

Solution:-

From the question it is given that a = -1, b = -2

We have,

= 2a + a – 2b – 4 – 5

= 3a – 2b – 9

Then, substitute the value of a and b in the equation

= (3 × (-1)) – (2 × (-2)) – 9

= -3 – (-4) – 9

= – 3 + 4 – 9

= -12 + 4

= -8

8. (i) If z = 10, find the value of z3 – 3(z – 10).

Solution:-

From the question it is given that z = 10

We have,

= z3 – 3z + 30

Then, substitute the value of z in the equation

= (10)3 – (3 × 10) + 30

= 1000 – 30 + 30

= 1000

(ii) If p = – 10, find the value of p2 – 2p – 100

Solution:-

From the question it is given that p = -10

We have,

= p2 – 2p – 100

Then, substitute the value of p in the equation

= (-10)2 – (2 × (-10)) – 100

= 100 + 20 – 100

= 20

9. What should be the value of a if the value of 2x2 + x – a equals to 5, when x = 0?

Solution:-

From the question it is given that x = 0

We have,

2x2 + x – a = 5

a = 2x2 + x – 5

Then, substitute the value of x in the equation

a = (2 × 02) + 0 – 5

a = 0 + 0 – 5

a = -5

10. Simplify the expression and find its value when a = 5 and b = – 3.

2(a2 + ab) + 3 – ab

Solution:-

From the question it is given that a = 5 and b = -3

We have,

= 2a2 + 2ab + 3 – ab

= 2a2 + ab + 3

Then, substitute the value of a and b in the equation

= (2 × 52) + (5 × (-3)) + 3

= (2 × 25) + (-15) + 3

= 50 – 15 + 3

= 53 – 15

= 38


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