 # NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Exercise 8.1

*According to the CBSE Syllabus 2023-24, this chapter has been renumbered as Chapter 7.

NCERT Solutions for Class 7 Maths Exercise 8.1 Chapter 8 Comparing Quantities in simple PDF are given here. This exercise of NCERT Solutions for Class 7 Maths Chapter 8 contains topics related to equivalent ratios. Different ratios can also be compared with each other to know whether they are equivalent or not. To do this, we need to write the ratios in the form of fractions and then compare them by converting them to like fractions. Our expert teachers have formulated these solutions in a precise and detailed form. Learn more about these topics by solving the questions of NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities with the help of solutions provided here.

## NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities – Exercise 8.1

### Access Other Exercises of NCERT Solutions for Class 7 Maths Chapter 8 – Comparing Quantities

Exercise 8.2 Solutions

Exercise 8.3 Solutions

### Access Answers to NCERT Class 7 Maths Chapter 8 – Comparing Quantities Exercise 8.1

1. Find the ratio of:

(a) ₹ 5 to 50 paise

Solution:-

We know that,

₹ 1 = 100 paise

Then,

₹ 5 = 5 × 100 = 500 paise

Now we have to find the ratio,

= 500/50

= 10/1

So, the required ratio is 10:1.

(b) 15 kg to 210 g

Solution:-

We know that,

1 kg = 1000 g

Then,

15 kg = 15 × 1000 = 15000 g

Now we have to find the ratio,

= 15000/210

= 1500/21

= 500/7 … [∵divide both by 3]

So, the required ratio is 500:7.

(c) 9 m to 27 cm

Solution:-

We know that,

1 m = 100 cm

Then,

9 m = 9 × 100 = 900 cm

Now we have to find the ratio,

= 900/27

= 100/3 … [∵divide both by 9]

So, the required ratio is 100:3.

(d) 30 days to 36 hours

Solution:-

We know that,

1 day = 24 hours

Then,

30 days = 30 × 24 = 720 hours

Now we have to find the ratio,

= 720/36

= 20/1 … [∵divide both by 36]

So, the required ratio is 20:1.

2. In a computer lab, there are 3 computers for every 6 students. How many computers will be needed for 24 students?

Solution:-

From the question, it is given that,

Number of computers required for 6 students = 3

So, the number of computers required for 1 student = (3/6)

= ½

So, the number of computers required for 24 students = 24 × ½

= 24/2

= 12

∴ The number of computers required for 24 students is 12 computers.

3. Population of Rajasthan = 570 lakhs and population of UP = 1660 lakhs.

Area of Rajasthan = 3 lakh km2, and the area of UP = 2 lakh km2.

(i) How many people are there per km2 in both these states?

(ii) Which State is less populated?

Solution:-

(i) From the question, it is given that,

Population of Rajasthan = 570 lakh

Area of Rajasthan = 3 lakh Km2

Then, population of Rajasthan in 1 km2 area = (570 lakh)/ (3 lakh km2)

= 190 people per km2

Population of UP = 1660 Lakh

Area of UP = 2 Lakh km2

Then, population of UP in 1 lakh km2 area = (1660 lakh)/ (2 lakh km2)

= 830 people per km2

(ii) By comparing the two states, Rajasthan is the less populated state.

Also, explore –

NCERT Solutions for Class 7 Maths

NCERT Solutions for Class 7

NCERT Solutions