** QUESTION 1**:

*What is the profit and theloss for the following transaction.Also find what is the profit percentage and the loss percentage in the cases given:*

*(i) Gardening shears were bought for Rs 250 and were sold for Rs 325*

*(ii) A refrigerator was bought for Rs 12,000 and sold for Rs 13,500*

*(iii) A cupboard was bought for Rs 2,500 and sold for Rs 3,000.*

*(iv) A shirt was bought for Rs 250 and sold for Rs 150*

*Solution;*

** (i)**the cost price of the gardening shears: Rs 250

The selling price of the gardening shears: Rs 325

Since, SP> CP therefore here it is a profit.

Therefore profit = SP – CP = Rs 325 – Rs 250

= Rs 75

Now profit % =

=

Therefore, Profit = Rs 75 and Profit % = 30%

** (ii)** Cost prince of refrigerator = Rs 12,000

Selling price of Refrigerator = Rs 13,500

Since, S.P > C.P Therefore, it is a profit.

Therefore, Profit = SP – CP = Rs 13500 – Rs 12000 = Rs 1500

Now profit % =

=

Therefore, Profit = Rs 1,500 and Profit % = 12.5 %

** (iii)** Cost price of cupboard = Rs 2500

Selling price of cupboard = Rs 3,000

Since, SP> CP, Therefore it is a profit.

Profit = SP – CP = Rs 3,000 – Rs 2,500 = Rs 500

=

Therefore, Profit = 500 and profit % = 20%

** (iv)** Cost price of shirt = Rs 250

Selling price of shirt = Rs 150

Since CP > SP, therefore here it is a loss.

Therefore Loss = CP – SP = Rs 250 – Rs 150

= Rs 100

Now loss % =

=

Therefore , Loss = Rs 100 and Loss% = 40%

*QUESTION 2: *

*Convert the following ratio to its percentages:*

*(i) 3 : 1*

*(ii) 2 : 3 : 5*

*(iii) 1 : 4*

*(iv) 1 : 2 : 5*

*Solution;*

** (i)**3 : 1

Total part = 3 + 1 = 4

Therefore, Fractional part =

=> Percentage of parts =

=> Percentage of parts = 75 % : 25 %

** (ii)**2 : 3 : 5

Total part = 2 + 3 + 5 = 10

Therefore, Fractional part =

=> Percentage of parts =

=> Percentage of parts = 20 % : 30 % : 50 %

** (iii)**1 : 4

Total part = 1 + 4 = 5

Therefore, Fractional part =

=> Percentage of parts =

=> Percentage of parts = 20% : 80%

** (iv)**1 : 2 : 5

Total part = 1 + 2 + 5 = 8

Therefore, Fractional part =

=> Percentage of parts =

=> Percentage of parts = 12.5 % : 25 % : 62.5 %

*QUESTION 3: *

*The population of a city decreased from 25,000 to 24,500. Find the decrease in percentage.*

*Solution;*

The decrease in population of a city is from 25,000 to 24,500.

Population Decreased = 25000 – 24500 = 500

Decreased percentage =

=

Hence, the percentage of decrease in the population is 2 %.

** QUESTION 4**:

*Reah and Reuben** bought a caravan for Rs. 3,50,000. The next year, the price raised to Rs 3,70,000. What is the percentage of price increased?*

*Solution;*

Increased in price of the caravan from Rs 3, 50,000 to 3, 70,000

Amount change = Rs 3, 70,000 – Rs 3, 50,000 = Rs 20,000

Therefore, Increased percentage =

Hence, The percentage of price increased is

*QUESTION 5: *

*Harismitha** bought a T.V for Rs 10,000 and sold it at a profit of 20%. How much money did she get for it?*

*Solution;*

The cost price of T.V = Rs 10000

Profit percent = 20%

Now, Profit = Profit % of CP

=

= Rs 2000

Selling price = CP + Profit = Rs 10000 + Rs 2000 = Rs 12000

She gets Rs 12000 on selling the T.V

*QUESTION 6: *

*Nancy sold a washing machine for Rs 13500. She Lost 20% in the bargain. What is the price that she bought the washing machine for?*

*Solution;*

Selling price of washing machine= Rs 13,500

Loss percent = 20%

Let the cost price of washing machine be Rs x

Since, Loss = Loss % of CP

=> Loss = 20 % of Rs x =

Therefore, SP = CP – Loss

Hence, The cost price of washing machine is Rs 16,875.

*QUESTION 7: *

*(a) Chalk contains Calcium, Carbon and Oxygen in the ratio 10: 3 : 12. Find the percentage of carbon in chalk.*

*(b) If in a stick of chalk, Carbon is 3g, what is the weight of the chalk stick?*

*Solution;*

** (a)** Given ratio = 10 : 3 : 12

Total part = 10 + 3 + 12 = 25

Part of carbon =

Percentage of Carbon part in Chalk =

** (b)** Quality of Carbon in chalk stick = 3g

Let the weight of chalk be x g.

Then, 12 % of x = 3

=>

=> x =

Hence, the weight of chalk stick is 25g.

*QUESTION 8: *

*Amulya buys a book for Rs 275 and sells it at a loss of 15% . How much does she sell it for?*

*Solution;*

The cost of a book = Rs 275

Loss percentage = 15 %

Loss = Loss % of CP = 15 % of 275

=

Therefore , SP = CP – Loss = 275 – 41.25 = Rs 233.75

Hence, Amulya sold the book for Rs 233.75

*QUESTION 9: *

*Find the amount to be paid at the end of 3 years in the following cases:*

*(i ) Principal = Rs 1200 at 12 % p. a*

*(ii) Principal = Rs 7500 at 5 % p. a*

*Solution;*

** (i)** Here, Principal (p) = 1200

Rate ( r ) = 12 % p a

Time ( T ) = 3 years

=432

Now, Amount = Principal + Simple Interest

= Rs 1200 + Rs 432

= Rs 1632

** (ii)** Here, Principal (p) = 7500

Rate ( r ) = 5 % p a

Time ( T ) = 3 years

= 1125

Now, Amount = Principal + Simple Interest

= Rs 7500 + Rs 1125

= Rs 8625

*QUESTION 10: *

*What rate gives Rs 280 as interest on a sum onRs 56,000 in 2 years?*

*Solution;*

Here, Principal (P ) = Rs 56000

Simple Interest (SI ) = Rs 280

Time ( T) = 2 yrs

Simple interest =

=> 280 =

=> R =

=> Hence, the rate of interest on sum is 0.25%

*QUESTION 11: *

*If Deepak gives an interest of Rs 45 for one year at 9% rate per annum. What is the sum he has borrowed from Nancy?*

*Solution;*

Simple Interest = Rs 45

Rate (R ) = 9%

Time ( T) = 1 year

Simple interest =

=> 45 =

=> P =

=> P = Rs 500

Hence, she had borrowed Rs 500.