The slope of a line (m) is determined by the value of tan θ, where, θ is the angle made by the line with the positive direction of x-axis in an anti-clockwise direction. The slope of the line passing through two points P (a1, b1) and Q (a2, b2) is given by:

\(m\;=\;tan\;\theta \;=\;\frac{b_{2}-b_{1}}{a_{2}-a_{1}}\)If m1 and m2 be the slopes of two lines. The angle θ between them is given by:

\(tan\;\theta =\;\pm \frac{(m_{1}-m_{2})}{1\;+\;m_{1}m_{2}}\)In case of acute angle, \(tan\;\theta =\;\pm \frac{(m_{1}-m_{2})}{1\;+\;m_{1}m_{2}}\)

- For parallel lines, m1 = m2
- For perpendicular lines, m1.m2 = -1

Three points A(h, k), B(m1, n1) and C(m2, n2) are said to be collinear, if, the slope of AB = slope of BC.

i.e. \(\frac{n_{1}-k}{m_{1}-h}=\frac{n_{2}-n_{1}}{m_{2}-m_{1}}\)Or, \((k-n_{1})\;(m_{2}-m_{1})\;=\;(h-m_{1})\;(n_{2}-n_{1})\)

### Equation of Line – Different Forms

- The equation of a line parallel to the x-axis and at a distance (p) from x-axis is given by, y = ± p.
- The equation of a line parallel to the y-axis and at a distance (q) from y-axis is given by, x = ± q.
- The equation of a line [Point-slope form] having slope (m) and passing through point (a0, b0) is given by, y – b0 = m(x – a0).
- The equation of a line [Two-point-form] passing through two points (a1, b1) and (a2, b2) is given by,

**5.**The equation of a line [Slope intercept form] making an intercept (p) on the y-axis (slope m) is given by y = mx + p. [value of p will be +ve or -ve based on the intercept made on

the +ve or -ve side of the y-axis].

- The equation of the line [Intercept form] making intercepts p and q on x and y axis respectively is given by

In normal form, the equation of the line is given by x cos ω + y sin ω = p. Where, p = Length of perpendicular (p) from the origin and ω = Angle which normal makes with the +ve x-axis direction.

The points (m1, n1) and (m2, n2) are on the same or opposite side of a line px + qy + r = 0, if pm1 + qn1 + r and pm2 + qn2 + r are of the same sign or of opposite signs respectively. The lines xm1 + yn1 + o1 = 0 and xm2 + yn2 + o = 0 are perpendicular, if, m2m1 + n2n1 = 0.

Also Access |

NCERT Solutions for Class 11 Maths Chapter 10 |

NCERT Exemplar for Class 11 Maths Chapter 10 |

### Straight Lines Class 11 Practice Questions

- Determine the equation of lines passing through (2, 3) and making angle 60° with

x-axis. - Determine the equation of a line parallel to the line 2x + 5y = 2 and passing through the point of intersection of lines 12x + 2y = 35 and 4x + 53y + 68 = 0.
- Determine the length of the triangle if the equation of the base of an equilateral triangle is 2x + 3y = 42 and the vertex is (3, -4).

- Determine the value of p and q if the intercepts cutoff on the coordinate axes by the

line px + qy + 3 = 0 are equal but have opposite signs to those cut off by the

line x – 2y + 4 = 0 on the axes.

- Determine the equation of the line if the intercept of a line connecting the coordinate axes is separated by a point (4, -3) in the ratio 2:4.

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