NCERT Solutions For Class 6 Maths Chapter 3 Playing with Numbers Exercise 3.6

The NCERT Solutions For Class 6 Maths Chapter 3 Playing with Numbers Exercise 3.5 explains the method of solving problems related to finding the HCF of a given set of numbers. These NCERT Solutions are prepared by the subject matter experts at BYJU’S to help students ace the exam. Set of examples are available in the NCERT textbook, before the exercise, to help students get a hold of the concepts. The faculties have followed the same method as of the solved examples to solve the questions present in the exercise. The faculties have done so to avoid any sort of confusions that could arise in the minds of the students. The exercise-wise problems can be solved and revised by the students with the help of the NCERT Solutions Class 6 Maths Chapter 3 Playing with Numbers Exercise 3.6.

NCERT Solutions for Class 6 Chapter 3: Playing with Numbers Exercise 3.6 Download PDF

 

ncert solutions class 6 maths chapter 3 ex 3.6
ncert solutions class 6 maths chapter 3 ex 3.6
ncert solutions class 6 maths chapter 3 ex 3.6
ncert solutions class 6 maths chapter 3 ex 3.6
ncert solutions class 6 maths chapter 3 ex 3.6

 

Access NCERT Solutions for Class 6 Chapter 3: Playing with Numbers Exercise 3.6

1. Find the HCF of the following numbers :

(a) 18, 48

(b) 30, 42

(c) 18, 60

(d) 27, 63

(e) 36, 84

(f) 34, 102

(g) 70, 105, 175

(h) 91, 112, 49

(i) 18, 54, 81

(j) 12, 45, 75

Solutions:

(a) 18, 48

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 1

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 2

18 = 2 × 3 × 3

48 = 2 × 2 × 2 × 2 × 3

HCF = 2 × 3 = 6

Therefore the HCF of 18, 48 is 6

(b) 30, 42

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 3

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 4

30 = 2 × 3 × 5

42 = 2 × 3 × 7

HCF = 2 × 3 = 6

Therefore the HCF of 30, 42 is 6

(c) 18, 60

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 5

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 6

18 = 2 × 3 × 3

60 = 2 × 2 × 3 × 5

HCF = 2 × 3 = 6

Therefore the HCF of 18, 60 is 6

(d) 27, 63

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 7

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 8

27 = 3 × 3 × 3

63 = 3 × 3 × 7

HCF = 3 × 3 = 9

Therefore the HCF of 27, 63 is 9

(e) 36, 84

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 9

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 10

36 = 2 × 2 × 3 × 3

84 = 2 × 2 × 3 × 7

HCF = 2 × 2 × 3 = 12

Therefore the HCF of 36, 84 is 12

(f) 34, 102

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 11

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 12

34 = 2 × 17

102 = 2 × 3 × 17

HCF = 2 × 17 = 34

Therefore the HCF of 34, 102 is 34

(g) 70, 105, 175

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 13

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 14

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 15

70 = 2 × 5 × 7

105 = 3 × 5 × 7

175 = 5 × 5 × 7

HCF = 5 × 7 = 35

Therefore the HCF of 70, 105, 175 is 35

(h) 91, 112, 49

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 16

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 17

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 18

91 = 7 × 13

112 = 2 × 2 × 2 × 2 × 7

49 = 7 × 7

HCF = 7

Therefore the HCF of 91, 112, 49 is 7

(i) 18, 54, 81

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 -19

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 20

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 21

18 = 2 × 3 × 3

54 = 2 × 3 × 3 × 3

81 = 3 × 3 × 3 × 3

HCF = 3 × 3 = 9

Therefore the HCF of 18, 54, 81 is 9

(j) 12, 45, 75

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 22

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 23

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.6 - 24

12 = 2 × 2 × 3

45 = 3 × 3 × 5

75 = 3 × 5 × 5

HCF = 3

Therefore the HCF of 12, 45, 75 is 3

 

2. What is the HCF of two consecutive

(a) numbers?

(b) even numbers?

(c) odd numbers?

Solutions:

(a) The HCF of two consecutive numbers is 1

Example: The HCF of 2 and 3 is 1

(b) The HCF of two consecutive even numbers is 2

Example: The HCF of 2 and 4 is 2

(c) The HCF of two consecutive odd numbers is 1

Example: The HCF of 3 and 5 is 1

3. HCF of co-prime numbers 4 and 15 was found as follows by factorisation:

4 = 2 × 2 and 15 = 3 × 5 since there is no common prime factor, so HCF of 4 and 15 is 0. Is the answer correct? If not, what is the correct HCF?

Solutions:

No. The answer is not correct. The correct answer is 1.


Access other exercise solutions of Class 6 Maths Chapter 3: Playing with Numbers

Exercise 3.1 Solutions

Exercise 3.2 Solutions

Exercise 3.3 Solutions

Exercise 3.4 Solutions

Exercise 3.5 Solutions

Exercise 3.7 Solutions

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