**Q-1) Complete the last column of the table.**

Sr. No. |
Equation |
Value |
Say, whether the equation is satisfied. (Yes/No) |

1 |
a + 4 = 0 |
a = 4 |
– |

2 |
a + 5 = 0 |
a = 0 |
– |

3 |
a + 4 = 0 |
a = – 4 |
– |

4 |
a – 8 = 1 |
a = 8 |
– |

5 |
a – 8 = 1 |
a = 9 |
– |

6 |
5a = 25 |
a = 0 |
– |

7 |
5a = 25 |
a = 5 |
– |

8 |
5a = 25 |
a = – 5 |
– |

9 |
x/3 = 3 |
x = – 9 |
– |

10 |
x/3 = 3 |
x = 0 |
– |

11 |
x/3 = 3 |
x = 9 |
– |

** ****Ans.)**

1. a + 4 = 0, a = 4

L.H.S = a + 4

By putting, a = 4;

Therefore, “**No**”, the equation is not satisfied.

2. a + 5 = 0, a = 0

L.H.S = a + 5

By putting, a = 0;

Therefore, “**No**”, the equation is not satisfied.

3. a + 4 = 0, a = – 4

L.H.S = a + 4

By putting, a = – 4;

L.H.S = – 4 + 4 = 0 = R.H.S

Therefore, “**Yes**”, the equation is satisfied.

4. a – 8 = 1, a = 8

L.H.S = a – 8

By putting, a = 8;

Therefore, “**No**”, the equation is not satisfied.

5. a – 8 = 1, a = 9

L.H.S = a – 8

By putting, a = 8;

L.H.S = 9 – 8 = 1 = R.H.S

Therefore, “**Yes**”, the equation is satisfied.

6. 5a = 25, a = 0,

L.H.S = 5a

By putting, a = 0;

Therefore, “**No**”, the equation is not satisfied.

7. 5a = 25, a = 5,

L.H.S = 5a

By putting, a = 5;

L.H.S = 5*5 = 25 = R.H.S

Therefore, “**Yes**”, the equation is satisfied.

8. 5a = 25, a = – 5,

L.H.S = 5a

By putting, a = – 5;

Therefore, “**No**”, the equation is not satisfied.

9. x/3 = 3, x = – 9,

L.H.S = x/3,

By putting, x = – 9;

Therefore, “**No**”, the equation is not satisfied.

10. x/3 = 3, x = 0,

L.H.S = x/3,

By putting, x = 0;

Therefore, “**No**”, the equation is not satisfied.

11. x/3 = 3, x = 9,

L.H.S = x/3,

By putting, x = 9;

L.H.S = 9/3 = 3 = R.H.S

Therefore, “**Yes**”, the equation is satisfied.

**Q-2) Verify whether the value in the brackets is the solution of the given equation.**

**x + 5 = 18 ( x = 1)****7x + 5 = 17 ( x = – 2)****7x + 5 = 19 ( x = 2)****4y – 3 = 11 (y = 1)****4y – 3 = 12 ( y = – 4)****4y – 3 = 14 ( y = 0)**

** **

**Ans.)**

1) Here, x + 5 is H.S, 18 is R.H.S and x = 1 ( given data)

L.H.S = x + 5,

By putting, x = 1,

As,

2) Here, 7x + 5 is H.S, 17 is R.H.S and x = – 2 ( given data)

L.H.S = 7x + 5,

By putting, x = – 2,

As,

3) Here, 7x + 5 is H.S, 19 is R.H.S and x = 2 ( given data)

L.H.S = 7x + 5,

By putting, x = 2,

L.H.S = 7(2) + 5 = 19 = R.H.S

As, L.H.S = R.H.S, so x = 2 is a solution.

4) Here, 4y – 3 is H.S, 11 is R.H.S and y = 1 ( given data)

L.H.S = 4y – 3,

By putting, y = 1,

As,

5) Here, 4y – 3 is H.S, 12 is R.H.S and y = – 4 ( given data)

L.H.S = 4y – 3,

By putting, x = – 4,

As,

6) Here, 4y – 3 is H.S, 14 is R.H.S and y = 0 ( given data)

L.H.S = 4y – 3,

By putting, x = 0,

As,

**Q-3) Solve the equation given below by trial and error method;**

**5m + 1 = 11****3p – 15 = 6**

Ans.)

1) 5m + 1 = L.H.S

By putting, m = 0,

By putting, m = 1,

By putting, m = 2,

5(2) + 1 = 11 = R.H.S

2) 3p – 15 = L.H.S

By putting, p = 5,

By putting, p = 6,

By putting, p = 7,

3(7) – 15 = 6 = R.H.S

**Q-4) Make the questions of the statements given below**

**The sum of numbers***p*and 5 is 10.**6 subtracted from***q*is 9.**Fifteen times***x*is 45.**The number***m*divided by 8 gives 2.**One-third of***n*is 9.**Ten times***k*plus 5 gives you 49.**Two-third of a number***h*minus 5 gives 7.**If you take away 7 from 7 times***w*, you get 56.**If you add 4 to One-fourth of***v*, you get 35.

**Ans.)**

*p*+ 5 = 10*q*– 6 = 9- 15
*x*= 45 *m*/8 = 2- 1/3
*n*= 9 - 10
*k*+ 5 = 49 - 2/3
*h*– 5 = 7 - 7
*w*– 7 = 56 - 1/4
*v*+ 4 = 35

**Q-5) Write the equations given below in the statement form;**

**x + 6 = 8****y – 9 = 10****4k = 14****1/3x = 9****1/5p = 8****1/2x + 6 = 9****4t + 3 = 27****3t – 4 = 25**

**Ans.)**

- The sum of
*x*and 6 is 8. - 9 subtracted from
*y*is 10. - Four times
*k*is 14. - One-third of
*x*is 9. - One-fifth of
*p*is 8. - When 6 is added to the half of a number
*x*, it gives 9. - Four times of a number
*t*, when added to 3, gives 27. - When 4 is subtracted from three times of number
*t*, gives 25.