# NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Exercise 4.2

NCERT Solutions for Class 7 Maths Exercise 4.2 Chapter 4 Simple Equations in simple PDF are provided here. Only one topic is covered in this exercise of NCERT Solutions for Class 7 Maths Chapter 4, i.e., Solving an equation. Students will learn how to solve the equations and obtain the final answer. Our expert teachers have formulated these NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations in a precise, comprehensive and detailed form.

## NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations â€“ Exercise 4.2

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### Access Answers to NCERT Solutions for Class 7 Maths Chapter 4 â€“ Simple Equations Exercise 4.2

1. Give first the step you will use to separate the variable and then solve the equation.

(a) x â€“ 1 = 0

Solution:-

We have to add 1 to both sides of the given equation.

Then, we get

= x â€“ 1 + 1 = 0 + 1

= x = 1

(b) x + 1 = 0

Solution:-

We have to subtract 1 from both sides of the given equation.

Then, we get

= x + 1 â€“ 1 = 0 â€“ 1

= x = â€“ 1

(c) x â€“ 1 = 5

Solution:-

We have to add 1 to both sides of the given equation.

Then, we get

= x â€“ 1 + 1 = 5 + 1

= x = 6

(d) x + 6 = 2

Solution:-

We have to subtract 6 from both sides of the given equation.

Then, we get

= x + 6 â€“ 6 = 2 â€“ 6

= x = â€“ 4

(e) y â€“ 4 = â€“ 7

Solution:-

We have to add 4 to both sides of the given equation.

Then, we get

= y â€“ 4 + 4 = â€“ 7 + 4

= y = â€“ 3

(f) y â€“ 4 = 4

Solution:-

We have to add 4 to both sides of the given equation.

Then, we get

= y â€“ 4 + 4 = 4 + 4

= y = 8

(g) y + 4 = 4

Solution:-

We have to subtract 4 from both sides of the given equation.

Then, we get

= y + 4 â€“ 4 = 4 â€“ 4

= y = 0

(h) y + 4 = â€“ 4

Solution:-

We have to subtract 4 from both sides of the given equation.

Then, we get

= y + 4 â€“ 4 = â€“ 4 â€“ 4

= y = â€“ 8

2. Give first the step you will use to separate the variable and then solve the equation.

(a) 3l = 42

Solution:-

Now, we have to divide both sides of the equation by 3.

Then, we get

= 3l/3 = 42/3

= l = 14

(b) b/2 = 6

Solution:-

Now, we have to multiply both sides of the equation by 2.

Then, we get

= b/2 Ã— 2= 6 Ã— 2

= b = 12

(c) p/7 = 4

Solution:-

Now, we have to multiply both sides of the equation by 7.

Then, we get

= p/7 Ã— 7= 4 Ã— 7

= p = 28

(d) 4x = 25

Solution:-

Now, we have to divide both sides of the equation by 4.

Then, we get

= 4x/4 = 25/4

= x = 25/4

(e) 8y = 36

Solution:-

Now, we have to divide both sides of the equation by 8.

Then, we get

= 8y/8 = 36/8

= x = 9/2

(f) (z/3) = (5/4)

Solution:-

Now, we have to multiply both sides of the equation by 3.

Then, we get

= (z/3) Ã— 3 = (5/4) Ã— 3

= x = 15/4

(g) (a/5) = (7/15)

Solution:-

Now, we have to multiply both sides of the equation by 5.

Then, we get

= (a/5) Ã— 5 = (7/15) Ã— 5

= a = 7/3

(h) 20t = â€“ 10

Solution:-

Now, we have to divide both sides of the equation by 20.

Then, we get

= 20t/20 = -10/20

= x = â€“ Â½

3. Give the steps you will use to separate the variable and then solve the equation.

(a) 3n â€“ 2 = 46

Solution:-

First, we have to add 2 to both sides of the equation.

Then, we get

= 3n â€“ 2 + 2 = 46 + 2

= 3n = 48

Now,

We have to divide both sides of the equation by 3.

Then, we get

= 3n/3 = 48/3

= n = 16

(b) 5m + 7 = 17

Solution:-

First, we have to subtract 7 from both sides of the equation.

Then, we get

= 5m + 7 â€“ 7 = 17 â€“ 7

= 5m = 10

Now,

We have to divide both sides of the equation by 5.

Then, we get

= 5m/5 = 10/5

= m = 2

(c) 20p/3 = 40

Solution:-

First, we have to multiply both sides of the equation by 3.

Then, we get

= (20p/3) Ã— 3 = 40 Ã— 3

= 20p = 120

Now,

We have to divide both sides of the equation by 20.

Then, we get

= 20p/20 = 120/20

= p = 6

(d) 3p/10 = 6

Solution:-

First, we have to multiply both sides of the equation by 10.

Then, we get

= (3p/10) Ã— 10 = 6 Ã— 10

= 3p = 60

Now,

We have to divide both sides of the equation by 3.

Then, we get

= 3p/3 = 60/3

= p = 20

4. Solve the following equations.

(a) 10p = 100

Solution:-

Now,

We have to divide both sides of the equation by 10.

Then, we get

= 10p/10 = 100/10

= p = 10

(b) 10p + 10 = 100

Solution:-

First, we have to subtract 10 from both sides of the equation.

Then, we get

= 10p + 10 â€“ 10 = 100 â€“ 10

= 10p = 90

Now,

We have to divide both sides of the equation by 10.

Then, we get

= 10p/10 = 90/10

= p = 9

(c) p/4 = 5

Solution:-

Now,

We have to multiply both sides of the equation by 4.

Then, we get

= p/4 Ã— 4 = 5 Ã— 4

= p = 20

(d) â€“ p/3 = 5

Solution:-

Now,

We have to multiply both sides of the equation by â€“ 3.

Then, we get

= â€“ p/3 Ã— (- 3) = 5 Ã— (- 3)

= p = â€“ 15

(e) 3p/4 = 6

Solution:-

First, we have to multiply both sides of the equation by 4.

Then, we get

= (3p/4) Ã— (4) = 6 Ã— 4

= 3p = 24

Now,

We have to divide both sides of the equation by 3.

Then, we get

= 3p/3 = 24/3

= p = 8

(f) 3s = â€“ 9

Solution:-

Now,

We have to divide both sides of the equation by 3.

Then, we get

= 3s/3 = -9/3

= s = -3

(g) 3s + 12 = 0

Solution:-

First, we have to subtract 12 from both sides of the equation.

Then, we get

= 3s + 12 â€“ 12 = 0 â€“ 12

= 3s = -12

Now,

We have to divide both sides of the equation by 3.

Then, we get

= 3s/3 = -12/3

= s = â€“ 4

(h) 3s = 0

Solution:-

Now,

We have to divide both sides of the equation by 3.

Then, we get

= 3s/3 = 0/3

= s = 0

(i) 2q = 6

Solution:-

Now,

We have to divide both sides of the equation by 2.

Then, we get

= 2q/2 = 6/2

= q = 3

(j) 2q â€“ 6 = 0

Solution:-

First, we have to add 6 to both sides of the equation.

Then, we get

= 2q â€“ 6 + 6 = 0 + 6

= 2q = 6

Now,

We have to divide both sides of the equation by 2.

Then, we get

= 2q/2 = 6/2

= q = 3

(k) 2q + 6 = 0

Solution:-

First, we have to subtract 6 from both sides of the equation.

Then, we get

= 2q + 6 â€“ 6 = 0 â€“ 6

= 2q = â€“ 6

Now,

We have to divide both sides of the equation by 2.

Then, we get

= 2q/2 = â€“ 6/2

= q = â€“ 3

(l) 2q + 6 = 12

Solution:-

First, we have to subtract 6 from both sides of the equation.

Then, we get

= 2q + 6 â€“ 6 = 12 â€“ 6

= 2q = 6

Now,

We have to divide both sides of the equation by 2.

Then, we get

= 2q/2 = 6/2

= q = 3

### Access Other Exercises of NCERT Solutions for Class 7 Maths Chapter 4 â€“ Simple Equations

Exercise 4.1 Solutions

Exercise 4.3 Solutions

Exercise 4.4 Solutions

Also, explore â€“Â

NCERT Solutions for Class 7 Maths

NCERT Solutions for Class 7Â

NCERT Solutions