RD Sharma Solutions Class 7 Operations On Rational Numbers Exercise 5.5

RD Sharma Class 7 Solutions Chapter 5 Ex 5.5 PDF Free Download

RD Sharma Solutions Class 7 Chapter 5 Exercise 5.5

Exercise 5.5

Q1. Find six rational numbers between \(\frac{-4}{8}\) and \(\frac{3}{8}\)

We know that

-4,-3,-2,-1,0,1,2,3

Therefore \(\frac{-4}{8}\)\(\frac{-3}{8}\)\(\frac{-2}{8}\)\(\frac{-1}{8}\)\(\frac{0}{8}\)\(\frac{1}{8}\)\(\frac{2}{8}\)\(\frac{3}{8}\)

Hence 6 rational numbers between \(\frac{-4}{8}\) and \(\frac{3}{8}\) are \(\frac{-3}{8}\), \(\frac{-2}{8}\), \(\frac{-1}{8}\), \(\frac{0}{8}\), \(\frac{1}{8}\), \(\frac{2}{8}\)

Q2. Find 10 rational numbers between \(\frac{7}{13}\) and \(\frac{-4}{13}\)

We know that

76543210-1-2-3-4

Therefore \(\frac{7}{13}\) \(\frac{6}{13}\) \(\frac{5}{13}\) \(\frac{4}{13}\) \(\frac{3}{13}\) \(\frac{2}{13}\) \(\frac{1}{13}\) \(\frac{0}{13}\) \(\frac{-1}{13}\) \(\frac{-2}{13}\) \(\frac{-3}{13}\) \(\frac{-4}{13}\)

Hence the 10 rational numbers between \(\frac{7}{13}\) and \(\frac{-4}{13}\) are

\(\frac{-3}{13}\), \(\frac{-2}{13}\),\(\frac{-1}{13}\),\(\frac{0}{13}\),\(\frac{1}{13}\),\(\frac{2}{13}\),\(\frac{3}{13}\),\(\frac{4}{13}\),\(\frac{5}{13}\),\(\frac{6}{13}\), \(\frac{7}{13}\),,

Q3. State true or false:

(i) Between any two distinct integers there is always an integer.

FALSE

(ii) Between any two distinct rational numbers there is always a rational number.

TRUE

(iii) Between any two distinct rational numbers there are infinitely many rational numbers.

TRUE

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