NCERT Solutions for Class 7 Maths Exercise 10.5 Chapter 10 Practical Geometry

*According to the latest CBSE Syllabus 2023-24, this chapter has been removed.

The NCERT Solutions for Class 7 Maths Exercise 10.5 Chapter 10 Practical Geometry in simple PDF are given here. Constructing a Right-Angled Triangle When the Length of One Leg and Its Hypotenuse are given (RHS Criterion) is the only topic covered in this exercise of the NCERT Solutions for Class 7 Maths Chapter 10. To help students with their exam preparation to achieve good marks in Maths, students are advised to try solving the problems from the NCERT Solutions for Class 7 Maths, Chapter 10 Practical Geometry. Then refer to these solutions to know the best way of approaching the different questions.

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry – Exercise 10.5

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Access Other Exercises of NCERT Solutions for Class 7 Maths Chapter 10 – Practical Geometry

Exercise 10.1 Solutions

Exercise 10.2 Solutions

Exercise 10.3 Solutions

Exercise 10.4 Solutions

Access Answers to NCERT Class 7 Maths Chapter 10 – Practical Geometry Exercise 10.5

1. Construct the right-angled ΔPQR, where m∠Q = 90°, QR = 8cm and PR = 10 cm.

Solution:-

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Image 13

Steps of construction

1. Draw a line segment QR = 8 cm.

2. At point Q, draw a ray QY to make an angle of 90o, i.e., ∠YQR = 90o.

3. With R as a centre and radius of 10 cm, draw an arc that cuts the ray QY at P.

4. Join PR.

Then, ΔPQR is the required right-angled triangle.

2. Construct a right-angled triangle whose hypotenuse is 6 cm long, and one of the legs is 4 cm long.

Solution:-

Let us consider ΔABC is a right-angled triangle at ∠B = 90o

Then,

AC is hypotenuse = 6 cm … [given in the question]

BC = 4 cm

Now, we have to construct the right-angled triangle by the above values.

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Image 14

Steps of construction

1. Draw a line segment BC = 4 cm.

2. At point B, draw a ray BX to make an angle of 90o, i.e., ∠XBC = 90o.

3. With C as a centre and radius of 6 cm, draw an arc that cuts the ray BX at A.

4. Join AC.

Then, ΔABC is the required right-angled triangle.

3. Construct an isosceles right-angled triangle ABC, where m∠ACB = 90° and AC = 6 cm.

Solution:-

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Image 15

Steps of construction

1. Draw a line segment BC = 6 cm.

2. At point C, draw a ray CX to make an angle of 90o, i.e., ∠XCB = 90o.

3. With C as a centre and radius of 6 cm, draw an arc that cuts the ray CX at A.

4. Join AB.

Then, ΔABC is the required right-angled triangle.

Also, explore – 

NCERT Solutions for Class 7 Maths

NCERT Solutions for Class 7 

NCERT Solutions


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  1. nicely answered better than most of the sites

  2. nicely answered better than other sites

  3. very easy to understand

  4. Easily understandable with ad free facility
    (Better than other sites)

  5. 👍Nicely explained the answers👍