 # NCERT Solutions For Class 6 Maths Chapter 14 Practical Geometry Exercise 14.4

NCERT Solutions For Class 6 Maths Chapter 14 Practical Geometry Exercise 14.4 are provided here to help students in their exam preparations. Perpendiculars and their construction using compass and ruler are the main concepts which are discussed under exercise 14.4. The problems related to these concepts are explained in NCERT Solutions Class 6 Maths using simple methods to make it easy for the students during exam preparation. Students can get their doubts cleared instantly by solving textbook problems using these solutions designed by our experts.

## NCERT Solutions for Class 6 Chapter 14: Practical Geometry Exercise 14.4 Download PDF    ### Access NCERT Solutions for Class 6 Chapter 14: Practical Geometry Exercise 14.4

1. Draw any line segment . Mark any point M on it. Through M, draw a perpendicular to . (use ruler and compasses)

Solutions:

(1) Draw a line segment and mark a point M on it. (2) Taking M as centre and a convenient radius, construct an arc intersecting the line segment at points C and D respectively. (3) By taking centres as C and D and radius greater than CM, construct two arcs such that they intersect each other at point E. (4) Join EM. Now is perpendicular to  2. Draw any line segment . Take any point R not on it. Through R, draw a perpendicular to . (use ruler and set-square)

Solutions:

(1) Draw a given line segment and mark a point R outside the line segment  (2) Place a set square on such that one of its right angles arm aligns along  (3) Now, place the ruler along the edge opposite to right angle of set square. (4) Hold the ruler fixed. Slide the set square along the ruler such that the point R touches the other arm of set square. (5) Draw a line along this edge of set square which passes through point R. Now, it is the required line perpendicular to  3. Draw a line l and a point X on it. Through X, draw a line segment perpendicular to l.

Now draw a perpendicular to XY at Y. (use ruler and compasses)

Solutions:

(1) Draw a line l and mark a point X on it. (2) By taking X as centre and with a convenient radius, draw an arc intersecting the line l at points A and B respectively. (3) With A and B as centres and a radius more than AX, construct two arcs such that they intersect each other at point Y. (4) Join XY. Here is perpendicular to l Similarly, by taking C and D as centres and radius more than CY, construct two arcs intersecting at point Z. Join ZY. The line is perpendicular to at Y 