RD Sharma Solutions for Class 12 Maths Chapter 23 Algebra of Vectors Exercise 23.3 are provided here. Top tutors of BYJU’S have designed these solutions to help students ace their Mathematics exams. These solutions are presented in a simple, precise and step-wise manner to aid all the students in securing a high score in the subject. The RD Sharma Solutions PDF can be downloaded from the link attached below.
RD Sharma Solution for Class 12 Maths Chapter 23 Exercise 3
Access Answers for RD Sharma Solution Class 12 Maths Chapter 23 Exercise 3
Exercise 23.3
1. Solution:
When,
Point R divides the line joining the two points P and Q in the ratio 1: 2 internally.
So, the position vector of point R =
And when,
Point R divides the line joining the two points P and Q in the ratio 1: 2 externally.
So, the position vector of point R =
2. Solution:
It’s given that
be the position vectors of the four distinct points A, B, C and D such that
So, AB is parallel and equal to DC (in magnitude).
Therefore, ABCD is a parallelogram.
3. Solution:
It’s given that
are position vectors of A and B, respectively.
Let C be a part of AB produced such that AC = 3AB
Thus, it’s clear that point C divides the line AB in a ratio 3: 2 externally
So,
The position vector of point C is given by
Again, let D be a point in BA produced such that BD = 2BA
Let
be the position vector of D. It is clear that point D divides the line AB in 1: 2 externally. So, the position vector of D is given by
4. Solution:
Given that,
It’s seen that the sum of the coefficients on both sides of equation (i) is 8, so divide equation (i) by 8 on both sides.
It shows that the position vector of a point P dividing AC in the ratio 3: 5, is the same as that of a point dividing BD in the ratio of 2: 6.
Hence, point P is the common point to AC and BD, and P is the point of intersection of AC and BD.
So, A, B, C and D are coplanar.
Therefore, the position vector of point P is given by
5. Solution:
It’s seen that the sum of the coefficients on both sides of equation (i) is 11, so divide equation (i) by 11 on both sides.
It shows the position vector of point A dividing PR in the ratio 6: 5 and QS in the ratio of 9: 2.
Hence, point A is the common point to PR and QS and it is also the point of intersection of PQ and QS.
So, P, Q, R and S are coplanar.
Therefore, the position vector of point A is given by
Comments