NCERT Solutions for Class 11 Biology Chapter 19 Excretory Products and Their Elimination

*According to the CBSE Syllabus 2023-24, this chapter has been renumbered as Chapter 16.

Get access to NCERT Solutions for Class 11 Biology Chapter 19 – Excretory Products and Their Elimination at BYJU’S. These NCERT Solutions are developed by experts after extensive research to put forth an authentic and accurate solution resource for Class 11 students. The experts provide NCERT solutions that help students understand the concepts in precise and simple language according to the latest CBSE Syllabus 2023-24. Utmost care is taken to produce the best answer possible to every question.

These NCERT Solutions, if practised meticulously, will clear all doubts pertaining to complex topics. Our panel of experts at BYJU’S have reviewed and analysed each chapter thoroughly so as to enhance the cognitive capabilities of students, which will prove to be extremely beneficial both in the board and entrance examinations. Chalking out a detailed study plan is one of the first strategies to be followed to crack any examination. Students are recommended to invest a few hours daily in solving the NCERT Solutions for Class 11 to perform exceedingly well at the CBSE examinations.

NCERT Solutions for Class 11 Biology Chapter 19 – Excretory Products and Their Elimination

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Access Answers to NCERT Class 11 Biology Chapter 19 – Excretory Products and Their Elimination

1. Define Glomerular Filtration Rate (GFR).

Solution:

Glomerular Filtration rate (GFR) is the amount of filtrate formed by both the kidneys (nephrons) every minute. The GFR of a healthy person is approximately 125ml per minute. The GFR consists majorly of water and other constituents such as amino acids, glucose, potassium, sodium, urea, uric acid and ketone bodies.

2. Explain the autoregulatory mechanism of GFR.

Solution:

Kidneys regulate the glomerular filtration rate through a mechanism which is auto-regulatory. It involves the action of the juxtaglomerular apparatus, which is a microscopic structure present between the returning distal convoluted tubule and vascular pole of the renal corpuscle of the same nephron. It regulates the glomerular filtration rate and renal blood flow. When the glomerular filtration rate declines, the juxtaglomerular cells are activated for the release of renin. This triggers the glomerular blood flow causing the GFR to revert to normal. Renin causes GFR to revert to normalcy by activating the renin-angiotensin mechanism.

3. Indicate whether the following statements are true or false.

(a) Micturition is carried out by a reflex.

(b) ADH helps in water elimination, making the urine hypotonic.

(c) Protein-free fluid is filtered from blood plasma into the Bowman’s capsule.

(d) Henle’s loop plays an important role in concentrating urine.

(e) Glucose is actively reabsorbed in the proximal convoluted tubule.

Solution:

(a) Micturition is carried out by a reflex. – True

(b) ADH helps in water elimination, making the urine hypotonic. – False

ADH helps in the reabsorption of water, causing the urine to be hypotonic.

(c) Protein-free fluid is filtered from blood plasma into the Bowman’s capsule. – True

(d) Henle’s loop plays an important role in concentrating urine. – True

(e) Glucose is actively reabsorbed in the proximal convoluted tubule. – True

4. Give a brief account of the counter-current mechanism.

Solution:

The chief adaptation for the conservation of water is the counter-current mechanism that is functional inside the kidney. In the kidney, there are two counter-current mechanisms, namely

  1. Henle’s loop
  2. Vasa recta

Biology - chapter 19 - image 1

  • Henle’s loop is a U-shaped part of the nephron. The flow of blood in the two branches of the tube is in the opposite direction, which gives rise to the counter currents.
  • Vasa recta, on the other hand, is an efferent arteriole that forms a capillary network around the tubules in the renal medulla, which tracks parallel to the Henle’s loop. Vasa recta are also U-shaped. The flow of blood is in opposite directions in the two limbs of the vasa recta. Hence, the blood that enters the renal medulla in the descending limb comes in close proximity with the outgoing blood in the ascending limb
  • Through the countercurrent mechanism, the osmolarity increases in the cortex from 300 mOsmolL-1 to about 1200 mOsmolL-1 in the inner medulla, which helps in sustaining the concentration gradient. This, in turn, aids in the easy movement of water from the collecting tubules. The concentration gradient is due to the movement of urea and NaCl.

5. Describe the role of the liver, lungs and skin in excretion.

Solution:

The role of the liver, lungs and skin in the process of excretion is as follows:

Liver

  • It is the chief site for the removal of inactivated products of steroid hormones, cholesterol, drugs and vitamins.
  • Dead erythrocytes possess haemoglobin. This haemoglobin is also disintegrated into bile pigments – biliverdin and bilirubin, which are treated wastes.
  • Bile carries substances to the intestine, which along with the wastes, are eliminated.

Lungs

  • Carbon dioxide is expelled from the body by the lungs.
  • Approximately it eliminates 200ml of carbon dioxide every minute.
  • Water in the form of water vapour is also eliminated.
  • Loss of water increases in colder conditions and declines in humid, hot conditions.
  • During the process of expiration, several volatile materials are also ejected.

Skin

  • It is chiefly responsible for the thermoregulation (cooling) of the body.
  • Sweat is excreted by the skin. It contains nitrogenous wastes. Sweat is excreted only when necessary, such as to cool the body.
  • Sweat is excreted by the sweat glands and constitutes urea, NaCl and lactic acid.
  • Through the sebum, the sebaceous glands remove hydrocarbons, sterols and waxes.
  • A protective oily covering is provided to the skin by the sebum.

6. Explain micturition.

Solution:

Micturition is the process of releasing urine. Micturition is caused by a neural mechanism known as the micturition reflex.

Biology - chapter 19 - image 2

The urinary bladder temporarily stores the urine that is formed. The bladder tends to stretch when the urinary bladder gets filled with urine. This stretching causes to initiate a signal, and responding to this signal, the receptors located in the walls of the bladder send out signals to the central nervous system (CNS). The CNS conveys motor messages that originate the relaxation of the urethral sphincters and the contraction of the smooth muscles of the urinary bladder, thereby resulting in micturition (passing of urine).

7. Match the items of column I with those of column II.

Column I Column II
(a) Ammonotelism (i) Birds
(b) Bowman’s capsule (ii) Water reabsorption
(c) Micturition (iii) Bony fish
(d) Uricotelism (iv) Urinary bladder
(d) ADH (v) Renal tubule

Solution:

Column I Column II
(a) Ammonotelism (iii) Bony fish
(b) Bowman’s capsule (v) Renal tubule
(c) Micturition (iv) Urinary bladder
(d) Uricotelism (i) Birds
(d) ADH (ii) Water reabsorption

8. What is meant by the term osmoregulation?

Solution:

Osmoregulation is the process of regulating the osmotic concentration in the cells of the body by checking the quantity of water and salts.

9. Terrestrial animals are generally either ureotelic or uricotelic, not ammonotelic. Why?

Solution:

Ammonia is an extremely toxic nitrogenous waste. In order to reduce the toxicity of ammonia in the body, a very large amount of water is necessary. To dilute ammonia, the bodies of terrestrial animals do not possess an adequate quantity of water. If the body of terrestrial animals stores this excess ammonia, it may turn extremely poisonous for them. Hence, in such animals, ammonia is always converted to less toxic uric acid and urea. This is the reason why terrestrial animals are generally either uricotelic or ureotelic.

10. What is the significance of the juxtaglomerular apparatus (JGA) in kidney function?

Solution:

The juxtaglomerular apparatus is a specialised sensitive region that is formed by the cellular modifications in the distal convoluted tubule and the afferent arteriole at the location of their contact.

Significance

  • Its mechanism is via the renin-angiotensin-aldosterone system (RAAS).
  • When the glomerular filtration rate dips, the juxtaglomerular apparatus stimulates, causing the secretion of renin.
  • This renin converts a protein into a peptide, i.e., angiotensinogen, to angiotensin.
  • Angiotensin is a hormone that elevates the GFR and the flow of blood in these three ways:
    1. Narrowing the efferent arterioles causes an increase in glomerular pressure.
    2. Triggering the walls of the PCT in order to reabsorb more water and NaCl.
    3. Triggers the adrenal gland to secrete aldosterone that facilitates reabsorption of water and NaCl in the DCT.
  • The volume of blood and blood pressure thereby increases. The hypertonic urine and urine volume decreases.

11. Name the following.

(a) A chordate animal having flame cells as excretory structures.

(b) Cortical portions projecting between the medullary pyramids in the human kidney.

(c) A loop of capillary running parallel to Henle’s loop.

Solution:

(a) A chordate animal having flame cells as excretory structures. – Amphioxus

Flame cells or protonephridia are the excretory structures found in some animals.

(b) Cortical portions projecting between the medullary pyramids in the human kidney. – Columns of

Bertini

The medulla is divided into several conical masses (medulla pyramids) that project into the calyces. The cortex extends in between the medullary pyramids as renal columns known as Columns of Bertini.

(c) A loop of capillary running parallel to Henle’s loop. – Vasa recta

A minute vessel of the network that runs parallel to the Henle’s loop forms a ‘U’ shaped vasa recta. Vasa recta are highly reduced in the cortical nephrons.

12. Fill in the gaps.

(a) Ascending limb of Henle’s loop is ______ to water, whereas the descending limb is _______ to it.

(b) Reabsorption of water from distal parts of the tubules is facilitated by hormone _______.

(c) Dialysis fluid contain all the constituents as in plasma except _______.

(d) A healthy adult human excretes (on an average) _______ gm of urea/day

Solution:

  1. Impermeable, permeable
  2. Vasopressin (anti-diuretic hormone)
  3. Nitrogenous waste
  4. 25-30

NCERT Solutions for Class 11 Biology Chapter 19 – Excretory Products and Their Elimination

NCERT Solutions for Class 11 Biology Chapter 19 – Excretory Products and Their Elimination are categorised under Unit 5 Human Physiology and included in the CBSE Syllabus for the 2022-23 session. Apart from thorough preparation, students can refer to the previous years’ question papers which has numerous benefits, one of which is it makes students familiar with the important questions appearing over the years.

This is where analysing question papers come in handy. As per previous trends, this unit 5 carries around 18 marks of the total, which approximately adds up to 25% of the total weightage. Hence, students must pay extra attention to all the chapters in this unit.

List of subtopics covered in Chapter 19 – Excretory Products and Their Elimination

Number Subtopic
19.1 Human Excretory System
19.2 Urine Formation
19.3 Function of the Tubules
19.4 Mechanism of Concentration of the Filtrate
19.5 Regulation of Kidney Function
19.6 Micturition
19.7 Role of other Organs in Excretion
19.8 Disorders of the Excretory System

NCERT Solutions for Class 11 Biology Chapter 19 – Excretory Products and Their Elimination

Excretion is a basic life process that is carried out by living entities. The chapter explains the Human excretory system and its corresponding organs performing respective functions. Some other topics covered are the formation of urine, different functions that the tubules perform, the mechanism of concentration of the filtrate, etc. The kidney is a vital organ, it filters the liquid that flows into it. Through this chapter, students learn how the kidney regulates its functions, how the act of micturition is performed and the significance of related organs in the excretory system.

Key Features of NCERT Solutions for Class 11 Biology Chapter 19 – Excretory Products and Their Elimination

  • NCERT Solutions are the ultimate resource for CBSE students.
  • Solutions at BYJU’S are framed by academic professionals.
  • Enables students to unlock their own potential.
  • Aids students in adopting the tactic of answering the right way.
  • Solutions help students assess their own preparation.
  • Solutions are provided in an easy-to-understand language.

Frequently Asked Questions on NCERT Solutions for Class 11 Biology Chapter 19

Q1

Why should I learn Chapter 19 of NCERT Solutions for Class 11 Biology thoroughly?

Chapter 19 of NCERT Solutions for Class 11 Biology is categorised under Unit 5. Along with second board exam preparation, students can also solve previous years’ question papers which have various advantages. By thorough practice, students will be able to analyse the type of questions that would appear in the Class 11 final exam. According to the previous trends, Unit 5 is around 18 marks which is 25% of the total weightage. So extra attention should be paid towards the chapters present in this unit. The solutions are present in a PDF format which can be used by the students based on their needs.
Q2

Do the NCERT Solutions for Class 11 Biology Chapter 19 provide accurate solutions?

The NCERT Solutions for Class 11 Biology Chapter 19 are designed by the academic professionals at BYJU’S to help students with their board exam preparation. Each and every concept is explained in a simple language that enables students to unlock their own potential. By referring to NCERT Solutions, students will be able to answer difficult questions effortlessly. Students can also self-assess their knowledge about the Chapter and work on them for a better score. The faculty make use of a step-wise method of answering questions to help students score well in the board exam.
Q3

Explain the role of lungs in excretion from Chapter 19 of NCERT Solutions for Class 11 Biology.

1. Lungs help in expelling carbon dioxide from our bodies.
2. Every minute, 200 ml of carbon dioxide is eliminated.
3. Lungs also eliminate water in the form of water vapour.
4. In colder conditions loss of water increases, whereas in hot conditions, it is declined.
5. Several volatile materials are ejected during the process of expiration.
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