# RD Sharma Solutions Class 12 Straight Line In Space Exercise 28.1

RD Sharma Solutions for Class 12 Maths Chapter 28 Straight Line in Space Exercise 28.1, is provided here. BYJUâ€™S tutor team has prepared solutions which help students attain good marks in Maths. From the exam point of view, the solutions are solved in a simple and structured manner where students can secure an excellent score in the board exams. RD Sharma Solutions pdf can be downloaded from the links given below.

## Download PDF of Rd Sharma Solution for Class 12 Maths Chapter 28 Exercise 1

### Access Answers for Rd Sharma Solution Class 12 Maths Chapter 28 Exercise 1

Q1.

Solution:

Q2.

Solution:

It is given that,

The direction ratios of the line are: (3+1, 4-0, 6-2) = (4, 4, 4)

Since the given line passes through (-1, 0, 2)

We know that the vector equation of a line is given as

Q3.

Solution:

Let us consider,

Vector equation of line passing through a fixed point vector a and parallel to vector b is given as

Q4.

Solution:

Let us consider,

Vector equation of line passing through a fixed point vector a and parallel to vector b is given as

Hence,

The Cartesian form of equation of the line is

Q5.

Solution:

It is given that, ABCD is a parallelogram.

Let us consider, AC and BD bisects each other at point O.

So,

Let us consider position vector of point O and B are represented by

So,

Equation of the line BD is the line passing through O and B is given by

Now, let us compare the coefficients of vector i, j, R

x = 2 – Î», y = -3 – 13Î», z = 4 – 17Î»

By equating to Î» we get,