RD Sharma Solutions for Class 8 Chapter 18 Practical Geometry (Constructions) Exercise 18.2

RD Sharma Class 8 Solutions Chapter 18 Ex 18.2 PDF Free Download

Exercise 18.2 mainly deals with concepts related to constructing a quadrilateral when its three sides and two diagonals are given. Students can self analyze the knowledge gained about the chapter by solving the solutions which are formulated by our expert tutors. Students aspiring to score high marks are advised to download and practice the solutions on a daily basis. RD Sharma Class 8 Solutions pdf are available here where students can download from the links provided below.

Download the Pdf of RD Sharma for Class 8 Maths Exercise 18.2 Chapter 18 Practical Geometry (Constructions)

 

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rd sharma class 8 maths chapter 18 ex 2
rd sharma class 8 maths chapter 18 ex 2
rd sharma class 8 maths chapter 18 ex 2

 

Access answers to RD Sharma Maths Solutions For Class 8 Exercise 18.2 Chapter 18 Practical Geometry (Constructions)

1. Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.0 cm, AD = 2.3 cm, AC = 4.5 cm and BD = 3.8 cm.

Solution:

The given details are AB = 3.8 cm, BC = 3.0 cm, AD = 2.3 cm, AC = 4.5 cm and BD = 3.8 cm.

Steps to construct a quadrilateral:

Step 1- Draw a line AC = 6cm.

Step 2- Cut an arc of radius 3.8cm with A as the center to mark that point as B.

Step 3- Cut an arc of radius 3cm with C as the center to intersect with point B.

Step 4- Cut an arc of radius 3.8cm with B as the center to mark that point as D.

Step 5- Cut an arc of radius 2.3cm with A as the center to intersect with point D.

Step 6- Now join AB, BD, AD and DC

RD Sharma Solutions for Class 8 Maths Chapter 18 – Practical Geometry (Constructions) image - 8

2. Construct a quadrilateral ABCD in which BC = 7.5 cm, AC = AD = 6 cm, CD = 5 cm and BD = 10 cm.

Solution:

The given details are BC = 7.5 cm, AC = AD = 6 cm, CD = 5 cm and BD = 10 cm.

Steps to construct a quadrilateral:

Step 1- Draw a line AC = 6cm.

Step 2- Cut an arc of radius 6cm with A as the center to mark that point as D.

Step 3- Cut an arc of radius 5cm with C as the center to intersect at point D.

Step 4- Cut an arc of radius 10cm with D as the center to mark that point as B.

Step 5- Cut an arc of radius 7.5cm with C as the center to intersect at point B.

Step 6- Now join AD, CD, DB and AB

RD Sharma Solutions for Class 8 Maths Chapter 18 – Practical Geometry (Constructions) image - 9

3. Construct a quadrilateral ABCD when AB = 3 cm, CD = 3 cm, DA = 7.5 cm, AC = 8 cm and BD = 4 cm.

Solution:

The given details are AB = 3 cm, CD = 3 cm, DA = 7.5 cm, AC = 8 cm and BD = 4 cm.

Consider a triangle ABD from the given data,

So, AB + BD = 3+4 = 7cm

We know that sum of lengths of two sides of a triangle is always greater than the third side.

∴ The construction is not possible.

4. Construct a quadrilateral ABCD given AD = 3.5 cm, BC = 2.5 cm, CD = 4.1 cm, AC = 7.3 cm and BD = 3.2 cm.

Solution:

The given details are AD = 3.5 cm, BC = 2.5 cm, CD = 4.1 cm, AC = 7.3 cm and BD = 3.2 cm.

Steps to construct a quadrilateral:

Step 1- Draw a line CD = 4.1cm

Step 2- Cut an arc of radius 7.3cm with C as the center to mark that point as A.

Step 3- Cut an arc of radius 3.5cm with D as the center to intersect at point A.

Step 4- Cut an arc of radius 3.2cm with D as the center to mark that point as B.

Step 5- Cut an arc of radius 2.5cm with C as the center to intersect at point B.

Step 6- Now join CA, DA, DB, CB and AB

RD Sharma Solutions for Class 8 Maths Chapter 18 – Practical Geometry (Constructions) image - 10

5. Construct a quadrilateral ABCD given AD = 5 cm, AB = 5.5 cm, BC = 2.5 cm, AC = 7.1 cm and BD = 8 cm.

Solution:

The given details are AD = 5 cm, AB = 5.5 cm, BC = 2.5 cm, AC = 7.1 cm and BD = 8 cm.

Steps to construct a quadrilateral:

Step 1- Draw a line AB = 5.5cm

Step 2- Cut an arc of radius 2.5cm with B as the center to mark that point as C.

Step 3- Cut an arc of radius 7.1cm with A as the center to intersect at point C.

Step 4- Cut an arc of radius 8cm with B as the center to mark that point as D.

Step 5- Cut an arc of radius 5cm with A as the center to intersect at point D.

Step 6- Now join BC, AC, BD, AD and CD

RD Sharma Solutions for Class 8 Maths Chapter 18 – Practical Geometry (Constructions) image - 11

6. Construct a quadrilateral ABCD in which BC = 4 cm, CA = 5.6 cm, AD = 4.5 cm, CD = 5 cm and BD = 6.5 cm.

Solution:

The given details are BC = 4 cm, CA = 5.6 cm, AD = 4.5 cm, CD = 5 cm and BD = 6.5 cm.

Steps to construct a quadrilateral:

Step 1- Draw a line BC = 4cm

Step 2- Cut an arc of radius 6.5cm with B as the center to mark that point as D.

Step 3- Cut an arc of radius 5cm with C as the center to intersect at point D.

Step 4- Cut an arc of radius 5.6cm with C as the center to mark that point as A.

Step 5- Cut an arc of radius 4.5cm with D as the center to intersect at point A.

Step 6- Now join BD, CD, CA, DA and AB

RD Sharma Solutions for Class 8 Maths Chapter 18 – Practical Geometry (Constructions) image - 12


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