RD Sharma Solutions for Class 9 Chapter 20 Surface Area and Volume of a Right Circular Cone VSAQS Exercise will help students understand the chapter in a much better way. After practising RD Sharma solutions, students will be able to easily solve any complex question based on the right circular cone. These solutions will also help students understand the concepts in depth and develop a strong base for further studies. Students can get their Exercise VSAQs copy by clicking on the link below.
RD Sharma Solutions for Class 9 Maths Chapter 20 Surface Area and Volume of a Right Circular Cone Exercise VSAQs
Access Answers to RD Sharma Solutions for Class 9 Maths Chapter 20 Surface Area and Volume of a Right Circular Cone Exercise VSAQs Page Number 20.23
Question 1: The height of a cone is 15 cm. If its volume is 500π cm3, then find the radius of its base.
Solution:
Height of a cone = 15 cm
Volume of cone = 500 π cm3
We know, the volume of a cone = 1/3 πr2h
So, 500π = 1/3 π r2 x 15
r2 = 100
or r = 10
The radius of the base is 10 cm.
Question 2: If the volume of a right circular cone of height 9 cm is 48π cm3, find the diameter of its base.
Solution:
Height of a cone = 9 cm
Volume of cone = 48 π cm3
We know, the volume of a cone = 1/3 πr2h
So, 48π = 1/3 π r2 x 9
r2 = 16
or r = 4
The radius of base r = 4 cm
Therefore, Diameter = 2 Radius = 2 x 4 cm = 8 cm.
Question 3: If the height and slant height of a cone are 21 cm and 28 cm, respectively, find its volume.
Solution:
Height of cone (h) = 21 cm
The slant height of cone (l) = 28 cm
Find the radius of the cone:
We know, l2 = r2 + h2
282 = r2 + 212
or r = 7√7 cm
Now,
We know, the volume of a cone = 1/3 πr2h
= 1/3 x π x (7√7 )2 x 21
= 2401 π
Therefore, the volume of the cone is 2401 π cm3.
Question 4: The height of a conical vessel is 3.5 cm. If its capacity is 3.3 litres of milk. Find the diameter of its base.
Solution:
Height of a conical vessel = 3.5 cm and
The capacity of the conical vessel is 3.3 litres or 3300 cm3
Now,
We know, the volume of a cone = 1/3 πr2h
3300 = 1/3 x 22/7 x r2 x 3.5
or r2 = 900
or r = 30
So, the radius of the cone is 30 cm
Hence, the diameter of its base = 2 Radius = 2×30 cm = 60 cm.
RD Sharma Solutions for Class 9 Maths Chapter 20 Surface Area and Volume of a Right Circular Cone Exercise VSAQs
RD Sharma Solutions Class 9 Maths Chapter 20 Surface Area and Volume of a Right Circular Cone Exercise VSAQs are based on the topic – Volume and Surface Area of a Right Circular Cone. In this exercise, students will practise problems on the volume and surface area of a right circular cone. The formulae of the volume and surface area of a right circular cone are very useful in everyday life since we come across conical figures at almost every step.
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