RD Sharma Solutions for Class 11 Chapter 32 - Statistics Exercise 32.2

Here in this exercise, we shall discuss the mean deviation of a discrete frequency distribution, along with an algorithm to calculate the mean deviation. Students who find difficulty in solving maths problems can follow the solutions prepared by the experts, who have formulated the solutions in the simplest way, for any student to understand easily. The main aim of preparing solutions is to help students solve textbook problems without any difficulty. Students who are not able to clear doubts during class hours can clear them by referring to the RD Sharma Class 11 Maths Solutions. Students can effortlessly download the solutions PDF, from the links given below.

RD Sharma Solutions for Class 11 Maths Exercise 32.2 Chapter 32 – Statistics

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Access answers to RD Sharma Solutions for Class 11 Maths Exercise 32.2 Chapter 32 – Statistics

EXERCISE 32.2 PAGE NO: 32.11

1. Calculate the mean deviation from the median of the following frequency distribution:

Solution:

To find the mean deviation from the median, firstly, let us calculate the median.

We know, Median is the Middle term,

So, Median = 61

Let x_i =Heights in inches

And, f_i = Number of students

N=197

= 1/197 × 336

= 1.70

∴ The mean deviation is 1.70.

2. The number of telephone calls received at an exchange in 245 successive on2-minute intervals is shown in the following frequency distribution:

Compute the mean deviation about the median.

Solution:

To find the mean deviation from the median, firstly, let us calculate the median.

We know, Median is the even term, (3+5)/2 = 4

So, Median = 8

Let x_i =Number of calls

And, f_i = Frequency

N = 245

= 1/245 × 336

= 1.49

∴ The mean deviation is 1.49.

3. Calculate the mean deviation about the median of the following frequency distribution:

Solution:

To find the mean deviation from the median, firstly, let us calculate the median.

We know N = 50

Median = (50)/2 = 25

So, the median Corresponding to 25 is 13

N = 50

= 1/50 × 136

= 2.72

∴ The mean deviation is 2.72.

4. Find the mean deviation from the mean for the following data:

(i)

Solution:

To find the mean deviation from the mean, firstly, let us calculate the mean.

By using the formula,

= 234/26

= 9

= 88/26

= 3.3

∴ The mean deviation is 3.3

(ii)

Solution:

To find the mean deviation from the mean, firstly, let us calculate the mean.

By using the formula,

= 350/25

= 14

= 158/25

= 6.32

∴ The mean deviation is 6.32

(iii)

Solution:

To find the mean deviation from the mean, firstly, let us calculate the mean.

By using the formula,

= 4000/80

= 50

= 1280/80

= 16

∴ The mean deviation is 16

5. Find the mean deviation from the median for the following data :

(i)

Solution:

To find the mean deviation from the median, firstly, let us calculate the median.

We know N = 21

Median = (21)/2 = 10.5

So, the median Corresponding to 10.5 is 27

N = 21

= 1/21 × 108

= 5.14

∴ The mean deviation is 5.14

(ii)

Solution:

To find the mean deviation from the median, firstly, let us calculate the median.

We know N = 50

Median = (50)/2 = 25

So, the median Corresponding to 25 is 74

N = 50

= 1/50 × 625

= 12.5

∴ The mean deviation is 12.5

(iii)

Solution:

To find the mean deviation from the median, firstly, let us calculate the median.

We know N = 20

Median = (20)/2 = 10

So, the median Corresponding to 10 is 12

N = 20

= 1/20 × 25

= 1.25

∴ The mean deviation is 1.25