RD Sharma Solutions for Class 9 Mathematics Chapter 1 Exercise 1.6 Number System are provided here. Exercise 1.6 is about the visualisation of the representation of real numbers by using the process of successive magnification. The RD Sharma Solutions Class 9 Maths Chapter 1 is designed by subject experts in accordance with the latest CBSE syllabus for the 9th standard. This study material contains solved questions to Exercise 1.6 in the RD Sharma Class 9 textbook. Click on the link to download the free PDF of Chapter 1, Exercise 1.6 solutions.
RD Sharma Solutions for Class 9 Maths Chapter 1 Number System Exercise 1.6
Access Answers to RD Sharma Solutions for Class 9 Maths Chapter 1 Number System Exercise 1.6 Page Number 1.39
Question 1: Visualise 2.665 on the number line using successive magnification.
Solution:
2.665 lies between 2 and 3 on the number line.
Divide the selected segment into 10 equal parts and mark each point of division as 2.1, 2.2, ….,2.9, 2.10
2.665 lies between 2.6 and 2.7
Divide the line segment between 2.6 and 2.7 into 10 equal parts, such as 2.661, 2.662, and so on.
Here we can see that the 5th point will represent 2.665.
Question 2: Visualise the representation of 5.37̅ on the number line up to 5 decimal places, that is up to 5.37777.
Solution:
Clearly, 5.37̅ is located between 5 and 6.
Again by successive magnification, and successively decrease 5.37̅ located between 5.3 and 5.4.
For more clarity, divide the 5.3 and 5.4 portions of the number line into 10 equal parts, and we can see 5.37̅ lies between 5.37 and 5.38.
To visualize 5.37̅ more accurately, divide the line segment between 5.37 and 5.38 into ten equal parts.
5.37̅ lies between 5.377 and 5.378.
Again divide the above portion between 5.377 and 5.378 into 10 equal parts, which shows 5.37̅ is located closer to 5.3778 than to 5.3777
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