Exercise 17.2 of RD Sharma textbook solutions are given here. This exercise is based on construction of the bisector of a given angle. The questions are also according to the syllabus and guidelines of CCE and Central Board of Secondary Education. Exercise 17.2 of RD Sharma Class 9 Chapter 17 helps students to learn how to construct different angles with the help of ruler and compass only. Click on the link below to get your pdf now.
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Question 1: Draw an angle and label it as ∠BAC. Construct another angle, equal to ∠BAC.
Solution:
Steps of construction:
Step 1: Draw any angle ABC.
Now will construct an angle equal to ∠BAC
Step 2: Draw a line segment QR.
Step 3: Draw an arc which intersects ∠BAC at E and D using A as center and choose any radius.
Step 4: With same measurements (set in step 2), Draw an arc from point Q.
Step 5: With S as center and radius equal to DE, draw an arc which intersects the previous arc at T.
Step 6: Join Q and T.
Therefore ∠PQR= ∠BAC
Question 2: Draw an obtuse angle. Bisect it. Measure each of the angles so formed.
Solution:
Steps of construction:
Step 1: Draw an obtuse angle. We choose ∠ABC = 1200.
Step 2: Draw an arc which intersects AB at P and BC at Q, from center B and choose any radius.
Step 3: Draw an arc from point P by setting radius more than half of PQ.
Step 4: Repeat step 3 using Q as center and cut the previous arc at R.
Step 5: Join BR.
Therefore ∠ABR= ∠RBC = 600
Question 3: Using your protractor, draw an angle of 1080. With this given angle as given, draw an angle of 540.
Solution:
Steps of construction:
Step 1: Draw ∠ABC = 1080.
Step 2: Draw an arc which intersects AB at P and BC at Q from point B. (Choose any radius)
Step 3: Draw an arc from point P by setting radius more than half of PQ.
Step 4: Repeat Step 3 using Q as the centre and intersect the previous arc at R.
Step 5: Join BR.
Therefore ∠RBC = 540
Question 4: Using the protractor, draw a right angle. Bisect it to get an angle of measure 450.
Solution:
Steps of construction:
Step 1: Draw ∠ABC = 900.
Step 2: Draw an arc which intersects AB at P and BC at Q from point B. (Choose any radius)
Step 3: Draw an arc from point P by setting radius more than half of PQ.
Step 4: Repeat step 3 using Q as a centre and intersect the previous arc at R.
Step 5: Join RB.
Therefore ∠RBC= 450
RD Sharma Solutions for Class 9 Maths Chapter 17 Construction Exercise 17.2
RD Sharma Solutions Class 9 Maths Chapter 17 Construction Exercise 17.2 is based on the following topics:
- Construction of the Bisector of a Given Angle
- Construction of some Standard Angles – 300, 600, 900, 450 and 1200
In this exercise, students will learn how to construct angles of 300, 600, 900, 450 and 1200 with the help of ruler and compass only.