RD Sharma Solutions for Class 9 Maths Chapter 17 Construction Exercise 17.2

RD Sharma Class 9 Solutions Chapter 17 Ex 17.2 Free Download

Exercise 17.2 of RD Sharma textbook solutions are given here. This exercise is based on construction of the bisector of a given angle. The questions are also according to the syllabus and guidelines of CCE and Central Board of Secondary Education. Exercise 17.2 of RD Sharma Chapter 17 helps students to learn how to construct different angles with the help of ruler and compass only. Click on the link below to get your pdf now.

Download PDF of RD Sharma Solutions for Class 9 Maths Chapter 17 Construction Exercise 17.2

 

rd sharma class 9 maths chapter 17
rd sharma class 9 maths chapter 17
rd sharma class 9 maths chapter 17

 

Access Answers to Maths RD Sharma Class 9 Chapter 17 Construction Exercise 17.2 Page number 17.7

Question 1: Draw an angle and label it as ∠BAC. Construct another angle, equal to ∠BAC.

Solution:

Steps of construction:

Step 1: Draw any angle ABC.

Now will construct an angle equal to ∠BAC

Step 2: Draw a line segment QR.

Step 3: Draw an arc which intersects ∠BAC at E and D using A as center and choose any radius.

Step 4: With same measurements (set in step 2), Draw an arc from point Q.

Step 5: With S as center and radius equal to DE, draw an arc which intersects the previous arc at T.

Step 6: Join Q and T.

RD sharma class 9 maths chapter 17 ex 17.2 solution 1

Therefore ∠PQR= ∠BAC

Question 2: Draw an obtuse angle. Bisect it. Measure each of the angles so formed.

Solution:

Steps of construction:

Step 1: Draw an obtuse angle. We choose ∠ABC = 1200.

Step 2: Draw an arc which intersects AB at P and BC at Q, from center B and choose any radius.

Step 3: Draw an arc from point P by setting radius more than half of PQ.

Step 4: Repeat step 3 using Q as center and cut the previous arc at R.

Step 5: Join BR.

RD sharma class 9 maths chapter 17 ex 17.2 solution 2

Therefore ∠ABR= ∠RBC = 600

Question 3: Using your protractor, draw an angle of 1080. With this given angle as given, draw an angle of 540.

Solution:

Steps of construction:

Step 1: Draw ∠ABC = 1080.

Step 2: Draw an arc which intersects AB at P and BC at Q from point B. (Choose any radius)

Step 3: Draw an arc from point P by setting radius more than half of PQ.

Step 4: Repeat Step 3 using Q as the centre and intersect the previous arc at R.

Step 5: Join BR.

Therefore ∠RBC = 540

RD sharma class 9 maths chapter 17 ex 17.2 solution 3

Question 4: Using the protractor, draw a right angle. Bisect it to get an angle of measure 450.

Solution:

Steps of construction:

Step 1: Draw ∠ABC = 900.

Step 2: Draw an arc which intersects AB at P and BC at Q from point B. (Choose any radius)

Step 3: Draw an arc from point P by setting radius more than half of PQ.

Step 4: Repeat step 3 using Q as a centre and intersect the previous arc at R.

Step 5: Join RB.

Therefore ∠RBC= 450

RD sharma class 9 maths chapter 17 ex 17.2 solution 4


Access other exercise solutions of Class 9 Maths Chapter 17 Construction

Exercise 17.1 Solutions

Exercise 17.3 Solutions

RD Sharma Solutions for Class 9 Maths Chapter 17 Exercise 17.2

Class 9 Maths Chapter 17 Construction Exercise 17.2 is based on the following topics:

  • Construction of the Bisector of a Given Angle
  • Construction of some Standard Angles – 300, 600, 900, 450 and 1200

In this exercise, students will learn how to construct angles of 300, 600, 900, 450 and 1200 with the help of ruler and compass only.

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