RD Sharma Solutions for Class 9 Maths Chapter 3 Rationalisation Exercise VSAQs

RD Sharma class 9 mathematics chapter 3 exercise VSAQs Rationalisation is provided here. Our experts have designed RD Sharma Class 9 chapter 3 solutions in accordance with CBSE syllabus for class 9. Learning this chapter will also help the students to score good marks in the examination. Students can download RD Sharma exercise VSAQs by clicking on the link below.

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RD Sharma Solution class 9 Maths Chapter 3 Rationalisation 14
RD Sharma Solution class 9 Maths Chapter 3 Rationalisation 15
RD Sharma Solution class 9 Maths Chapter 3 Rationalisation 16
RD Sharma Solution class 9 Maths Chapter 3 Rationalisation 17

Access Answers to Maths RD Sharma Class 9 Chapter 3 Rationalisation Exercise VSAQs

Question 1: Write the value of (2 + √3) (2 – √3).

Solution:

(2 + √3) (2 – √3)

= (2)2 – (√3)2

[Using identity : (a + b)(a – b) = a2 – b2]

= 4 – 3

= 1

Question 2: Write the reciprocal of 5 + √2.

Solution:

rd sharma class 9 maths chapter 3 Short answers question 2

Question 3: Write the rationalisation factor of 7 – 3√5.

Solution:

Rationalisation factor of 7 – 3√5 is 7 + 3√5

Question 4: If

rd sharma class 9 maths chapter 3 Short answers question 4

Find the values of x and y.

Solution:

[Using identities : (a + b)(a – b) = a2 – b2 and (a – b)2 = a2 + b2 – 2ab]

rd sharma class 9 maths chapter 3 Short answers question 4 solution

Question 5: If x = √2 – 1, then write the value of 1/x.

Solution:

x = √2 – 1

or 1/x = 1/(√2 – 1)

Rationalising denominator, we have

= 1/(√2 – 1) x (√2 + 1)/(√2 + 1)

= (√2 + 1)/(2-1)

= √2 + 1

Question 6: Simplify

rd sharma class 9 maths chapter 3 Short answers question 6

Solution:

rd sharma class 9 maths chapter 3 Short answers question 6 solution

[ Because: (a + b)2 = a2 + b2 + 2ab ]

Question 7: Simplify

rd sharma class 9 maths chapter 3 Short answers question 7

Solution:

rd sharma class 9 maths chapter 3 Short answers question 7 solution

[ Because: (a – b)2 = a2 + b2 – 2ab ]

Question 8: If a = √2 +1, then find the value of a – 1/a.

Solution:

Given: a = √2 + 1

1/a = 1/(√2 + 1)

= 1/(√2 + 1) x (√2 – 1)/(√2 – 1)

= (√2 – 1)/ ((√2)2 – (1)2)

= (√2 – 1)/1

= √2 – 1

Now,

a – 1/a = (√2 + 1) – (√2 – 1)

= 2

Question 9: If x = 2 + √3, find the value of x + 1/x.

Solution:

Given: x = 2 + √3

1/a = 1/(2 + √3)

= 1/(2 + √3) x (2 – √3)/(2 – √3)

= (2 – √3)/ ((2)2 – (√3)2)

= (2 – √3)/(4-3)

= (2 – √3)

Now,

x + 1/x = (2 + √3) + (2 – √3)

= 4

Question 10: Write the rationalisation factor of √5 – 2.

Solution:

Rationalisation factor of √5 – 2 is √5 + 2

Question 11: If x = 3 + 2√2, then find the value of √x – 1/√x.

Solution:

rd sharma class 9 maths chapter 3 Short answers question 11 solution

RD Sharma Solutions for Class 9 Maths Chapter 3 Exercise VSAQs

RD Sharma Solutions Class 9 Maths Chapter 3 Rationalisation Exercise VSAQs is based on the following topics:

  • Use of some important algebraic identities
  • Rationalisation of denominator

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