NCERT exemplar class 11 physics Chapter 8 Gravitation is the foremost learning material that is very much essential for the students of CBSE class and for them who are preparing for engineering and medical entrance examinations. This NCERT exemplar class 11 physics Chapter 8 pdf has class 11 gravitation questions from NCERT exemplar books in addition to gravitation class 11 important derivations, solved numericalâ€™s on gravitation, MCQâ€™S, worksheets, HOTS and exercises. Gravitation is simply a phenomenon that occurs in nature, where things with energy or mass are attracted to each other. These may be planets, stars and even galaxies. This force of attraction that exists between two objects causes them to gravitate towards each other. Albert Einstein initially proposed the general theory of relativity which described gravity in the most accurate way.
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Multiple Choice Questions I
8.1. The earth is an approximate sphere. If the interior contained matter which is not of the same density everywhere, then on the surface of the earth, the acceleration due to gravity
a) will be directed towards the centre but not the same everywhere
b) will have the same value everywhere but not directed towards the centre
c) will be same everywhere in magnitude directed towards the centre
d) cannot be zero at any point
Answer:
The correct answer is d) cannot be zero at any point
8.2. As observed from earth, the sun appears to move in an approximate circular orbit. For the motion of another planet like mercury as observed from earth, this would
a) be similarly true
b) not be true because the force between earth and mercury is not inverse square law
c) not be true because the major gravitational force on mercury is due to sun
d) not be true because mercury is influenced by forces other than gravitational forces
Answer:
The correct answer is c) not be true because the major gravitational force on mercury is due to sun
8.3. Different points in earth are at slightly different distances from the sun and hence experience different forces due to gravitation. For a rigid body, we know that if various forces act at various points in it, the resultant motion is as if a net force acts on the cm causing translation and a net torque at the cm causing translation and a net torque at the cm causing rotation around an axis through the cm. For the earth-sun system
a) the torque is zero
b) the torque causes the earth to spin
c) the rigid body result is not applicable since the earth is not even approximately a rigid body
d) the torque causes the earth to move around the sun
Answer:
The correct answer is a) the torque is zero
8.4. Satellites orbiting the earth have finite life and sometimes debris of satellites fall to the earth. This is because
a) the solar cells and batteries in satellites run out
b) the laws of gravitation predict a trajectory spiralling inwards
c) of viscous forces causing the speed of satellite and hence height to gradually decrease
d) of collisions with other satellites
Answer:
The correct answer is c) of viscous forces causing the speed of satellite and hence height to gradually decrease
8.5. Both earth and moon are subject to the gravitational force of the sun. as observed from the sun, the orbit of the moon
a) will be elliptical
b) will not be strictly elliptical because the total gravitational force on it is not central
c) is not elliptical but will necessarily be a closed curve
d) deviates considerably from being elliptical due to influence of planets other than earth
Answer:
The correct answer is b) will not be strictly elliptical because the total gravitational force on it is not central
8.6. In our solar system, the inter-planetary region has chunks of matter called asteroids. They
a) will not move around the sun since they have very small masses compared to sun
b) will move in an irregular way because of their small masses and will drift away outer space
c) will move around the sun in closed orbits but not obey Keplerâ€™s laws
d) will move in orbits like planets and obey Keplerâ€™s laws
Answer:
The correct answer is d) will move in orbits like planets and obey Keplerâ€™s laws
8.7. Choose the wrong option.
a) inertial mass is a measure of difficulty of accelerating a body by an external force whereas the gravitational mass is relevant in determining the gravitational force on it by an external mass
b) that the gravitational mass and inertial mass are equal is an experimental result
c) that the acceleration due to gravity on earth is the same for all bodies is due to the equality of gravitational mass and inertial mass
d) gravitational mass of a particle like proton can depend on the presence of neighbouring heavy objects but the inertial mass cannot
Answer:
The correct answer is d) gravitational mass of a particle like proton can depend on the presence of neighbouring heavy objects but the inertial mass cannot
8.8. Particles of masses 2M, m and M are respectively at points A, B, and C with AB = 1/2 (BC). M is much-much smaller than M and at time t = 0, they are all at rest. At subsequent times before any collision takes place
a) m will remain at rest
b) m will move towards M
c) m will move towards 2M
d) m will have oscillatory motion
Answer:
The correct answer is c) m will move towards 2M
Multiple Choice Questions II
8.9. Which of the following options are correct?
a) acceleration due to gravity decreases with increasing altitude
b) acceleration due to gravity increases with increasing depth
c) acceleration due to gravity increases with increasing latitude
d) acceleration due to gravity is independent of the mass of the earth
Answer:
The correct answer is
a) acceleration due to gravity decreases with increasing altitude
c) acceleration due to gravity increases with increasing latitude
8.10. If the law of gravitation, instead of being inverse-square law, becomes an inverse-cube-law
a) planets will not have elliptic orbits
b) circular orbits of planets is not possible
c) projectile motion of a stone thrown by hand on the surface of the earth will be approximately parabolic
d) there will be no gravitational force inside a spherical shell of uniform density
Answer:
The correct answer is
a) planets will not have elliptic orbits
b) circular orbits of planets is not possible
c) projectile motion of a stone thrown by hand on the surface of the earth will be approximately parabolic
8.11. If the mass of sun were ten times smaller and gravitational constant G were ten times larger in magnitudes
a) walking on ground would become more difficult
b) the acceleration due to gravity on earth will not change
c) raindrops will fall much faster
d) airplanes will have to travel much faster
Answer:
The correct answer is
a) walking on ground would become more difficult
c) raindrops will fall much faster
d) airplanes will have to travel much faster
8.12. If the sun and the planets carried huge amounts of opposite charges,
a) all three of Keplerâ€™s laws would still be valid
b) only the third law will be valid
c) the second law will not change
d) the first law will still be valid
Answer:
The correct answer is
a) all three of Keplerâ€™s laws would still be valid
c) the second law will not change
d) the first law will still be valid
8.13. There have been suggestions that the value of the gravitational constant G becomes smaller when considered over very large time period in the future. If that happens for our earth,
a) nothing will change
b) we will become hotter after billions of years
c) we will be going around but not strictly in closed orbits
d) after sufficiently long time we will leave the solar system
Answer:
The correct answer is
c) we will be going around but not strictly in closed orbits
d) after sufficiently long time we will leave the solar system
8.14. Supposing Newtonâ€™s law of gravitation for gravitation forces F1 and F2 between two masses m1 and m2 at positions r1 and r2 read
where Mo is a constant of dimension of mass, r12 = r1 â€“ r2 and n is a number. In such a case,
a) the acceleration due to gravity on earth will be different for different object
b) none of the three laws of Kepler will be valid
c) only the third law will become invalid
d) for n negative, an object lighter than water will sink in water
Answer:
The correct answer is
a) the acceleration due to gravity on earth will be different for different object
c) only the third law will become invalid
d) for n negative, an object lighter than water will sink in water
8.15. Which of the following are true?
a) a polar satellite goes around the earthâ€™s pole in north-south direction
b) a geostationary satellite goes around the earth in east-west direction
c) a geostationary satellite goes around the earth in west-east direction
d) a polar satellite goes around the earth in east-west direction
Answer:
The correct answer is
a) a polar satellite goes around the earthâ€™s pole in north-south direction
c) a geostationary satellite goes around the earth in west-east direction
8.16. The centre of mass of an extended body on the surface of the earth and its centre of gravity
a) are always at the same point for any size of the body
b) are always at the same point only for spherical bodies
c) can never be at the same point
d) is close to each other for objects, say of sizes less than 100 m
e) both can change if the object is taken deep inside the earth
Answer:
The correct answer is d) is close to each other for objects, say of sizes less than 100 m
Very Short Answers
8.17. Molecules in air in the atmosphere are attracted by gravitational force of the earth. Explain why all of them do not fall into the earth just like an apple falling from a tree.
Answer:
Molecules in air in the atmosphere are attracted by gravitational force of the earth but they do not fall into the earth because they are in random motion whereas apple has a downward motion.
8.18. Give one example each of central force and non-central force.
Answer:
Central force: Electrostatic force acting on the point charge
Non-central force: Nuclear force between the atoms
8.19. Draw areal velocity versus time graph for mars.
Answer:
According to Keplerâ€™s law, the areal velocity of mars around the sun does not change when it is revolving around the sun. therefore, the graph of areal velocity versus time is a straight line.
8.20. What is the direction of areal velocity of the earth around the sun?
Answer:
The direction of areal velocity of the earth around the sun is in the direction of product of r and v.
8.21. How is the gravitational force between two point masses affected when they are dipped in water keeping the separation between them the same?
Answer:
The gravitational force is unaffected by the medium and it remains the same between the point masses irrespective of their surrounding. Therefore, when the two point masses are dipped in water the gravitational force between them remains the same.
8.22. Is it possible for a body to have inertia but no weight?
Answer:
Yes, it is possible for a body to have inertia but no weight as inertia is associated with the mass of the body. Satellite revolving around the earth is example of a body with inertia and has no weight.
8.23. We can shield a charge from electric fields by putting it side a hollow conductor. Can we shield a body from the gravitational influence of nearby matter by putting it inside a hollow sphere or by some other means?
Answer:
No, it is possible to shield a body from the gravitational influence of nearby matter by putting it inside a hollow sphere as gravitation is independent of the medium.
8.24. An astronaut inside a small spaceship orbiting around the earth cannot detect gravity. If the space station orbiting around the earth has a large size, can he hope to detect gravity?
Answer:
When the size of the space station orbiting around the earth is large, astronaut will experience variation and this is because of acceleration due to gravity.
8.25. The gravitational force between a hollow spherical shell and a point mass is F. Show the nature of F vs r graph where r is the distance of the point from the centre of the hollow spherical shell of uniform density.
Answer:
R is the radius of the spherical shell and r is the distance between m and M. M is the mass of the hollow spherical shell and m is the mass of the point. We know that,
F = GMm/r^{2}
When the F = 0, F = GM/r^{2} for r â‰¥ R
Below is the graph which shows the variation of F versus r such that when force is maximum, r tends to infinity.
8.26. Out of aphelion and perihelion, where is the speed of the earth more and why?
Answer:
According to Keplerâ€™s second law, a real velocity is constant and is given as:
r_{p} Ã— v_{p} = r_{A} Ã— v_{A}
r_{A}/r_{p} = v_{p}/v_{A}
r_{A} > r_{p} and v_{p} > v_{A}
8.27. What is the angle between the equatorial plane and the orbital plane of
a) polar satellite?
b) geostationary satellite?
Answer:
a) The angle between the equatorial plane and the orbital plane of polar satellite is 90^{o}
b) The angle between the equatorial plane and the orbital plane of geostationary satellite is 0^{o}
Short Answer
8.28. Mean solar day is the time interval between two successive noon when sun passes through zenith point. Sidereal day is the time interval between two successive transits of a distant star through the zenith point. By drawing appropriate diagram showing earthâ€™s spin and orbital motion, show that mean solar day is four minutes longer than the sidereal day. In other words, distant stars would rise 4 minutes early every successive day.
Answer:
E and Eâ€™ is the polar axis of the earth and its movement.
Pâ€™ is the translational motion
In every 24 hours, the orbit of the earth is approximately advanced by 1^{o}
Therefore, time taken for transverse is = (24/360^{o}) (1^{o}) = 239.3 sec = 4 minutes.
8.29. Two identical heavy spheres are separated by a distance 10 times their radius. Will an object placed at the mid point of the line joining their centres be in stable equilibrium or unstable equilibrium? Give reason for your answer.
Answer:
M is the mass of the spheres and R is the radius of the spheres.
P is the mid point of A and B.
The magnitude of the force is given as:
F1 = F2 = GMm/(5R)^{2}
The equilibrium will be unstable as the resultant force acting on the object moves towards sphere A.
8.30. Show the nature of the following graph for a satellite orbiting the earth.
a) KE vs orbital radius R
b) PE vs orbital radius R
c) TE vs orbital radius R
Answer:
a) K = 1/2mv^{2} = (1/2 m)(GM/R)
b) PE of satellite is U = -GMm/R = -2K
c) Total energy of the satellite = -GMm/2R
8.31. Shown are several curves. Explain with reason, which ones amongst them can be possible trajectories traced by a projectile
Answer:
The given options, option (c) show the focus of trajectory.
8.32. An object of mass m is raised from the surface of the earth to a height equal to the radius of the earth, that is, taken from a distance R to 2R from the centre of the earth. What is the gain in its potential energy?
Answer:
The PE of the body on the earth = -GMm/R
When the body is close to the equator, the PE = -GMm/2R
Gain in PE = 1/2 mgR
8.33. A mass m is placed at P a distance h along the normal through the centre O of a thin circular ring of mass M and radius r. If the mass is removed further away such that OP becomes 2h, by what factor the force of gravitation will decrease, if h = r?
Answer:
Let r be the radius of the ring and m be the mass of the ring. Small element dM is considered as the mass, the gravitation force dF = G(dM)m/x^{2}
Where x^{2} = r^{2} + h^{2}
When the force is integrated, the distance between the m and the ring is 2h.
Long Answers
8.34. A star like the sun has several bodies moving around it at different distances. Consider that all of them are moving in circular orbits. Let r be the distance of the body from the centre of the star and let its linear velocity be v, angular velocity Ï‰, kinetic energy K, gravitational potential energy U, total energy E, and angular momentum l. As the radius r of the orbit increases, determine which of the above quantities increase and which ones decrease.
Answer:
8.35. Six point masses of mass m each are at the vertices of a regular hexagon of side l. Calculate the force on any of the masses.
Answer:
AE = AG + EG = AG + AG = 2AG = 2l cos 30^{o}
AE = AC = âˆš3l
AD = 2l
Therefore,
Force on A due to B is Gm^{2}/l^{2} along B to A
Force on A due to C is Gm^{2}/3l^{2} along D to A
Force on A due to D is Gm^{2}/4l^{2} along D to A
Force on A due to E is Gm^{2}/3l^{2} along E to A
Therefore, total force = F = Gm^{2}/l^{2} (1 + 1/âˆš3 + 1/4) along DA
8.36. A satellite is to be placed in equatorial geostationary orbit around earth for communication
a) calculate height of such a satellite
b) find out the minimum number of satellites that are needed to cover entire earth so that at least one satellites is visible from any point on the equator
Answer:
a) Mass of the earth, M = 6 1024 kg
Radius of the earth, R = 6.4 103 m
Time period = 24 36 102 s
G = 6.67 10-11 N.m2/kg2
Orbital radius = R + h
Using orbital velocity, we can calculate h = 35,940 km
b) The no.of satellites that are needed to cover entire earth so that at least one satellite is visible from any point of the equator is 3.
8.37. Earthâ€™s orbit is an ellipse with eccentricity 0.0167. Thus, earthâ€™s distance from the sun and speed as it moves around the sun varies from day to day. This means that the length of the solar day is not constant through the year. Assume that earthâ€™s spin axis is normal to its orbital plane and find out the length of the shortest and the longest day. A day should be taken from noon to noon. Does this explain variation of the length of the day during the year?
Answer:
Velocity of the earth at perigee = vp
Velocity of the earth at apogee = va
Angular velocity of the earth at perihelion = êž·p
Angular velocity of the earth at aphelion = êž·a
êž·p/êž·a = 1.0691
êž· is the mean angular speed = 1.0691
êž·p/êž· = êž·/êž·a = 1.034
Therefore, it can be said that this does not explain the actual variation of length of the day during the year.
8.38. A satellite is in an elliptic orbit around the earth with aphelion of 6R and perihelion of 2R where R = 6400 km is the radius of the earth. Find eccentrically of the orbit. Find the velocity of the satellite at apogee and perigee. What should be done if this satellite has to be transferred to a circular orbit of radius 6R?
Answer:
Radius of perigee = rp = 2R
Radius of apogee = ra = 6R
rp = 2R
ra = 6R
rp = a(1-e) = 2R
ra = a(1+e) = 6R
From the above equation, e = 1/2
Since there is no external force on the system, from law of conservation of angular momentum
L1 = L2
ma = mp = m = mass of the satellite
va/vp = rp/ra = 1/3
Therefore, vp = 3va
From conservation of energy we get
va = 2.28 km/s
vc = 3.23 km/s
The velocity at the apogee is vc â€“ va = 0.95 km/s
Important topics of Chapter 8 Gravitation
- Kepler’s laws
- The universal law of gravitation
- The gravitational constant
- Acceleration due to the gravity of the earth
- Acceleration due to gravity below and above the surface of the earth
- Gravitational potential energy
- Escape speed
- Earth satellites
- The energy of an orbiting satellite
- Geostationary and polar satellites
- Weightlessness.
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