This exercise mainly deals with problems based on types of sets, which include an empty set, singleton set, finite set, infinite set, equivalent sets and equal sets. From the exam point of view, solutions are prepared using shortcut techniques, which speed up the ability to solve problems. Students may keep the textbook aside and use RD Sharma Class 11 Solutions for revision purposes. Students can refer to and download the PDF from the links provided below.
RD Sharma Solutions for Class 11 Maths Exercise 1.3 Chapter 1 – Sets
Access answers to RD Sharma Solutions for Class 11 Maths Exercise 1.3 Chapter 1 – Sets
1. Which of the following are examples of empty set?
(i) Set of all even natural numbers divisible by 5.
(ii) Set of all even prime numbers.
(iii) {x: x2–2=0 and x is rational}.
(iv) {x: x is a natural number, x < 8 and simultaneously x > 12}.
(v) {x: x is a point common to any two parallel lines}.
Solution:
(i) All numbers ending with 0. Except 0 is divisible by 5 and are even natural number. Hence it is not an example of an empty set.
(ii) 2 is a prime number and is even, and it is the only prime which is even. So this is not an example of an empty set.
(iii) x2 – 2 = 0, x2 = 2, x = ± √2 ∈ N. There is no natural number whose square is 2. So it is an example of an empty set.
(iv) There is no natural number less than 8 and greater than 12. Hence it is an example of an empty set.
(v) No two parallel lines intersect at each other. Hence it is an example of an empty set.
2. Which of the following sets are finite and which are infinite?
(i) Set of concentric circles in a plane.
(ii) Set of letters of the English Alphabets.
(iii) {x ∈ N: x > 5}
(iv) {x ∈ N: x < 200}
(v) {x ∈ Z: x < 5}
(vi) {x ∈ R: 0 < x < 1}.
Solution:
(i) Infinite concentric circles can be drawn in a plane. Hence it is an infinite set.
(ii) There are just 26 letters in English Alphabet. Hence it is a finite set.
(iii) It is an infinite set because the number of natural numbers greater than 5 is infinite.
(iv) It is a finite set since natural numbers start from 1, and there are 199 numbers less than 200. Hence it is a finite set.
(v) It is an infinite set. Because integers less than 5 are infinite, it is an infinite set.
(vi) It is an infinite set. Because between two real numbers, there are infinite real numbers.
3. Which of the following sets are equal?
(i) A = {1, 2, 3}
(ii) B = {x ∈ R:x2–2x+1=0}
(iii) C = (1, 2, 2, 3}
(iv) D = {x ∈ R : x3 – 6x2+11x – 6 = 0}.
Solution:
A set is said to be equal with another set if all elements of both sets are equal and the same.
A = {1, 2, 3}
B ={x ∈ R: x2–2x+1=0}
x2–2x+1 = 0
(x–1)2 = 0
∴ x = 1.
B = {1}
C= {1, 2, 2, 3}
In sets, we do not repeat elements. Hence C can be written as {1, 2, 3}
D = {x ∈ R: x3 – 6x2+11x – 6 = 0}
For x = 1, x2–2x+1=0
= (1)3–6(1)2+11(1)–6
= 1–6+11–6
= 0
For x =2,
= (2)3–6(2)2+11(2)–6
= 8–24+22–6
= 0
For x =3,
= (3)3–6(3)2+11(3)–6
= 27–54+33–6
= 0
∴ D = {1, 2, 3}
Hence, sets A, C and D are equal.
4. Are the following sets equal?
A={x: x is a letter in the word reap},
B={x: x is a letter in the word paper},
C={x: x is a letter in the word rope}.
Solution:
For A
Letters in word reap
A ={R, E, A, P} = {A, E, P, R}
For B
Letters in the word paper
B = {P, A, E, R} = {A, E, P, R}
For C
Letters in word rope
C = {R, O, P, E} = {E, O, P, R}.
Set A = Set B
Because every element of set A is present in set B
But Set C is not equal to either of them because all elements are not present.
5. From the sets given below, pair the equivalent sets:
A= {1, 2, 3}, B = {t, p, q, r, s}, C = {α, β, γ}, D = {a, e, i, o, u}.
Solution:
Equivalent sets are different from equal sets; Equivalent sets are those which have an equal number of elements. They do not have to be the same.
A = {1, 2, 3}
Number of elements = 3
B = {t, p, q, r, s}
Number of elements = 5
C = {α, β, γ}
Number of elements = 3
D = {a, e, i, o, u}
Number of elements = 5
∴ Set A is equivalent to Set C.
Set B is equivalent to Set D.
6. Are the following pairs of sets equal? Give reasons.
(i) A = {2, 3}, B = {x: x is a solution of x2 + 5x + 6= 0}
(ii) A={x: x is a letter of the word “WOLF”}
B={x: x is letter of word “FOLLOW”}
Solution:
(i) A = {2, 3}
B = x2 + 5x + 6 = 0
x2 + 3x + 2x + 6 = 0
x(x+3) + 2(x+3) = 0
(x+3) (x+2) = 0
x = -2 and -3
= {–2, –3}
Since A and B do not have exactly the same elements, they are not equal.
(ii) Every letter in WOLF
A = {W, O, L, F} = {F, L, O, W}
Every letter in FOLLOW
B = {F, O, L, W} = {F, L, O, W}
Since A and B have the same number of elements which are exactly the same, they are equal sets.
7. From the sets given below, select equal sets and equivalent sets.
A = {0, a}, B = {1, 2, 3, 4}, C = {4, 8, 12},
D = {3, 1, 2, 4}, E = {1, 0}, F = {8, 4, 12},
G = {1, 5, 7, 11}, H = {a, b}
Solution:
A = {0, a}
B = {1, 2, 3, 4}
C = {4, 8, 12}
D = {3, 1, 2, 4} = {1, 2, 3, 4}
E = {1, 0}
F = {8, 4, 12} = {4, 8, 12}
G = {1, 5, 7, 11}
H = {a, b}
Equivalent sets:
i. A, E, H (all of them have exactly two elements in them)
ii. B, D, G (all of them have exactly four elements in them)
iii. C, F (all of them have exactly three elements in them)
Equal sets:
i. B, D (all of them have exactly the same elements, so they are equal)
ii. C, F (all of them have exactly the same elements, so they are equal)
8. Which of the following sets are equal?
A = {x: x ∈ N, x < 3}
B = {1, 2}, C= {3, 1}
D = {x: x ∈ N, x is odd, x < 5}
E = {1, 2, 1, 1}
F = {1, 1, 3}
Solution:
A = {1, 2}
B = {1, 2}
C = {3, 1}
D = {1, 3} (since the odd natural numbers less than 5 are 1 and 3)
E = {1, 2} (since repetition is not allowed)
F = {1, 3} (since repetition is not allowed)
∴ Sets A, B and E are equal.
C, D and F are equal.
9. Show that the set of letters needed to spell “CATARACT” and the set of letters needed to spell “TRACT” are equal.
Solution:
For “CATARACT”
Distinct letters are
{C, A, T, R} = {A, C, R, T}
For “TRACT”
Distinct letters are
{T, R, A, C} = {A, C, R, T}
As we see, the letters needed to spell cataract is equal to the set of letters needed to spell tract.
Hence the two sets are equal.
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