RD Sharma Solutions for Class 9 Chapter 24 Measure of Central Tendency Exercise 24.1 are provided here. RD Sharma Class 9 Textbook offers a much harder approach to questions of Measures of Central Tendency when compared to the other textbooks. Solving the RD Sharma textbook questions requires you to have an extensive understanding of the topic. Each question is solved by subject experts in an easy language and given step-by-step solutions for better understanding. The problems in this exercise will help students to solve the arithmetic mean of the given data. Download the PDF now and start practising.
RD Sharma Solutions for Class 9 Maths Chapter 24 Measure of Central Tendency Exercise 24.1
Access Answers to RD Sharma Solutions for Class 9 Maths Chapter 24 Measure of Central Tendency Exercise 24.1 Page Number 24.9
Question 1: If the heights of 5 persons are 140 cm, 150 cm, 152 cm, 158 cm and 161 cm, respectively, find the mean height.
Solution:
The heights of 5 persons are 140 cm, 150 cm, 152 cm, 158 cm and 161 cm (Given)
Mean height = (Sum of heights) / (Total number of persons)
Sum of heights = 140 + 150 + 152 + 158 + 161 = 761
Total number of persons = 5
So, Mean height = 761/5 =152.2
Question 2: Find the mean of 994, 996, 998, 1002 and 1000.
Solution:
Sum of numbers = 994+996+998+1000+100 = 4990
Total counts = 5
Therefore, Mean = (Sum of numbers)/(Total Counts)
= 4990/5
= 998
Mean = 998
Question 3: Find the mean of the first five natural numbers.
Solution:
The first five natural numbers are 1, 2, 3, 4, and 5.
Sum of all the numbers = 1+2+3+4+5 = 15
Total Numbers = 5
Therefore, Mean = (Sum of numbers)/(Total Numbers)
= 15/5
= 3
Mean = 3
Question 4: Find the mean of all factors of 10.
Solution:
Factors of 10 are 1, 2, 5, and 10.
Sum of all the factors = 1+2+5+10 = 18
Total Numbers = 4
Therefore, Mean = (Sum of factors)/(Total Numbers)
= 18/4
= 4.5
Mean = 4.5
Question 5: Find the mean of the first 10 even natural numbers.
Solution:
First 10 even natural numbers = 2, 4, 6, 8, 10, 12, 14, 16, 18, 20
Sum of numbers = 2+4+6+8+10+12+14+16+18+20 = 110
Total Numbers = 10
Now,
Mean = (Sum of numbers) / (Total Numbers)
= 110/10
Mean = 11
Question 6: Find the mean of x , x + 2 , x + 4 , x + 6 , x + 8.
Solution:
Given numbers are x , x + 2 , x + 4 , x + 6 , x + 8.
Sum of numbers = x+(x+2) + (x+4) + (x+6) + (x+8) = 5x+20
Total Numbers = 5
Now,
Mean = (Sum of numbers) / (Total Numbers)
= (5x+20)/5
= 5(x + 4)/5
= x + 4
Mean = x + 4
Question 7: Find the mean of the first five multiples of 3.
Solution:
The first five multiples of 3 are 3, 6, 9, 12 and 15.
Sum of numbers = 3+6+9+12+15 = 45
Total Numbers = 5
Now,
Mean = (Sum of numbers) / (Total Numbers)
= 45/5
=9
Mean = 9
Question 8: Following are the weights (in kg) of 10 newborn babies in a hospital on a particular day: 3.4, 3 .6, 4.2, 4.5, 3.9, 4.1, 3.8, 4.5, 4.4, 3.6. Find the mean.
Solution:
The weights of 10 newborn babies (in kg): 3.4, 3 .6, 4.2, 4.5, 3.9 , 4.1, 3.8, 4.5, 4.4, 3.6
Sum of weights = 3.4+3.6+4.2+4.5+3.9+4.1+3.8+4.5+4.4+3.6 = 40
Total number of babies = 10
No, Mean = (Sum of weights) / (Total number of babies)
= 40/10
= 4
Mean weight = 4 kg
Question 9: The percentage marks obtained by students of a class in mathematics are :
64, 36, 47, 23, 0, 19, 81, 93, 72, 35, 3, 1. Find their mean.
Solution:
The percentage marks obtained by students: 64, 36, 47, 23, 0, 19, 81, 93, 72, 35, 3, 1
Sum of marks = 64+36+47+23+0+19+81+93+72+35+3+1 = 474
Total students = 12
Now, Mean marks = (Sum of marks ) / (Total students )
=474/12
= 39.5
Mean Marks = 39.5
Question 10: The numbers of children in 10 families of a locality are:
2, 4, 3, 4, 2, 3, 5, 1, 1, 5. Find the number of children per family.
Solution:
The numbers of children in 10 families: 2, 4, 3, 4, 2, 3, 5, 1, 1, 5
Total number of children = 2+4+3+4+2+3+5+1+1+5 = 30
Total Families = 10
Number of children per family = Mean = (Total number of children) / (Total Families) = 30/10
= 3
Therefore, the tumber of children per family is 3.
RD Sharma Solutions for Class 9 Maths Chapter 24 Measures of Central Tendency Exercise 24.1
RD Sharma Solutions Class 9 Maths Chapter 24 Measures of Central Tendency Exercise 24.1 are based on the following topics:
- The measure of central tendency introduction
- The arithmetic mean of individual observations or ungrouped data
- Properties of arithmetic mean
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