RD Sharma Solutions Class 9 Measures Of Central Tendency Exercise 24.2

RD Sharma Class 9 Solutions Chapter 24 Ex 24.2 Free Download

Class 9 Chapter 24 – Measure of Central Tendency Exercise 24.2 solutions are provided here. RD Sharma solutions for class 9 – Measures of Central Tendency is the best tool to prepare for your exams. This will help to guide you through the questions you have trouble while trying to solve RD Sharma for class 9. These solutions for class 9 textbook are outlined and solved by the experts at BYJU’S.

Download PDF of RD Sharma Solutions for Class 9 Maths Chapter 24 Measure of Central Tendency Exercise 24.2

 

rd sharma solution class 9 maths chapter 24
rd sharma solution class 9 maths chapter 24
rd sharma solution class 9 maths chapter 24
rd sharma solution class 9 maths chapter 24
rd sharma solution class 9 maths chapter 24
rd sharma solution class 9 maths chapter 24
rd sharma solution class 9 maths chapter 24

 

Access Answers to Maths RD Sharma Class 9 Chapter 24 Measure of Central Tendency Exercise 24.2 Page number 24.14

Question 1: Calculate the mean for the following distribution:

RD sharma class 9 maths chapter 24 ex 24.2 question 1

Solution:

RD sharma class 9 maths chapter 24 ex 24.2 question 1 soln

Formula to calculate mean:

Mean formula

= 281/40

= 7.025

⇒ Mean for the given distribution is 7.025.

Question 2: Find the mean of the following data:

RD sharma class 9 maths chapter 24 ex 24.2 question 2

Solution:

RD sharma class 9 maths chapter 24 ex 24.2 question 2 soln

Formula to calculate mean:

RD sharma class 9 maths chapter 24 ex 24.2 question 2 solution

= 2650/106

= 25

⇒ Mean for the given data is 25.

Question 3: The mean of the following data is 20.6 .Find the value of p.

RD sharma class 9 maths chapter 24 ex 24.2 question 3

Solution:

RD sharma class 9 maths chapter 24 ex 24.2 question 3 solution

Formula to calculate mean:

RD sharma class 9 maths chapter 24 ex 24.2 question 3 soln

= (25p + 530)/50

Mean = 20.6 (Given)

So,

20.6 = (25p + 530)/50

25p + 530 = 1030

25p = 1030 − 530 = 500

or p = 20

⇒ The value of p is 20.

Question 4: If the mean of the following data is 15, find p.

RD sharma class 9 maths chapter 24 ex 24.2 question 4

Solution:

RD sharma class 9 maths chapter 24 ex 24.2 question 4 solution

Formula to calculate mean:

RD sharma class 9 maths chapter 24 ex 24.2 question 4 soln

= (10p + 445)/(p + 27)

Mean = 15 (Given)

So, (10p + 445)/(p + 27) = 15

10p + 445 = 15(p + 27)

10p – 15p = 405 – 445 = -40

-5p = -40

or p = 8

⇒ The value of p is 8.

Question 5: Find the value of p for the following distribution whose mean is 16.6.

RD sharma class 9 maths chapter 24 ex 24.2 question 5

Solution:

RD sharma class 9 maths chapter 24 ex 24.2 question 5 solution

Formula to calculate mean:

RD sharma class 9 maths chapter 24 ex 24.2 question 5 soln

= (24p + 1228)/100

Mean = 16.6 (given)

So, (24p + 1228)/100 = 16.6

24p + 1228 = 1660

24p = 1660 – 1228 = 432

p = 432/24 = 18

⇒ The value of p is 18.

Question 6: Find the missing value of p for the following distribution whose mean is 12.58.

RD sharma class 9 maths chapter 24 ex 24.2 question 6

Solution:

RD sharma class 9 maths chapter 24 ex 24.2 question 6 solution

Formula to calculate mean:

RD sharma class 9 maths chapter 24 ex 24.2 question 6 soln

= (7p + 524)/50

Mean = 12.58 (given)

So, (7p + 524)/50 = 12.58

7p + 524 = 12.58 x 50

7p + 524 = 629

7p = 629 – 524 = 105

p = 105/7 = 15

⇒ The value of p is 15.

Question 7: Find the missing frequency (p) for the following distribution whose mean is 7.68.

RD sharma class 9 maths chapter 24 ex 24.2 question 7

Solution:

RD sharma class 9 maths chapter 24 ex 24.2 question 7 solution

Formula to calculate mean:

RD sharma class 9 maths chapter 24 ex 24.2 question 7 soln

= (9p + 303)/(p+41)

Mean = 7.68 (given)

So, (9p + 303)/(p+41) = 7.68

9p + 303 = 7.68 (p + 41)

9p + 303 = 7.68p + 314.88

9p − 7.68p = 314.88 − 303

1.32p = 11.88

or p = (11.881)/(1.32) = 9

⇒ The value of p is 9.


Access other exercise solutions of Class 9 Maths Chapter 24 Measure of Central Tendency

Exercise 24.1 Solutions

Exercise 24.3 Solutions

Exercise 24.4 Solutions

Exercise VSAQs Solutions

RD Sharma Solutions for Class 9 Maths Chapter 24 Exercise 24.2

Class 9 Maths Chapter 24 Measure of Central Tendency Exercise 24.2 is based on following topics:

  • Arithmetic mean of grouped data or discrete frequency distribution
  • Methods to solve Arithmetic mean – Direct Method, Short-cut Method, step deviation method

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