RD Sharma Solutions for Class 9 Chapter 24 Measure of Central Tendency Exercise 24.2 are provided here. RD Sharma Solutions for Class 9 – Measures of Central Tendency is the best study tool to prepare for the annual exams. This will help you to guide through the questions you have trouble with while solving the RD Sharma textbook questions for Class 9. These solutions are outlined and solved by the subject experts at BYJU’S. Download the solutions in PDFs for free from the links provided below.
RD Sharma Solutions for Class 9 Maths Chapter 24 Measure of Central Tendency Exercise 24.2
Access Answers to RD Sharma Solutions for Class 9 Maths Chapter 24 Measure of Central Tendency Exercise 24.2 Page Number 24.14
Question 1: Calculate the mean for the following distribution:
Solution:
Formula to calculate mean:
= 281/40
= 7.025
⇒ Mean for the given distribution is 7.025.
Question 2: Find the mean of the following data:
Solution:
Formula to calculate mean:
= 2650/106
= 25
⇒ Mean for the given data is 25.
Question 3: The mean of the following data is 20.6. Find the value of p.
Solution:
Formula to calculate mean:
= (25p + 530)/50
Mean = 20.6 (Given)
So,
20.6 = (25p + 530)/50
25p + 530 = 1030
25p = 1030 − 530 = 500
or p = 20
⇒ The value of p is 20.
Question 4: If the mean of the following data is 15, find p.
Solution:
Formula to calculate mean:
= (10p + 445)/(p + 27)
Mean = 15 (Given)
So, (10p + 445)/(p + 27) = 15
10p + 445 = 15(p + 27)
10p – 15p = 405 – 445 = -40
-5p = -40
or p = 8
⇒ The value of p is 8.
Question 5: Find the value of p for the following distribution whose mean is 16.6.
Solution:
Formula to calculate mean:
= (24p + 1228)/100
Mean = 16.6 (given)
So, (24p + 1228)/100 = 16.6
24p + 1228 = 1660
24p = 1660 – 1228 = 432
p = 432/24 = 18
⇒ The value of p is 18.
Question 6: Find the missing value of p for the following distribution whose mean is 12.58.
Solution:
Formula to calculate mean:
= (7p + 524)/50
Mean = 12.58 (given)
So, (7p + 524)/50 = 12.58
7p + 524 = 12.58 x 50
7p + 524 = 629
7p = 629 – 524 = 105
p = 105/7 = 15
⇒ The value of p is 15.
Question 7: Find the missing frequency (p) for the following distribution whose mean is 7.68.
Solution:
Formula to calculate mean:
= (9p + 303)/(p+41)
Mean = 7.68 (given)
So, (9p + 303)/(p+41) = 7.68
9p + 303 = 7.68 (p + 41)
9p + 303 = 7.68p + 314.88
9p − 7.68p = 314.88 − 303
1.32p = 11.88
or p = (11.881)/(1.32) = 9
⇒ The value of p is 9.
RD Sharma Solutions for Class 9 Maths Chapter 24 Measures of Central Tendency Exercise 24.2
RD Sharma Solutions Class 9 Maths Chapter 24 Measures of Central Tendency Exercise 24.2 are based on the following topics:
- The arithmetic mean of grouped data or discrete frequency distribution
- Methods to solve arithmetic mean – Direct method, short-cut method, step deviation method
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