RD Sharma Solutions for Class 6 Maths Exercise 1.7 PDF
RD Sharma Solutions are created by subject matter experts with explanations in simple language to make them easy for students to understand. They help students gain better knowledge about the method of solving problems and ace the exam. The students can use the PDF of solutions as a vital resource for revision purposes before the exam. Solving exercise-wise problems using the solutions prepared by experts help in scoring good marks in the exams. RD Sharma Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Exercise 1.7 are provided here.
RD Sharma Solutions for Class 6 Maths Chapter 1: Knowing Our Numbers Exercise 1.7
Access answers to Maths RD Sharma Solutions for Class 6 Chapter 1: Knowing Our Numbers Exercise 1.7
Exercise 1.7 page: 1.29
1. Estimate the following by rounding off each factor to the nearest hundreds:
(i) 730 + 998
(ii) 796 – 314
(iii) 875 – 384
Solution:
(i) It can be rounded off to the nearest hundreds as 700 + 1000 = 1, 700.
(ii) It can be rounded off to the nearest hundreds as 800 – 300 = 500.
(iii) It can be rounded off to the nearest hundreds as 900 – 400 = 500.
2. Estimate the following by rounding off each factor to the nearest thousands:
(i) 12, 094 + 2, 888
(ii) 28, 292 – 21, 496
Solution:
(i) It can be rounded off to the nearest thousands as 13,000 + 3,000 = 16,000.
(ii) It can be rounded off to the nearest thousands as 28,000 – 21,000 = 7,000.
3. Estimate the following by rounding off each number to its greatest place:
(i) 439 + 334 + 4, 317
(ii) 8, 325 – 491
(iii) 1, 08, 734 – 47, 599
(iv) 898 × 785
(v) 9 × 795
(vi) 87 × 317
Solution:
(i) It can be rounded off to its greatest place as 400 + 300 + 4, 000 = 4, 700.
(ii) It can be rounded off to its greatest place as 8, 000 – 500 = 7, 500.
(iii) It can be rounded off to its greatest place as 1, 00, 000 – 50, 000 = 50, 000.
(iv) It can be rounded off to its greatest place as 900 × 800 = 7, 20, 000.
(v) It can be rounded off to its greatest place as 10 × 800 = 8, 000.
(vi) It can be rounded off to its greatest place as 90 × 300 = 27, 000.
4. Find the estimated quotient for each of the following by rounding off each number to its greatest place:
(i) 878 ÷ 28
(ii) 745 ÷ 24
(iii) 4489 ÷ 394
Solution:
(i) It can be rounded off to its greatest place as 900 ÷ 30 = 30.
(ii) It can be rounded off to its greatest place as 700 ÷ 20 = 35.
(iii) It can be rounded off to its greatest place as 4000 ÷ 400 = 10.
RD Sharma Solutions Class 6 Maths Chapter 1 – Knowing Our Numbers Exercise 1.7
RD Sharma Solutions Class 6 Maths Chapter 1 Knowing Our Numbers Exercise 1.7 help estimation or rounding off the given numbers using sum, difference, product and quotient methods.
Key features of RD Sharma Solutions for Class 6 Maths Chapter 1: Knowing Our Numbers Exercise 1.7
- The solutions are created with the aim of bridging the gap between students and their conceptual understanding.
- The brief explanation of solutions provides a clear idea about the topics and methods which are used in solving problems.
- The students can self-evaluate their performance by solving problems using RD Sharma solutions.
- The solution PDFs created by faculty at BYJU’S help students perform better in the exam.
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